Samacheer Class 6 Maths Bill, Profit and Loss Book Back Answers & Solutions

Q.2Prepare a bill for the following books of biographies purchased from Maruthu Book Store, Chidambaram on 12.04.2018 bearing the bill number 507. 10 copies of Subramanya Bharathiar @ Rs 55 each, 15 copies of Thiruvalluvar @ Rs 75 each, 12 copies of Veeramamunivar @ Rs 60 each, and 12 copies of ThiruviKa @ Rs 70 each.v

Solution

Samacheer Kalvi 6th Maths Guide Term 2 Chapter 3 Bill, Profit and Loss Ex 3.1 2

Answer:

Samacheer Kalvi 6th Maths Guide Term 2 Chapter 3 Bill, Profit and Loss Ex 3.1 2

Q.5Rani bought a set of bangles for ₹ 310. Her neighbour liked it the most. So Rani sold it to her for ₹ 325. Find the profit or loss to Rani.v

Solution

CP = Rs 310
SP = Rs 325
Profit = SP – CP = Rs 325 – Rs 310 = Rs 15

Answer:

CP = Rs 310
SP = Rs 325
Profit = SP – CP = Rs 325 – Rs 310 = Rs 15

Q.6Sugan bought a pair of jeans pant for Rs 750 not fit him. He sold it to his friend for Rs 710, Find the profit or loss to sugan.v

Solution

CP = Rs 750
SP = Rs 710
CP > SP
Loss = CP – SP
= Rs 750 – Rs 710
= Rs 40

Answer:

CP = Rs 750
SP = Rs 710
CP > SP
Loss = CP – SP
= Rs 750 – Rs 710
= Rs 40

Q.8Muthu has a car worth Rs 8,50,000 and he wants to sell it at a profit of Rs 25,000. What should be the selling price of the car?v

Solution

CP = Rs 8,50,000
Profit = Rs 25,000
SP = CP + Profit
= Rs 8,50,000 + Rs 25,000
= Rs 8,75,000

Answer:

CP = Rs 8,50,000
Profit = Rs 25,000
SP = CP + Profit
= Rs 8,50,000 + Rs 25,000
= Rs 8,75,000

Q.9Valarmathi sold her pearl set for ₹ 30,000 at a profit of ₹ 5000. Find the cost price of the pearl set.v

Solution

SP = Rs 30,000
Profit = Rs 5,000
CP = SP – Profit
= Rs 30,000 – Rs 5,000
= Rs 25,000

Answer:

SP = Rs 30,000
Profit = Rs 5,000
CP = SP – Profit
= Rs 30,000 – Rs 5,000
= Rs 25,000

Q.10If Guna marks his product to be sold for Rs 325 and gives a discount of Rs 30, then find the S.P.v

Solution

MP = Rs 325
Discount = Rs 30
SP = MP – Discount
= Rs 325 – Rs 30
= Rs 295
Samacheer Kalvi 6th Maths Guide Term 2 Chapter 3 Bill, Profit and Loss Ex 3.1

Answer:

MP = Rs 325
Discount = Rs 30
SP = MP – Discount
= Rs 325 – Rs 30
= Rs 295
Samacheer Kalvi 6th Maths Guide Term 2 Chapter 3 Bill, Profit and Loss Ex 3.1

Q.11A man buys a chair for ₹ 1500. He wants to sell it at a profit of ₹ 250 after making a discount of ₹ 100. What is the M.P of the chair?v

Solution

CP = Rs 1,500
Profit = Rs 250
SP = CP + Profit
= Rs 1,500 + Rs 250
= Rs 1,750
Discount = Rs 100
SP = MP – Discount
MP = SP + Discount
= Rs 1,750 + Rs 100
= Rs 1,850

Answer:

CP = Rs 1,500
Profit = Rs 250
SP = CP + Profit
= Rs 1,500 + Rs 250
= Rs 1,750
Discount = Rs 100
SP = MP – Discount
MP = SP + Discount
= Rs 1,750 + Rs 100
= Rs 1,850

Q.12Amutha marked her home product of pickle as Rs 300 per pack. But she sold it for only Rs 275 per pack. What was the discount offered by her per pack?v

