CBSE · NCERT · Class 6 Maths · Chapter 2

NCERT Solutions: Class 6 Maths Chapter 2 - Lines and Angles

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Chapter-wise NCERT intext questions and exercise answers for Lines and Angles, grounded in the official textbook.

Questions are taken verbatim from the NCERT textbook; answers were grounded against the chapter's content during generation. Items needing review are marked.
Sections in this chapter
Figure it Out (Section 2.4) 6Figure it Out (Section 2.5) 6Figure it Out (Comparing Angles) 3Section 2.8 1Figure it Out (Section 2.8) 4Figure it Out (Classifying Angles) 4Figure it out (Section 2.9) 1Section 2.9 1Think (Section 2.10) 1Figure it Out (Section 2.10) 8Figure it Out (Where are the angles?) 4Figure it Out (Section 2.11) 7Let's Explore (Section 2.11) 1
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1Figure it Out (Section 2.4)6 questions
Q.1Can you help Rihan and Sheetal find their answers?v
Solution

A single point does not fix the direction of a line, so many lines can pass through it. Two distinct points determine a unique straight line.

Answer:

Rihan can draw infinitely many lines through one point. Sheetal can draw exactly one line through two given distinct points.

Q.2Name the line segments in Fig. 2.4. Which of the five marked points are on exactly one of the line segments? Which are on two of the line segments?v
Solution

In the chain $L-M-P-Q-R$, each adjacent pair forms one segment. End points belong to one segment, while the middle joining points belong to two adjacent segments.

Answer:

The line segments are $LM$, $MP$, $PQ$ and $QR$. Points $L$ and $R$ are on exactly one line segment. Points $M$, $P$ and $Q$ are on two line segments.

Q.3Name the rays shown in Fig. 2.5. Is T the starting point of each of these rays?v
Solution

A ray is named by writing its starting point first. In ray $NB$, the starting point is $N$, not $T$.

Answer:

The rays are $TA$, $TB$, $TN$ and $NB$. No, $T$ is the starting point of $TA$, $TB$ and $TN$, but not of $NB$.

Q.4Draw a rough figure and write labels appropriately to illustrate each of the following: a. OP and OQ meet at O. b. XY and PQ intersect at point M. c. Line l contains points E and F but not point D. d. Point P lies on AB.v
Solution

Each drawing should show the stated incidence relation: meeting, intersecting, lying on a line, or lying away from a line.

Answer:

a. Draw two line segments or rays $OP$ and $OQ$ with common point $O$. b. Draw lines $XY$ and $PQ$ crossing at $M$. c. Draw a line $l$ through $E$ and $F$, and mark $D$ away from the line. d. Draw segment or line $AB$ and mark $P$ on it.

Q.5In Fig. 2.6, name: a. Five points b. A line c. Four rays d. Five line segmentsv
Solution

The named points lie on the figure. A line can be named by any two points on it. Rays are named with their starting point first, and line segments are named by their two endpoints.

Answer:

a. Five points: $D,E,O,B,C$. b. A line: $DE$ or $DB$. c. Four rays: $OC$, $OB$, $OE$, $OD$. d. Five line segments: $DE$, $DO$, $DB$, $EO$, $EB$.

Q.6Here is a ray OA (Fig. 2.7). It starts at O and passes through the point A. It also passes through the point B. a. Can you also name it as OB? Why? b. Can we write OA as AO? Why or why not?v
Solution

The first letter in the name of a ray gives its starting point. Other points on the same ray may be used as the second letter.

Answer:

a. Yes. It can also be named $OB$ because $O$ is the starting point and $B$ lies on the same ray. b. No. $OA$ starts at $O$, while $AO$ would start at $A$, so they are different rays.

2Figure it Out (Section 2.5)6 questions
Q.1Can you find the angles in the given pictures? Draw the rays forming any one of the angles and name the vertex of the angle.v
Solution

An angle is formed by two rays with a common starting point. The common starting point is the vertex.

Answer:

Yes. One possible angle is $\angle BDC$, with vertex $D$ and arms/rays $DB$ and $DC$.

Q.2Draw and label an angle with arms ST and SR.v
Solution

Both arms have the same starting point $S$, so $S$ must be the middle letter when naming the angle.

Answer:

Draw two rays $ST$ and $SR$ starting from the same point $S$. The angle is $\angle TSR$ or $\angle RST$, and its vertex is $S$.

Q.3Explain why ∠APB cannot be labelled as ∠P.v
Solution

When several rays meet at the same vertex, using only the vertex name is ambiguous. Three-letter notation identifies the exact arms of the angle.

Answer:

$\angle APB$ cannot be labelled only as $\angle P$ because more than one angle is formed at point $P$ in the figure.

Q.4Name the angles marked in the given figure.v
Solution

The common vertex is $T$. Use one point from each arm with the vertex in the middle.

Answer:

The marked angles are $\angle RTQ$ and $\angle RTP$.

