Ch 1Set Language
5-Mark Questions
Consider the following sets
$$A = {0, 3, 5, 8}$$ $$B = {2, 4, 6, 10}$$ $$C = {12, 14, 18, 20}$$ (a) State whether True or False (i) (18 \in C) → True (ii) (6 \notin A) → True (iii) (14 \notin C) → False (iv) (10 \in B) → True (v) (5 \in B) → False (vi) (0 \in B) → False (b) Fill in the blanks (i) (3 \in \boxed{A}) (ii) (14 \in \boxed{C}) (iii) (18 \boxed{\notin} B) (iv) (4 \boxed{\in} B)
Represent the following sets in set-builder form.
(i) $$B = {x : x \text{ is an Indian cricket player who scored a double century in ODI}}$$ (ii) $$C = \left{x : x=\frac{n}{n+1},\ n\in\mathbb{N}\right}$$ (iii) $$D = {x : x \text{ is a Tamil month in a year}}$$ (iv) $$E = {x : x \text{ is an odd whole number and } x<9}$$
2-Mark Questions
List the set of letters of the following words in roster form.
(i) INDIA $${I, N, D, A}$$ (ii) PARALLELOGRAM $${P, A, R, L, E, O, G, M}$$ (iii) MISSISSIPPI $${M, I, S, P}$$ (iv) CZECHOSLOVAKIA $${C, Z, E, H, O, S, L, V, A, K, I}$$
Represent the following sets in roster form.
(i) $$A = {2,4,6,8,10,12,14,16,18}$$ (ii) $$B = \left{\frac12,\frac22,\frac32,\frac42,\frac52\right}$$ or $$B = \left{\frac12,1,\frac32,2,\frac52\right}$$ (iii) Perfect cubes between 27 and 216 are: $$64,\ 125$$ Hence, $$C = {64,125}$$ (iv) $$D = {-4,-3,-2,-1,0,1,2}$$
Find the cardinal number of the following sets.
(i) $$M = {p,q,r,s,t,u}$$ $$n(M)=6$$ (ii) $$P = {x : x=3n+2,\ n\in W,\ x<15}$$ Values: $$2,5,8,11,14$$ $$n(P)=5$$ (iii) $$Q = \left{y : y=\frac{4}{3n},\ n\in\mathbb{N},\ 2<n\le5\right}$$ Values: $$\left{\frac49,\frac13,\frac4{15}\right}$$ $$n(Q)=3$$ (iv) $$R={x:x\in\mathbb{Z}, -5\le x<5}$$ Elements: $${-5,-4,-3,-2,-1,0,1,2,3,4}$$ $$n(R)=10$$ (v) Leap years between 1882 and 1906: $$1884,1888,1892,1896,1904$$ $$n(S)=5$$
1-Mark Questions (MCQ)
Which of the following are sets?
(i) The collection of prime numbers up to 100. ✓ Set (ii) The collection of rich people in India. ✕ Not a set (iii) The collection of all rivers in India. ✓ Set (iv) The collection of good Hockey players. ✕ Not a set
Ch 2Real Numbers
5-Mark Questions
Find any five rational numbers between
# (i) Between (\frac14) and (\frac15) Step 1: Take LCM denominator $$\frac14=\frac{25}{100}$$ $$\frac15=\frac{20}{100}$$ Now choose fractions between: $$\frac{20}{100} \quad \text{and} \quad \frac{25}{100}$$ Answer Five rational numbers are: $$\frac{21}{100}, \frac{22}{100}, \frac{23}{100}, \frac{24}{100}, \frac{241}{1000}$$ (Any valid five rational numbers are acceptable.) # (ii) Between (0.1) and (0.11) Step 1: Write with same decimal places $$0.1 = 0.100$$ $$0.11 = 0.110$$ Now choose numbers between them. …
Express the following rational numbers into decimal form and state the kind of decimal expansion
# (i) (\frac{2}{7}) Solution $$\frac{2}{7}=0.285714285714\ldots$$ The digits repeat continuously. Answer $$\frac{2}{7}=0.\overline{285714}$$ Type of decimal expansion: Non-terminating recurring decimal # (ii) (-5\frac{3}{11}) Step 1: Convert mixed fraction into improper fraction $$-5\frac{3}{11} ============== -\frac{58}{11}$$ Step 2: Convert into decimal $$\frac{58}{11}=5.272727\ldots$$ Therefore, $$-\frac{58}{11}=-5.272727\ldots$$ Answer $$-5\frac{3}{11}=-5.\overline{27}$$ Type of decimal expansion: Non-terminating recurring decimal # (iii) (\frac{22}{3}) Solution $$\frac{22}{3}=7.333333\ldo …
2-Mark Questions
Which arrow best shows the position of (\frac{11}{3}) on the number line?
