Term 1 · Class 7 Science · Chapter 2

Samacheer Class 7 Science - Force and Motion

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Chapter-wise textbook exercise answers for Force and Motion with validation-aware solutions.

Answers marked verified were checked during generation against the chapter context and source question text.
Sections in this chapter
I. Choose the appropriate answer : 5II. Fill in the blanks : 1III. Match the following : 1IV. Analogy : 3V. Give very short answer : 3VI. Give Short Answer : 4VII. Answer in detail. 2VIII. Numerical problems: 2Activity 9
Your Progress - Chapter 20% complete
1I. Choose the appropriate answer :5 questions
Q.1A particle is moving in a circular path of radius r. The displacement after half a circle would bev
  1. A. Zero
  2. B. R
  3. C. 2r
  4. D. r/2
Solution

(c) 2r

Answer:

(c) 2r

Q.2From the given v-t graph it can be inferred that the object is Force And Motion Class 7 Samacheer Kalvi Science Solutions Term 1 Chapter 2v
  1. A. in uniform motion Time
  2. B. at rest
  3. C. in non uniform motion
  4. D. moving with uniform acceleration
Solution

(d) moving with uniform acceleration

Answer:

(d) moving with uniform acceleration

Q.3Which of the following figures represent uniform motion of a moving object correctly? Force And Motion Class 7 Book Back Questions And Answers Samacheer Kalvi Science Solutions Term 1 Chapter 2v
Solution

Force And Motion Class 7 Questions And Answers Samacheer Kalvi Science Solutions Term 1 Chapter 2

Answer:

Force And Motion Class 7 Questions And Answers Samacheer Kalvi Science Solutions Term 1 Chapter 2

Q.4Suppose a boy is enjoying a ride on a merry go round which is moving with a constant speed of 10 m/s. It implies that the boy is.v
  1. A. at rest
  2. B. moving with no acceleration
  3. C. in accelerated motion
  4. D. moving with uniform velocity
Solution

(c) in accelerated motion

Answer:

(c) in accelerated motion

Q.5What is one way you might increase the stability of an object?v
  1. A. lower the centre of gravity
  2. B. raise the centre of gravity
  3. C. increase the height of the object
  4. D. shorten the base of the object
Solution

(a) lower the centre of gravity

Answer:

(a) lower the centre of gravity

2II. Fill in the blanks :1 questions
Q.G1The shortest distance between the two places is _______ The rate of change of velocity is _______ If the velocity of an object increases with respect to time, then the object is said to be in _______ acceleration. The slope of the speed-time graph gives _______ In _______ equilibrium its centre of gravity remains at the same height when it is displacementv
Solution

displacement
acceleration
positive
velocity
neutral

Answer:

displacement
acceleration
positive
velocity
neutral

3III. Match the following :1 questions
Q.G21. Displacementv
  1. (a) Knot 2. Light travels through vacuum
  2. (b) Geometric centre 3. Speed of ship
  3. (c) Metre 4. Centre of gravity of the geometrical shaped object
  4. (d) Larger base area 5. Stability
  5. (e) Uniform velocity
Solution

c
e
a
d
b

Answer:

c
e
a
d
b

4IV. Analogy :3 questions
Q.1velocity : metre/ second :: acceleration : _______v
Solution

metre/second 2

Answer:

metre/second 2

Q.2length of scale : metre : : speed of aeroplane : _______v
Solution

knot

Answer:

knot

Q.3displacement / time : velocity : : speed / time : _______v
Solution

acceleration

Answer:

acceleration

5V. Give very short answer :3 questions
Q.1All objects having uniform speed need not have uniform velocity. Describe with the help of examples.v
Solution

An object moving in uniform circular motion is moving around the perimeter of the circle with a constant speed. While the speed of object is constant, its velocity is changing, Ex: Merry-go-round, roller coaster, planets orbiting the sun.

Answer:

An object moving in uniform circular motion is moving around the perimeter of the circle with a constant speed. While the speed of object is constant, its velocity is changing, Ex: Merry-go-round, roller coaster, planets orbiting the sun.