Q.5Mark any three points on your paper that are not on one line. Label them A, B, C. Draw all possible lines going through pairs of these points. How many lines do you get? Name them. How many angles can you name using A, B, C? Write them down, and mark each of them with a curve as in Fig. 2.9.v
Solution

Three non-collinear points form a triangle. Each pair of points determines one line, and each point can be used as the vertex of one angle of the triangle.

Answer:

You get three lines: $AB$, $BC$ and $CA$. You can name three angles: $\angle ABC$, $\angle BCA$ and $\angle CAB$; equivalently, $\angle CBA$, $\angle ACB$ and $\angle BAC$.

Q.6Now mark any four points on your paper so that no three of them are on one line. Label them A, B, C, D. Draw all possible lines going through pairs of these points. How many lines do you get? Name them. How many angles can you name using A, B, C, D? Write them all down, and mark each of them with a curve as in Fig. 2.9.v
Solution

Four points with no three collinear determine one line for each pair of points: $\binom{4}{2}=6$. At each point, three rays to the other points form three angles, giving $4\times3=12$ named angles.

Answer:

You get six lines: $AB$, $AC$, $AD$, $BC$, $BD$ and $CD$. The angles include $\angle BAC$, $\angle CAD$, $\angle BAD$, $\angle ADB$, $\angle BDC$, $\angle ADC$, $\angle DCA$, $\angle ACB$, $\angle DCB$, $\angle CBD$, $\angle DBA$ and $\angle CBA$.

3Figure it Out (Comparing Angles)3 questions
Q.1Fold a rectangular sheet of paper, then draw a line along the fold created. Name and compare the angles formed between the fold and the sides of the paper. Make different angles by folding a rectangular sheet of paper and compare the angles. Which is the largest and smallest angle you made?v
Solution

Compare the angles by superimposition or by observing the amount of opening between the fold and the side of the paper.

Answer:

A sample fold creates angles such as $\angle AEF$, $\angle BEF$, $\angle DFE$ and $\angle CFE$. In one such fold, $\angle AEF$ and $\angle CFE$ are larger than $\angle BEF$ and $\angle DFE$. The largest and smallest angles depend on the fold made.

Q.2In each case, determine which angle is greater and why. a. ∠AOB or ∠XOY b. ∠AOB or ∠XOB c. ∠XOB or ∠XOC Discuss with your friends on how you decided which one is greater.v
Solution

$\angle AOB$ contains smaller parts including $\angle XOY$, so it is greater. In part c, the two angles are equal by symmetry in the given figure.

Answer:

a. $\angle AOB$ is greater. b. $\angle AOB$ is greater. c. Neither is greater; $\angle XOB=\angle XOC$.

Q.3Which angle is greater: ∠XOY or ∠AOB? Give reasons.v
Solution

When angles are close in size or placed differently, visual comparison may be misleading. Folding, tracing or measuring can compare them accurately.

Answer:

From the printed figure alone, it is not reliable to decide by sight. Superimposition or measurement is needed.

4Section 2.81 questions
Q.1If a straight angle is formed by half of a full turn, how much of a full turn will form a right angle?v
Solution

A straight angle is half a full turn and contains two right angles. Therefore one right angle is half of a straight angle, which is $\frac{1}{4}$ of a full turn.

Answer:

A right angle is $\frac{1}{4}$ of a full turn.

5Figure it Out (Section 2.8)4 questions
Q.1How many right angles do the windows of your classroom contain? Do you see other right angles in your classroom?v
Solution

A right angle looks like an exact L-shape and measures $90^\circ$.

Answer:

A usual rectangular classroom window has four right angles. Other right angles may be seen at the corners of the blackboard, books, door frames, floor tiles and desks.

Q.2Join A to other grid points in the figure by a straight line to get a straight angle. What are all the different ways of doing it?v
Solution

A straight angle is formed when the two arms are opposite rays of the same line. So the new point must be collinear with $A$ and $B$.

Answer:

Join $A$ to grid points that lie on the same straight line through $A$ and $B$, on either side if available.

Q.3Now join A to other grid points in the figure by a straight line to get a right angle. What are all the different ways of doing it?v
Solution

A right angle at $A$ is formed by a line through $A$ that divides the straight angle on line $AB$ into two equal parts.

Answer:

Join $A$ to any grid point lying on a line through $A$ that is perpendicular to line $AB$.

Q.4Get a slanting crease on the paper. Now, try to get another crease that is perpendicular to the slanting crease. a. How many right angles do you have now? Justify why the angles are exact right angles. b. Describe how you folded the paper so that any other person who doesn't know the process can simply follow your description to get the right angle.v
Solution

Two perpendicular creases intersect to form four equal angles around a point. Since a full turn is $360^\circ$, each is $360^\circ\div4=90^\circ$, a right angle.

Answer:

a. Four right angles are formed. b. Fold the paper so that the slanting crease falls exactly on itself in the opposite direction; the new crease made by the fold is perpendicular to the first crease.

6Figure it Out (Classifying Angles)4 questions
Q.1Identify acute, right, obtuse and straight angles in the previous figures.v
Solution

Use the definitions: acute $<90^\circ$, right $=90^\circ$, obtuse between $90^\circ$ and $180^\circ$, and straight $=180^\circ$.