First convert the rational number into mixed form. $$\frac{11}{3}=3\frac{2}{3}$$ So, the number lies: between (3) and (4) closer to (4) Therefore, the correct arrow is the one pointing at: $$3\frac{2}{3}$$ on the number line.
Find any three rational numbers between
$$-\frac{7}{11} \quad \text{and} \quad \frac{2}{11}$$ Solution We need rational numbers greater than $$-\frac{7}{11}$$ and less than $$\frac{2}{11}$$ Possible rational numbers are: $$-\frac{6}{11},; -\frac{5}{11},; -\frac{4}{11}$$ Answer Any three rational numbers are: $$-\frac{6}{11},; -\frac{5}{11},; -\frac{4}{11}$$
Express (\frac{1}{13}) in decimal form. Find the length of the period of decimals.
$$\frac{1}{13}=0.076923076923\ldots$$ The repeating block is: $$076923$$ This block contains 6 digits. Answer $$\frac{1}{13}=0.\overline{076923}$$ Length of the period: $$6$$
1-Mark Questions (MCQ)
Without actual division, find which of the following rational numbers have terminating decimal expansion
A rational number has a terminating decimal expansion if the denominator in simplest form contains only the prime factors: $$2 \text{ and/or } 5$$ # (i) (\frac{7}{128}) $$128=2^7$$ Only factor (2) is present. Answer $$\frac{7}{128}$$ has a terminating decimal expansion . # (ii) (\frac{21}{15}) Simplify: $$\frac{21}{15}=\frac75$$ Denominator: $$5$$ Only factor (5). Answer $$\frac{21}{15}$$ has a terminating decimal expansion . # (iii) (4\frac{9}{35}) Convert fractional part: $$\frac{9}{35}$$ Denominator: $$35=5\times7$$ Factor (7) is present. …
Ch 3Algebra
5-Mark Questions
Write the coefficient of (x^2) and (x)
# (i) $$4+\frac25x^2-3x$$ Coefficient of (x^2): $$\frac25$$ Coefficient of (x): $$-3$$ # (ii) $$6-2x^2+3x^3-\sqrt7x$$ Coefficient of (x^2): $$-2$$ Coefficient of (x): $$-\sqrt7$$ # (iii) $$\pi x^2-x+2$$ Coefficient of (x^2): $$\pi$$ Coefficient of (x): $$-1$$ # (iv) $$\sqrt3x^2+\sqrt2x+0.5$$ Coefficient of (x^2): $$\sqrt3$$ Coefficient of (x): $$\sqrt2$$ # (v) $$x^2-\frac72x+8$$ Coefficient of (x^2): $$1$$ Coefficient of (x): $$-\frac72$$
Find the zeros of the polynomial
# (i) $$p(x)=x-3$$ Solution Set: $$x-3=0$$ $$x=3$$ Zero $$3$$ # (ii) $$p(x)=2x+5$$ Solution $$2x+5=0$$ $$2x=-5$$ $$x=-\frac52$$ Zero $$-\frac52$$ # (iii) $$q(y)=2y-3$$ Solution $$2y-3=0$$ $$2y=3$$ $$y=\frac32$$ Zero $$\frac32$$ # (iv) $$f(z)=8z$$ Solution $$8z=0$$ $$z=0$$ Zero $$0$$ # (v) $$p(x)=ax,\quad a\ne0$$ Solution $$ax=0$$ Since (a\ne0), $$x=0$$ Zero $$0$$ # (vi) $$h(x)=ax+b$$ where $$a\ne0$$ Solution $$ax+b=0$$ $$ax=-b$$ $$x=-\frac ba$$ Zero $$-\frac ba$$
2-Mark Questions
Find the degree of the following polynomials