Solution

MP = Rs 300
SP = Rs 275
Discount = MP – SP
= Rs 300 – Rs 275
= Rs 25

Answer:

MP = Rs 300
SP = Rs 275
Discount = MP – SP
= Rs 300 – Rs 275
= Rs 25

Q.13Valavan bought 24 eggs for ₹ 96. Four of them were broken and also he had a loss of ₹ 36 on selling them. What is the selling price of one egg?v

Solution

Cost of 24 eggs = Rs 96
Since 4 of the eggs were broken, the number of remaining eggs = 24 – 4 = 20
Since the loss is Rs 36
The selling price of 20 eggs
SP = CP – Loss
= Rs 96 – Rs 36
= Rs 60
∴ Cost of 1 egg = Rs 60 / 20 = Rs. 3
Samacheer Kalvi 6th Maths Guide Term 2 Chapter 3 Bill, Profit and Loss Ex 3.1

Answer:

Cost of 24 eggs = Rs 96
Since 4 of the eggs were broken, the number of remaining eggs = 24 – 4 = 20
Since the loss is Rs 36
The selling price of 20 eggs
SP = CP – Loss
= Rs 96 – Rs 36
= Rs 60
∴ Cost of 1 egg = Rs 60 / 20 = Rs. 3
Samacheer Kalvi 6th Maths Guide Term 2 Chapter 3 Bill, Profit and Loss Ex 3.1

Q.14Mangai bought a cell phone for Rs 12,585. It fell down. She spent Rs 500 on its repair. She sold it for Rs 7,500. Find her profit or loss.v

Solution

CP = Rs 12,585 + Rs 500
= Rs 13,085
SP = Rs 7,500
CP > SP
Loss = CP – SP
= Rs 13,085 – Rs 7,500
= Rs 5,585
Objective Type Questions

Answer:

CP = Rs 12,585 + Rs 500
= Rs 13,085
SP = Rs 7,500
CP > SP
Loss = CP – SP
= Rs 13,085 – Rs 7,500
= Rs 5,585
Objective Type Questions

Q.15Discount is subtracted from ______ to get S.P.v

A. M.P
B. C.P
C. Loss
D. Profit

Solution

(a) M.P
Samacheer Kalvi 6th Maths Guide Term 2 Chapter 3 Bill, Profit and Loss Ex 3.1

Answer:

(a) M.P
Samacheer Kalvi 6th Maths Guide Term 2 Chapter 3 Bill, Profit and Loss Ex 3.1

Q.16Overhead expenses are always included in ………v

A. S.P
B. C.P
C. Profit
D. Loss

Solution

(b) C.P

Answer:

(b) C.P

Q.17There is no profit or loss when ______.v

A. C.P = S.P.
B. C.P. > S.P
C. C.P. < S.P
D. M.P = Discount

Solution

(a) cost price = selling price
Samacheer Kalvi 6th Maths Guide Term 2 Chapter 3 Bill, Profit and Loss Ex 3.1

Answer:

(a) cost price = selling price
Samacheer Kalvi 6th Maths Guide Term 2 Chapter 3 Bill, Profit and Loss Ex 3.1

Q.18Discount = M.P.v

A. Profit
B. S.P
C. Loss
D. C.P

Solution

(b) S.P
Posted in Class 6 on January 23, 2025 January 24, 2025
Leave a Reply Cancel reply
You must be logged in to post a comment.
Facebook
Twitter
Instagram
Pinterest
Copyright © 2026 Samacheer Kalvi

Answer:

(b) S.P
Posted in Class 6 on January 23, 2025 January 24, 2025
Leave a Reply Cancel reply
You must be logged in to post a comment.
Facebook
Twitter
Instagram
Pinterest
Copyright © 2026 Samacheer Kalvi

Q.1A Shopkeeper buys three articles for Rs 325, Rs 450, and Rs 510. He is able to sell them for Rs 350, Rs 425, and Rs 525 respectively. Find the gain or loss to the shopkeeper on the whole.v