Q.2“She moves at a constant speed in a constant direction”. Rephrase the same sentence in fewer words using concepts related to motion.v
Solution

She moves in a straight line with constant velocity.

Answer:

She moves in a straight line with constant velocity.

Q.3Correct your friend who says “The acceleration gives the idea of how fast the position changes”.v
Solution

There are two possible answers:
Velocity gives an idea of how fast the position changes, or Acceleration gives an idea of how fast the velocity changes.

Answer:

There are two possible answers:
Velocity gives an idea of how fast the position changes, or Acceleration gives an idea of how fast the velocity changes.

6VI. Give Short Answer :4 questions
Q.1Show the shape of the distance – time graph for the motion in the following cases.v
  1. A. A bus moving with a constant speed
  2. B. A car parked on a road side.
Solution

(a) A bus moving with constant speed.
Force And Motion 7th Standard Samacheer Kalvi Science Solutions Term 1 Chapter 2 Force And Motion
(b) A car parked on road side
7th Standard Science Force And Motion Question Answer Samacheer Kalvi Term 1 Chapter 2

Answer:

(a) A bus moving with constant speed.
Force And Motion 7th Standard Samacheer Kalvi Science Solutions Term 1 Chapter 2 Force And Motion
(b) A car parked on road side
7th Standard Science Force And Motion Question Answer Samacheer Kalvi Term 1 Chapter 2

Q.2Distinguish between speed and velocity.v
Solution

7th Science Force And Motion Samacheer Kalvi Term 1 Chapter 2

Answer:

7th Science Force And Motion Samacheer Kalvi Term 1 Chapter 2

Q.3What do you mean by constant acceleration?v
Solution

A body is said to have constant acceleration, if it travels is a straight line and its velocity increases or decreases by equal magnitude in equal intervals of time.
Ex: the motion of a freely falling body.

Answer:

A body is said to have constant acceleration, if it travels is a straight line and its velocity increases or decreases by equal magnitude in equal intervals of time.
Ex: the motion of a freely falling body.

Q.4What is centre of gravity ?v
Solution

The centre of gravity of an object is the point through which the entire weight of the object appears to act.

Answer:

The centre of gravity of an object is the point through which the entire weight of the object appears to act.

7VII. Answer in detail.2 questions
Q.1Explain the types of stability with suitable examples.v
Solution

Stability is a measure of the body’s ability to maintain its original position.
The three types of stability are
Stable equilibrium
Unstable equilibrium
Neutral equilibrium
Stable Equilibrium:
The frustum can be tilted through quite a big angle without toppling.
7th Standard Science Force And Motion Samacheer Kalvi Term 1 Chapter 2
Its centre of gravity is raised when it is displaced. The vertical line through its centre of gravity still falls within its base. So it can return to its originalposition.
Unstable Equilibrium:
The frustum will topple with the slightest tilting. Its centre of gravity is lowered when it is displaced.
Samacheer Kalvi Guru 7th Science Solutions Term 1 Chapter 2 Force And Motion
The vertical line through its centre of gravity falls outside its base.
Samacheer Kalvi 7th Science Books Answers Term 1 Chapter 2 Force And Motion
Neutral Equilibrium:
It causes frustum to topple.
The frustum will roll about but does not topple.
Its centre of gravity remains at the same height when it is displaced.
The body will stay in any position to which it has been displaced.

Answer:

Stability is a measure of the body’s ability to maintain its original position.
The three types of stability are
Stable equilibrium
Unstable equilibrium
Neutral equilibrium
Stable Equilibrium:
The frustum can be tilted through quite a big angle without toppling.
7th Standard Science Force And Motion Samacheer Kalvi Term 1 Chapter 2
Its centre of gravity is raised when it is displaced. The vertical line through its centre of gravity still falls within its base. So it can return to its originalposition.
Unstable Equilibrium:
The frustum will topple with the slightest tilting. Its centre of gravity is lowered when it is displaced.
Samacheer Kalvi Guru 7th Science Solutions Term 1 Chapter 2 Force And Motion
The vertical line through its centre of gravity falls outside its base.
Samacheer Kalvi 7th Science Books Answers Term 1 Chapter 2 Force And Motion
Neutral Equilibrium:
It causes frustum to topple.
The frustum will roll about but does not topple.
Its centre of gravity remains at the same height when it is displaced.
The body will stay in any position to which it has been displaced.