# (i) $$1-\sqrt2y^2+y^7$$ Highest exponent: $$7$$ Degree $$7$$ # (ii) $$\frac{x^3-x^4+6x^6}{x^2}$$ Simplify $$=x-x^2+6x^4$$ Highest exponent: $$4$$ Degree $$4$$ # (iii) $$x^3(x^2+x)$$ Simplify $$=x^5+x^4$$ Highest exponent: $$5$$ Degree $$5$$ # (iv) $$3x^4+9x^2+27x^6$$ Highest exponent: $$6$$ Degree $$6$$ # (v) $$2\sqrt5p^4-\frac{8p^3}{\sqrt3}+\frac{2p^2}{7}$$ Highest exponent: $$4$$ Degree $$4$$
Rewrite in standard form
# (i) $$x-9+\sqrt7x^3+6x^2$$ Standard form $$\sqrt7x^3+6x^2+x-9$$ # (ii) $$\sqrt2x^2-\frac72x^4+x-5x^3$$ Standard form $$-\frac72x^4-5x^3+\sqrt2x^2+x$$ # (iii) $$7x^3-\frac65x^2+4x-1$$ Already in standard form. # (iv) $$y^2+\sqrt5y^3-11-\frac73y+9y^4$$ Standard form $$9y^4+\sqrt5y^3+y^2-\frac73y-11$$
Add the following polynomials and find the degree
# (i) $$p(x)=6x^2-7x+2$$ $$q(x)=6x^3-7x+15$$ Addition $$=6x^3+6x^2-14x+17$$ Highest exponent: $$3$$ Degree $$3$$ # (ii) $$h(x)=7x^3-6x+1$$ $$f(x)=7x^2+17x-9$$ Addition $$=7x^3+7x^2+11x-8$$ Degree $$3$$ # (iii) $$f(x)=16x^4-5x^2+9$$ $$g(x)=-6x^3+7x-15$$ Addition $$16x^4-6x^3-5x^2+7x-6$$ Degree $$4$$
1-Mark Questions (MCQ)
Which of the following expressions are polynomials? If not, give reason.
# (i) $$\frac1{x^2}+3x-4$$ Solution $$\frac1{x^2}=x^{-2}$$ The exponent is negative. Hence, it is not a polynomial . # (ii) $$x^2(x-1)$$ Solution $$=x^3-x^2$$ All exponents are non-negative integers. Hence, it is a polynomial. # (iii) $$\frac1x(x+5)$$ Solution $$=\frac{x+5}{x} =1+\frac5x$$ Contains negative exponent. Hence, it is not a polynomial . # (iv) $$\frac1{x-2}+\frac1{x-1}+7$$ Solution Variable occurs in denominator. Hence, it is not a polynomial . # (v) $$\sqrt5x^2+\sqrt3x+\sqrt2$$ Solution All exponents are non-negative integers. Irrational coefficients are allowed. …
Ch 4Geometry
5-Mark Questions
Is the figure ∠A supplementary to ∠B? Give reasons.
Yes. (i) 70° and 110° are supplementary. (ii) 50° and 130° are supplementary. (iii) 40° and 140° are supplementary.
Verify whether the given triangles are congruent
(i) SSS. (ii) SAS. (iii) RHS. (iv) ASA. (v) SSS. (vi) SAS.
2-Mark Questions
The angles of a triangle are in the ratio 1 : 2 : 3. Find the measures of each angle.
Let angles be x, 2x, 3x. Sum = x + 2x + 3x = 6x = 180° ⇒ x = 30°. Thus angles are 30°, 60°, 90°.
ΔABC and ΔDEF are two triangles
ΔABC ≅ ΔDEF (by ASA).
The angles of a quadrilateral are in the ratio 2 : 4 : 5 : 7. Find all the angles.
40°, 80°, 100°, 140°.
1-Mark Questions (MCQ)
In quadrilateral ABCD, AB = BC and AD = DC. The diagram gives ∠ABC = 108° and ∠ADC = 42°. Find ∠BCD.
(3) 105°.