Solution

C.P of three articles = 325 + 450 + 510 = ₹ 1285
S.P of three articles = 350 + 425 + 525 = ₹ 1,300
Here S.P > C.P
Profit = S.P – C.P = 1,300 – 1285 = ₹ 15
The shopkeeper gained = ₹ 15
Samacheer Kalvi 6th Maths Guide Term 2 Chapter 3 Bill, Profit and Loss Ex 3.2

Answer:

C.P of three articles = 325 + 450 + 510 = ₹ 1285
S.P of three articles = 350 + 425 + 525 = ₹ 1,300
Here S.P > C.P
Profit = S.P – C.P = 1,300 – 1285 = ₹ 15
The shopkeeper gained = ₹ 15
Samacheer Kalvi 6th Maths Guide Term 2 Chapter 3 Bill, Profit and Loss Ex 3.2

Q.2A stationery shop owner bought a scientific calculator for ₹ 750. He had put a battery worth ₹ 100 in it. He had spent ₹ 50 for its outer pouch. He was able to sell it at ₹ 850. Find his profit or loss.v

Solution

Cost of the scientific calculator = ₹ 750
Cost of its battery = ₹ 100
Cost of outer pouch = ₹ 50
Cost Price of the calculator = ₹ 750 + ₹ 100 + ₹ 50 = ₹ 900
S.P = ₹ 850
Here S.P > C.P
Loss = C.P – S.P = 900 – 850 = ₹ 50
Loss = ₹ 50

Answer:

Cost of the scientific calculator = ₹ 750
Cost of its battery = ₹ 100
Cost of outer pouch = ₹ 50
Cost Price of the calculator = ₹ 750 + ₹ 100 + ₹ 50 = ₹ 900
S.P = ₹ 850
Here S.P > C.P
Loss = C.P – S.P = 900 – 850 = ₹ 50
Loss = ₹ 50

Q.3Nathan paid Rs 800 and bought 10 bottles of honey from a village vendor. He sold them in a gain for Rs 100 per bottle. Find his profit or loss.v

Solution

C.P of 10 bottles of honey = ₹ 800
C.P of 1 bottle honey = 800/10 = ₹ 80
S.P of a bottle honey = ₹ 100
Here S.P > C.P
Profit per bottle = ₹ 100 – ₹ 80 = ₹ 20
Profit for 10 bottles = 20 × 10 = ₹ 200
Profit = ₹ 200
Samacheer Kalvi 6th Maths Guide Term 2 Chapter 3 Bill, Profit and Loss Ex 3.2

Answer:

C.P of 10 bottles of honey = ₹ 800
C.P of 1 bottle honey = 800/10 = ₹ 80
S.P of a bottle honey = ₹ 100
Here S.P > C.P
Profit per bottle = ₹ 100 – ₹ 80 = ₹ 20
Profit for 10 bottles = 20 × 10 = ₹ 200
Profit = ₹ 200
Samacheer Kalvi 6th Maths Guide Term 2 Chapter 3 Bill, Profit and Loss Ex 3.2

Q.4A man bought 400 metres of cloth for ₹ 60,000 and sold it at the rate of ₹ 400 per metre. Find his profit or loss.v

Solution

C.P of 400 metres of cloth = ₹ 60,000
S.P per metre = ₹ 400
S.P of 400 metres of cloth = 400 × 400 = ₹ 1,60,000
Here S.P > C.P
Profit = C.P – S.P = 1,60,000 – 60,000 = ₹ 1,00,000
Challenge Problems

Answer:

C.P of 400 metres of cloth = ₹ 60,000
S.P per metre = ₹ 400
S.P of 400 metres of cloth = 400 × 400 = ₹ 1,60,000
Here S.P > C.P
Profit = C.P – S.P = 1,60,000 – 60,000 = ₹ 1,00,000
Challenge Problems

Q.5A fruit seller bought 2 dozen bananas at Rs 20 a dozen and sold them at Rs 3 per banana. Find his gain or loss.v

Solution

Cost of one dozen banana = ₹ 20
Cost of 2 dozen bananas = ₹ 20 × 2 = ₹ 40
C.P = ₹ 40
S.P per banana = ₹ 3
S.P for 2 dozen banana = ₹ 3 × 24 = ₹ 72
Here S.P > C.P
Profit = S.P – C.P = 72 – 40 = 32
Profit = ₹ 32
Samacheer Kalvi 6th Maths Guide Term 2 Chapter 3 Bill, Profit and Loss Ex 3.2