Q.2Write about the experiment to find the centre of gravity of the irregularly shaped plate.v
Solution

Make three holes in the lamina.
Suspend the lamina from the optical pin through one of the holes
Samacheer Kalvi 7th Books Science Solutions Term 1 Chapter 2 Force And Motion
Suspend the plumb line from the pin and mark the position of the plumb line on the lamina’
Draw lines on the lamina representing the positions of the plumb line.
Repeat the above steps for the holes.
Label the intersection of the three lines as X, the position of the center of gravity of the lamina.

Answer:

Make three holes in the lamina.
Suspend the lamina from the optical pin through one of the holes
Samacheer Kalvi 7th Books Science Solutions Term 1 Chapter 2 Force And Motion
Suspend the plumb line from the pin and mark the position of the plumb line on the lamina’
Draw lines on the lamina representing the positions of the plumb line.
Repeat the above steps for the holes.
Label the intersection of the three lines as X, the position of the center of gravity of the lamina.

8VIII. Numerical problems:2 questions
Q.1Geetha takes 15 minutes from her house to reach her school on a bicycle. If the bicycle lias a speed of 2 m/s, calculate the distance between her house and the school.v
Solution

Given : time taken = 15 minutes [1 min = 60 sec]
= 15 x 60 = 900 sec
Speed – 2 m/s
Distance = ?
Formula : Distance = Speed x time = 2 x 900
Distance between her house and the school = 1,800 m

Answer:

Given : time taken = 15 minutes [1 min = 60 sec]
= 15 x 60 = 900 sec
Speed – 2 m/s
Distance = ?
Formula : Distance = Speed x time = 2 x 900
Distance between her house and the school = 1,800 m

Q.2A car started from rest and travelling with velocity of 20 m /s in 10 s. What is its acceleration?v
Solution

Given :
Initial velocity of the car (u) = 0 m/s
Final velocity of the car (v) = 20 m/s
time taken = 10s
Acceleration = ?
Formula: Acceleration = \(\frac { 20 – 0 }{ 10 }\) = \(\frac { 20 }{ 10 }\)
Acceleration of the car = 2 m/s2

Answer:

Given :
Initial velocity of the car (u) = 0 m/s
Final velocity of the car (v) = 20 m/s
time taken = 10s
Acceleration = ?
Formula: Acceleration = \(\frac { 20 – 0 }{ 10 }\) = \(\frac { 20 }{ 10 }\)
Acceleration of the car = 2 m/s2

9Activity9 questions
Q.1As shown in the above picture, Kavitha can reach her school in two ways. Can you tell, by choosing which path she could reach the school early. Samacheer Kalvi 7th Science Solutions Term 1 Chapter 2 Force And Motion Road A Road Bv
Solution

By choosing road A kavitha could reach the school early as the distance is less compared to road B.

Answer:

By choosing road A kavitha could reach the school early as the distance is less compared to road B.

Q.3Uma and Priya are friends studying in the same school. After school hours, they go to the nearby playground, play games and return back home. One day Uma told that she would reach the playground after visiting her grandmother’s house. The path in which they took reached the playground is shown here. Samacheer Kalvi 7th Standard Science Solutions Term 1 Chapter 2 Force And Motion Take a twine and measure the length of the two paths (A & B). Which is the longest path among the two?v
Solution

Path A is the longest among the two. as it is not a straight line.

Answer:

Path A is the longest among the two. as it is not a straight line.

Q.4The path in which a rabbit ran is shown in figure. Find the distance and displacement of it in the two figures. Let us consider that each square is in an unit of one square meter. The rabbit starts from point A and reaches the point B. Samacheer Kalvi 7th Science Book Answers Term 1 Chapter 2 Force And Motion When will the distance and displacement be equal. Explain. But the starting and finishing points should be different. _______v
Solution

Distance : 17
Distance: 24
Displacement: 3
Displacement: 1
When the rabbit moves in a straight line from A to B, the distance and displacement will be equal.