Ch 5Coordinate Geometry
5-Mark Questions
Plot the following points and identify the quadrants
Given points: \(P(-7,6)\) \(Q(7,-2)\) \(R(-6,-7)\) \(S(3,5)\) \(T(3,9)\) Rules for Quadrants First Quadrant: \[ (+,+) \] Second Quadrant: \[ (-,+) \] Third Quadrant: \[ (-,-) \] Fourth Quadrant: \[ (+,-) \] Identifying Quadrants Point \(P(-7,6)\) x-coordinate negative y-coordinate positive ✓ Lies in: \[ \boxed{\text{Second Quadrant}} \] Point \(Q(7,-2)\) x-coordinate positive y-coordinate negative ✓ Lies in: \[ \boxed{\text{Fourth Quadrant}} \] Point \(R(-6,-7)\) x-coordinate negative y-coordinate negative ✓ Lies in: \[ \boxed{\text{Third Quadrant}} \] Point \(S(3,5)\) x-coordinate positive y- …
Plot the following points and join them. State your conclusion.
(i) Points: \[ (-5,3),\ (-1,3),\ (0,3),\ (5,3) \] Observation: All points have same y-coordinate: \[ y = 3 \] Therefore all points lie on a horizontal line parallel to x-axis. ✓ Conclusion: \[ \boxed{\text{All points are collinear and lie on a horizontal line}} \] (ii) Points: \[ (0,-4),\ (0,-2),\ (0,4),\ (0,5) \] Observation: All points have same x-coordinate: \[ x = 0 \] Therefore all points lie on the y-axis. ✓ Conclusion: \[ \boxed{\text{All points are collinear and lie on the y-axis}} \]
2-Mark Questions
Write the abscissa and ordinate from Fig. 5.11
Definitions Abscissa = x-coordinate Ordinate = y-coordinate ✓ From the graph: Read horizontal value → Abscissa Read vertical value → Ordinate > Exact values require Fig. 5.11. <div
Show that points form a parallelogram
(i) A(–3,1), B(–6,–7), C(3,–9), D(6,–1) Using distance formula: \[ AB=CD \] \[ BC=AD \] Opposite sides are equal. ✓ Hence ABCD is a parallelogram. (ii) A(–7,–3), B(5,10), C(15,8), D(3,–5) Similarly: \[ AB=CD \] \[ BC=AD \] ✓ Hence ABCD is a parallelogram.
Verify that points form a rhombus
(i) A(3,–2), B(7,6), C(–1,2), D(–5,–6) All four sides are equal. ✓ Hence rhombus. (ii) A(1,1), B(2,1), C(2,2), D(1,2) All sides equal to 1 unit. ✓ Hence rhombus. (Note: This is also a square.)
1-Mark Questions (MCQ)
Which of the following points lie in the fourth quadrant? Q(3,−4) and R(1,−1).
Fourth quadrant points have coordinates (+, −). Both Q(3,−4) and R(1,−1) have positive x and negative y, so both lie in the fourth quadrant. Answer: Q and R.
Ch 6Trigonometry
5-Mark Questions
Verify the following equalities
(i) 1 (ii) 4/3 (iii) 0 (iv) 1
Find the value of the following
(i) 5/4 (ii) 7/4 (iii) 3
2-Mark Questions
Verify cos 3A = 4 cos^3 A - 3 cos A for A = 30°
Verified (both sides = 0)
Find the value of 8 sin 2x cos 4x sin 6x when x = 15°
2x = 30°, 4x = 60°, 6x = 90°. So expression = 8 sin30° cos60° sin90° = 8(1/2)(1/2)(1) = 8·1/4 = 2.
Find the value of the following (use tables)
(i) 0.7547 (ii) 0.2647 (iii) 1.4010 (iv) 0.3642 (v) 0.8300 (vi) 2.7948
1-Mark Questions (MCQ)
Find the value of 3 sin 70° sec 20° + 2 sin 49° sec 51°.
As printed: approximately 5.39849, so none of the options is correct. If sin 49° is the textbook typo and sin 39° was intended, the answer is (3) 5.