Answer:

Cost of one dozen banana = ₹ 20
Cost of 2 dozen bananas = ₹ 20 × 2 = ₹ 40
C.P = ₹ 40
S.P per banana = ₹ 3
S.P for 2 dozen banana = ₹ 3 × 24 = ₹ 72
Here S.P > C.P
Profit = S.P – C.P = 72 – 40 = 32
Profit = ₹ 32
Samacheer Kalvi 6th Maths Guide Term 2 Chapter 3 Bill, Profit and Loss Ex 3.2

Q.6A store purchased pens at ₹ 216 per dozen. He paid ₹ 58 for conveyance and sold the pens at the discount of n per pen and made an overall profit of ₹ 50. Find the M.P of each pen.v

Solution

Cost of a dozen pens = ₹ 216
Paid for conveyance = ₹ 58
Cost price of 12 pens = 216 + 58 = ₹ 274 [∵ 1 dozen = 12]
Profit of 12 pens = ₹ 50
Profit = S.P – C.P
⇒ 50 = S.P – 274
⇒ S.P = 50 + 274 = ₹ 324
Also discount allowed per pen = ₹ 2
Discount for 12 pens = 2 × 12 = ₹ 24
S.P = M.P – Discount
⇒ 324 = M.P – 24
⇒ M.P = 324 + 24 = ₹ 348
Marked price for 12 pens = ₹ 348
M.P of a pen = \(\frac { 348 }{ 12 }\) = ₹ 29
M.P per pen = ₹ 29
Samacheer Kalvi 6th Maths Guide Term 2 Chapter 3 Bill, Profit and Loss Ex 3.2

Answer:

Cost of a dozen pens = ₹ 216
Paid for conveyance = ₹ 58
Cost price of 12 pens = 216 + 58 = ₹ 274 [∵ 1 dozen = 12]
Profit of 12 pens = ₹ 50
Profit = S.P – C.P
⇒ 50 = S.P – 274
⇒ S.P = 50 + 274 = ₹ 324
Also discount allowed per pen = ₹ 2
Discount for 12 pens = 2 × 12 = ₹ 24
S.P = M.P – Discount
⇒ 324 = M.P – 24
⇒ M.P = 324 + 24 = ₹ 348
Marked price for 12 pens = ₹ 348
M.P of a pen = \(\frac { 348 }{ 12 }\) = ₹ 29
M.P per pen = ₹ 29
Samacheer Kalvi 6th Maths Guide Term 2 Chapter 3 Bill, Profit and Loss Ex 3.2

Q.7A Vegetable vendor buys 10 kg of tomatoes per day at Rs 10 per kg, for the first three days of a week. 1 kg of tomatoes got smashed every day for those 3 days. For the remaining 4 days of the week, he buys 15 kg of tomatoes daily per kg. If for the entire week he sells tomatoes at Rs 20 per kg, then find his profit or loss for the week.v

Solution

Total tomatoes bought for 3 days = 3 × 10 = 30 kg
Cost of 1 kg = ₹ 10
Cost of 30kg tomatoes = 30 × 10 = ₹ 300
Total tomatoes bought for other 4 days = 4 × 15 = 60 kg
Cost of 1 kg = ₹ 8
Cost of 60 kg tomatoes = 60 × 8 = ₹ 480
Total cost of 90 kg tomatoes = 300 + 480 = ₹ 780
C.P = ₹ 780
Tomatoes smashed = 3 kg
Total kg of Tomatoes for sale = 90 – 3 = 87 kg
S.P of 1 kg tomatoes = ₹ 20
S.P of 87 kg tomatoes = 87 × 20 = ₹ 1740
Here S.P > C.P
Profit = S.P – C.P = 1740 – 780 = ₹ 960
Profit = ₹ 960
Samacheer Kalvi 6th Maths Guide Term 2 Chapter 3 Bill, Profit and Loss Ex 3.2

Answer:

Total tomatoes bought for 3 days = 3 × 10 = 30 kg
Cost of 1 kg = ₹ 10
Cost of 30kg tomatoes = 30 × 10 = ₹ 300
Total tomatoes bought for other 4 days = 4 × 15 = 60 kg
Cost of 1 kg = ₹ 8
Cost of 60 kg tomatoes = 60 × 8 = ₹ 480
Total cost of 90 kg tomatoes = 300 + 480 = ₹ 780
C.P = ₹ 780
Tomatoes smashed = 3 kg
Total kg of Tomatoes for sale = 90 – 3 = 87 kg
S.P of 1 kg tomatoes = ₹ 20
S.P of 87 kg tomatoes = 87 × 20 = ₹ 1740
Here S.P > C.P
Profit = S.P – C.P = 1740 – 780 = ₹ 960
Profit = ₹ 960
Samacheer Kalvi 6th Maths Guide Term 2 Chapter 3 Bill, Profit and Loss Ex 3.2

Q.8An electrician buys a used T.V for ₹ 12,000 and a used Fridge for ₹ 11,000. After spending ₹ 1000 on repairing the T.V and ₹ 1500 on painting the Fridge, he fixes up the M.P of T.V as ₹ 15,000 and that of the Fridge as ₹ 15,500. If he gives each ₹ 1000 discount oh each find his profit or loss.v

Solution

(i) Cost of a T.V = ₹ 12,000
Paid for repair = ₹ 1,000
C.P of the T.V = 12,000 + 1000 = ₹ 13,000
M.P of the T.V = ₹ 15,000
Discount on a TV = ₹ 1000
S.P = M.P – Discount = 15,000 – 1000 = ₹ 14,000
Here S.P > C.P
Profit = S.P – C.P = 14,000 – 13,000 = ₹ 1,000
Profit on the T.V = ₹ 1,000
(ii) Cost of the Fridge = ₹ 11,000
Painting charge = ₹ 1500
C.P of the Fridge = 11000 + 1500 = ₹ 12,500
M.P of the Fridge = ₹ 15,500
Discount allowed = ₹ 1000
S.P = M.P – Discount = ₹ 15,500 – ₹ 1000 = ₹ 14,500
Here also S.P > C.P
Profit = ₹ 14,500 – ₹ 12,500 = ₹ 2000
Total profit = Profit on T.V + Profit on Fridge = ₹ 1000 + ₹ 2000 = ₹ 3000
Profit = ₹ 3000
Samacheer Kalvi 6th Maths Guide Term 2 Chapter 3 Bill, Profit and Loss Ex 3.2
Posted in Class 6 on January 22, 2025 January 23, 2025
Leave a Reply Cancel reply
You must be logged in to post a comment.
Facebook
Twitter
Instagram
Pinterest
Copyright © 2026 Samacheer Kalvi

Answer:

(i) Cost of a T.V = ₹ 12,000
Paid for repair = ₹ 1,000
C.P of the T.V = 12,000 + 1000 = ₹ 13,000
M.P of the T.V = ₹ 15,000
Discount on a TV = ₹ 1000
S.P = M.P – Discount = 15,000 – 1000 = ₹ 14,000
Here S.P > C.P
Profit = S.P – C.P = 14,000 – 13,000 = ₹ 1,000
Profit on the T.V = ₹ 1,000
(ii) Cost of the Fridge = ₹ 11,000
Painting charge = ₹ 1500
C.P of the Fridge = 11000 + 1500 = ₹ 12,500
M.P of the Fridge = ₹ 15,500
Discount allowed = ₹ 1000
S.P = M.P – Discount = ₹ 15,500 – ₹ 1000 = ₹ 14,500
Here also S.P > C.P
Profit = ₹ 14,500 – ₹ 12,500 = ₹ 2000
Total profit = Profit on T.V + Profit on Fridge = ₹ 1000 + ₹ 2000 = ₹ 3000
Profit = ₹ 3000
Samacheer Kalvi 6th Maths Guide Term 2 Chapter 3 Bill, Profit and Loss Ex 3.2
Posted in Class 6 on January 22, 2025 January 23, 2025
Leave a Reply Cancel reply
You must be logged in to post a comment.
Facebook
Twitter
Instagram
Pinterest
Copyright © 2026 Samacheer Kalvi