Answer:

Distance : 17
Distance: 24
Displacement: 3
Displacement: 1
When the rabbit moves in a straight line from A to B, the distance and displacement will be equal.

Q.1What is the distance she travelled?v
Solution

400 m

Answer:

400 m

Q.3The distance travelled by an object is 15 km and its displacement is 15 km. What do you infer from this?v
Solution

The object moves in a straight line in one direction without turning back.

Answer:

The object moves in a straight line in one direction without turning back.

Q.4The distance of a person is 30 km and his displacement is 0 km. What do you infer from this?v
Solution

The distance of a person = 30 km Displacement = 0 km.

Answer:

The distance of a person = 30 km Displacement = 0 km.

Q.6Answer the following questions: (i) Calculate the velocity of a car travelling with a uniform velocity covering 100 m distance in 4 seconds.v
Solution

Samacheer Kalvi 7th Standard Science Book Term 1 Chapter 2 Force And Motion
(ii) Usain Bolt covers 100 m distance in 9.58 seconds. Calculate his speed. Who will be the winner if Usain Bolt comepetes with a Cheetah running at a speed of 30 m/s
Samacheer Kalvi Science 7th Standard Term 1 Chapter 2 Force And Motion
(iii) You are walking along east covering a distance of 4 m, then 2 m towards south, then 4 m towards west and at last 2 m towards north. You cover the total distance in 21 seconds, what is your average speed and average velocity?
Total distance covered = 12 m
Total time taken =21 seconds
Samacheer Kalvi 7th Science Books Term 1 Chapter 2 Force And Motion
\(\frac { 12m }{ 21 }\) = 0.571 m/s
Average velocity = 0 m/s
Average velocity is zero because the starting point and the finishing point is same
∴Displacement is zero so, average velocity is also
Samacheer Kalvi 7th Science Solution Term 1 Chapter 2 Force And Motion

Answer:

Samacheer Kalvi 7th Standard Science Book Term 1 Chapter 2 Force And Motion
(ii) Usain Bolt covers 100 m distance in 9.58 seconds. Calculate his speed. Who will be the winner if Usain Bolt comepetes with a Cheetah running at a speed of 30 m/s
Samacheer Kalvi Science 7th Standard Term 1 Chapter 2 Force And Motion
(iii) You are walking along east covering a distance of 4 m, then 2 m towards south, then 4 m towards west and at last 2 m towards north. You cover the total distance in 21 seconds, what is your average speed and average velocity?
Total distance covered = 12 m
Total time taken =21 seconds
Samacheer Kalvi 7th Science Books Term 1 Chapter 2 Force And Motion
\(\frac { 12m }{ 21 }\) = 0.571 m/s
Average velocity = 0 m/s
Average velocity is zero because the starting point and the finishing point is same
∴Displacement is zero so, average velocity is also
Samacheer Kalvi 7th Science Solution Term 1 Chapter 2 Force And Motion

Q.8My name is cheetah. I can run at a great speed. Do you know what my speed is? 25 m/s to 30 m/s. My speed changes from 0 to 20 m/s in 2 second. See how good my acceleration is ! From the above information, can you calculate the acceleration of the cheetah?v
Solution

Samacheer Kalvi 7th Science Answers Solutions Term 1 Chapter 2 Force And Motion

Answer:

Samacheer Kalvi 7th Science Answers Solutions Term 1 Chapter 2 Force And Motion

Q.9Samacheer Kalvi 7th Science Solutions Term 1 Chapter 1 Force And Motion When the velocity of the object is increasing by 20 m/s the acceleration is 20 m/s2 When the velocity of the object is decreasing by 20 m/s the deceleration is 20 m/s2.v
Solution

When the velocity of the object is decreasing by 20m/s the deceleration is 20 m/s2.
Samacheer Kalvi 7th Science Solutions Term 1 Chapter 1 Force And Motion
The velocity of the object is decreasing by 20m/s in one second.

Answer:

When the velocity of the object is decreasing by 20m/s the deceleration is 20 m/s2.
Samacheer Kalvi 7th Science Solutions Term 1 Chapter 1 Force And Motion
The velocity of the object is decreasing by 20m/s in one second.