Ch 7Mensuration
5-Mark Questions
Using Heron’s formula, find the area
(i) Sides = 10 cm, 24 cm, 26 cm Semi-perimeter: \[ s=\frac{10+24+26}{2} \] \[ =\frac{60}{2} \] \[ =30 \] Area: \[ A = \sqrt{30(30-10)(30-24)(30-26)} \] \[ = \sqrt{30\times20\times6\times4} \] \[ = \sqrt{14400} \] \[ =120 \] ✓ Area: \[ \boxed{120\text{ cm}^2} \] (ii) Sides = 1.8 m, 8 m, 8.2 m Semi-perimeter: \[ s = \frac{1.8+8+8.2}{2} \] \[ =\frac{18}{2} \] \[ =9 \] Area: \[ A = \sqrt{9(9-1.8)(9-8)(9-8.2)} \] \[ = \sqrt{9\times7.2\times1\times0.8} \] \[ = \sqrt{51.84} \] \[ =7.2 \] ✓ Area: \[ \boxed{7.2\text{ m}^2} \]
Triangular ground with sides
\[ 22\text{ m},\ 120\text{ m},\ 122\text{ m} \] Find area and levelling cost at ₹20/m². Semi-perimeter: \[ s = \frac{22+120+122}{2} \] \[ =\frac{264}{2} \] \[ =132 \] Area: \[ A = \sqrt{132(132-22)(132-120)(132-122)} \] \[ = \sqrt{132\times110\times12\times10} \] \[ = \sqrt{1742400} \] \[ =1320 \] ✓ Area: \[ \boxed{1320\text{ m}^2} \] Cost of levelling \[ \text{Cost} = 1320\times20 \] \[ =26400 \] ✓ Cost: \[ \boxed{₹26,400} \]
2-Mark Questions
Find area of equilateral triangle whose perimeter is 180 cm
Side: \[ a=\frac{180}{3}=60\text{ cm} \] Area formula: :contentReference[oaicite:1]{index=1} \[ A = \frac{\sqrt3}{4}(60)^2 \] \[ = \frac{\sqrt3}{4}\times3600 \] \[ =900\sqrt3 \] ✓ Area: \[ \boxed{900\sqrt3\text{ cm}^2} \]
Find the area of unshaded region
Use: Area of larger figure Subtract shaded area ✓ Exact numerical answer requires the figure dimensions.
A parallelogram has adjacent sides 34 m and 20 m and a diagonal of length 42 m. Find the area of the parallelogram.
The diagonal divides the parallelogram into two congruent triangles with sides 34 m, 20 m and 42 m. Semi-perimeter s = (34 + 20 + 42)/2 = 48 Area of one triangle = √[48(48−34)(48−20)(48−42)] = √[48·14·28·6] = 336 m² Parallelogram area = 2 × 336 = 672 m² Answer: 672 m²
Ch 8Statistics
5-Mark Questions
Mean score of students
| Marks | Number of Students | |---|---| | 75 | 10 | | 60 | 12 | | 40 | 8 | | 30 | 3 | Calculate \(fx\) | x | f | fx | |---|---|---| | 75 | 10 | 750 | | 60 | 12 | 720 | | 40 | 8 | 320 | | 30 | 3 | 90 | Totals \[ \sum f = 10+12+8+3 = 33 \] \[ \sum fx = 750+720+320+90 = 1880 \] Mean: \[ \bar{x} = \frac{1880}{33} \] \[ \approx56.97 \] ✓ Mean score: \[ \boxed{56.97} \]
If mean of the data is 20.2, find \(p\)
| Marks | 10 | 15 | 20 | 25 | 30 | |---|---|---|---|---|---| | No. of students | 6 | \(p\) | 8 | 10 | 6 | Using: \[ \bar{x} = \frac{\sum fx}{\sum f} \] Given mean: \[ 20.2 \] Calculate \(\sum f\) \[ 6+p+8+10+6 \] \[ =30+p \] Calculate \(\sum fx\) \[ 10(6)+15(p)+20(8)+25(10)+30(6) \] \[ =60+15p+160+250+180 \] \[ =650+15p \] Apply mean formula \[ 20.2 = \frac{650+15p}{30+p} \] Cross multiply: \[ 20.2(30+p)=650+15p \] \[ 606+20.2p=650+15p \] \[ 20.2p-15p=44 \] \[ 5.2p=44 \] \[ p=\frac{44}{5.2} \] \[ p\approx8.46 \] Since frequency must be a whole number and textbook solution uses exact fractional …
2-Mark Questions
Mean temperature of the week
Temperatures: \[ 26^\circ C,\ 24^\circ C,\ 28^\circ C,\ 31^\circ C,\ 30^\circ C,\ 26^\circ C,\ 24^\circ C \] Sum of temperatures \[ 26+24+28+31+30+26+24 \] \[ =189 \] Number of days: \[ 7 \] Mean: \[ \bar{x} = \frac{189}{7} \] \[ =27 \] ✓ Mean temperature: \[ \boxed{27^\circ C} \]
Mean weight of 4 family members is 60 kg
Three weights: \[ 56\text{ kg},\ 68\text{ kg},\ 72\text{ kg} \] Find fourth weight. Total weight of family \[ 4\times60 = 240 \] Sum of known weights \[ 56+68+72 = 196 \] Fourth weight: \[ 240-196 = 44 \] ✓ Weight of fourth member: \[ \boxed{44\text{ kg}} \]
Mean tumor volume of mice
Tumor volumes (mm³): \[ 145,\ 158,\ 142,\ 141,\ 139,\ 140 \] Using arithmetic mean: :contentReference[oaicite:0]{index=0} Sum of observations \[ 145+158+142+141+139+140 \] \[ =865 \] Number of mice: \[ 6 \] Mean: \[ \bar{x} = \frac{865}{6} \] \[ =144.17 \] ✓ Mean tumor volume: \[ \boxed{144.17\text{ mm}^3} \]
Ch 9Probability
5-Mark Questions
Frame two probability problems using the spinner
Assume spinner sectors labeled 1–8 (equal). Problem 1: Find P(spinner lands on an even number). Even = {2,4,6,8} → 4/8 = 1/2. Problem 2: Find P(spinner lands on a prime number). Primes ≤8: {2,3,5,7} → 4/8 = 1/2.
Among 1500 surveyed families, 860 have only part-time maids, 370 have only full-time maids, and 250 have both. Find the probability that a randomly selected family has (i) both types of maids, (ii) part-time maids, and (iii) no maids.
(i) 1/6, (ii) 43/75, (iii) 1/75.
2-Mark Questions
Probability that a stranger’s next birthday falls on a Sunday
There are 7 equally likely days; only Sunday is favourable. P = 1/7.
Probability of drawing a King or Queen or Jack from a deck of cards
Favourable cards = 4 Kings + 4 Queens + 4 Jacks = 12. Total = 52. P = 12/52 = 3/13.
Probability of throwing an even number on a die
Even faces = {2,4,6} (3 outcomes). Total outcomes = 6. P = 3/6 = 1/2.
Frequently asked questions
- Consider the following sets
- $$A = {0, 3, 5, 8}$$ $$B = {2, 4, 6, 10}$$ $$C = {12, 14, 18, 20}$$ (a) State whether True or False (i) (18 \in C) → True (ii) (6 \notin A) → True (iii) (14 \notin C) → False (iv) (10 \in B) → True (v) (5 \in B) → False (vi) (0 \in B) → False (b) Fill in the blanks (i) (3 \in \boxed{A}) (ii) (14 \in \boxed{C}) (iii) (18 \boxed{\notin} B) (iv) (4 \boxed{\in} B)
- Represent the following sets in set-builder form.
- (i) $$B = {x : x \text{ is an Indian cricket player who scored a double century in ODI}}$$ (ii) $$C = \left{x : x=\frac{n}{n+1},\ n\in\mathbb{N}\right}$$ (iii) $$D = {x : x \text{ is a Tamil month in a year}}$$ (iv) $$E = {x : x \text{ is an odd whole number and } x<9}$$
- List the set of letters of the following words in roster form.
- (i) INDIA $${I, N, D, A}$$ (ii) PARALLELOGRAM $${P, A, R, L, E, O, G, M}$$ (iii) MISSISSIPPI $${M, I, S, P}$$ (iv) CZECHOSLOVAKIA $${C, Z, E, H, O, S, L, V, A, K, I}$$
- Represent the following sets in roster form.
- (i) $$A = {2,4,6,8,10,12,14,16,18}$$ (ii) $$B = \left{\frac12,\frac22,\frac32,\frac42,\frac52\right}$$ or $$B = \left{\frac12,1,\frac32,2,\frac52\right}$$ (iii) Perfect cubes between 27 and 216 are: $$64,\ 125$$ Hence, $$C = {64,125}$$ (iv) $$D = {-4,-3,-2,-1,0,1,2}$$
These important questions are selected from the Samacheer Kalvi Class 9 Maths textbook book-back exercises to help you revise the most useful questions. Mark weightage (5/2/1) follows the usual exam pattern and may vary by exam — always check your latest syllabus and question pattern. Open each chapter for the complete set of questions and answers.