Answer:

Angles smaller than a right angle are acute; angles exactly like an L-shape are right; angles greater than a right angle but less than a straight angle are obtuse; angles forming a straight line are straight.

Q.2Make a few acute angles and a few obtuse angles. Draw them in different orientations.v
Solution

Draw any angles less than $90^\circ$ for acute angles and any angles greater than $90^\circ$ but less than $180^\circ$ for obtuse angles.

Answer:

Examples of acute angles: $30^\circ$, $45^\circ$, $60^\circ$. Examples of obtuse angles: $110^\circ$, $125^\circ$, $150^\circ$.

Q.3Do you know what the words acute and obtuse mean? Acute means sharp and obtuse means blunt. Why do you think these words have been chosen?v
Solution

The names describe the visual appearance of the angle openings.

Answer:

The word acute fits because an acute angle has a small, sharp opening. The word obtuse fits because an obtuse angle has a wider, blunter opening.

Q.4Find out the number of acute angles in each of the figures below. What will be the next figure and how many acute angles will it have? Do you notice any pattern in the numbers?v
Solution

The number of acute angles increases by 9 each time: $3,12,21,30,\ldots$. Thus the next count is $21+9=30$.

Answer:

The numbers are 3, 12 and 21. The next figure will have 30 acute angles.

7Figure it out (Section 2.9)1 questions
Q.1Write the measures of the following angles: a. ∠ KAL b. ∠WAL c. ∠TAKv
Solution

Read the protractor marks from the common vertex $A$ and count the degree units between the arms of each angle.

Answer:

$\angle KAL=30^\circ$, $\angle WAL=50^\circ$, and $\angle TAK=120^\circ$.

8Section 2.91 questions
Q.2Name the different angles in the figure and write their measures.v
Solution

Each angle is measured at the common vertex $O$ by subtracting the protractor positions of its two arms.

Answer:

$\angle POQ=35^\circ$, $\angle POR=95^\circ$, $\angle POS=125^\circ$, $\angle POT=160^\circ$, $\angle QOR=60^\circ$, $\angle QOS=90^\circ$, $\angle QOT=125^\circ$, $\angle QOU=145^\circ$, $\angle ROS=30^\circ$, $\angle ROT=65^\circ$, $\angle ROU=85^\circ$, $\angle SOT=35^\circ$, $\angle SOU=55^\circ$, $\angle TOU=20^\circ$.

9Think (Section 2.10)1 questions
Q.1In Fig. 2.19, we have ∠AOB = ∠BOC = ∠COD = ∠DOE = ∠EOF = ∠FOG = ∠GOH = ∠HOI=_____. Why?v
Solution

The straight angle of $180^\circ$ is divided into 8 equal parts. Therefore each part measures $180^\circ\div8=22.5^\circ$.

Answer:

Each angle is $22.5^\circ$.

10Figure it Out (Section 2.10)8 questions
Q.1Find the degree measures of the following angles using your protractor.v
Solution

Place the protractor centre at the vertex and read the degree mark where the second arm meets the scale.

Answer:

The angle measures are approximately $47^\circ$, $23^\circ$ and $108^\circ$ for the three given diagrams.

Q.2Find the degree measures of different angles in your classroom using your protractor.v
Solution

Use a protractor to measure real classroom angles by placing its centre on the vertex and aligning one arm with the baseline.

Answer:

Sample observations: a book corner is $90^\circ$, a door opened partly may be about $60^\circ$, and a clock-hands angle at 3 o'clock is $90^\circ$.

Q.3Find the degree measures for the angles given below. Check if your paper protractor can be used here!v
Solution

A standard protractor is needed when the angle placement or available space does not suit the handmade paper protractor.

Answer:

The angle measures are $42^\circ$ and $116^\circ$. A paper protractor cannot be used conveniently here.

Q.4How can you find the degree measure of the angle given below using a protractor?v
Solution

Measure the smaller unmarked angle as $100^\circ$. The full turn is $360^\circ$, so the marked reflex angle is $360^\circ-100^\circ=260^\circ$.

Answer:

The marked angle is $260^\circ$.

Q.5Measure and write the degree measures for each of the following angles:v
Solution

Measure each angle with a protractor, keeping the centre at the vertex and one arm along the baseline.

Answer:

a. $80^\circ$ b. $120^\circ$ c. $60^\circ$ d. $130^\circ$ e. $130^\circ$ f. $60^\circ$

Q.6Find the degree measures of ∠BXE, ∠CXE, ∠AXB and ∠BXC.v
Solution

Read each ray's position on the protractor and subtract the relevant degree marks to find the angle between the rays.

Answer:

$\angle BXE=115^\circ$, $\angle CXE=85^\circ$, $\angle AXB=65^\circ$ and $\angle BXC=30^\circ$.

Q.7Find the degree measures of ∠PQR, ∠PQS and ∠PQT.v
Solution

All three angles have vertex $Q$ and arm $QP$ as one side. Measure from $QP$ to $QR$, $QS$ and $QT$ respectively.

Answer:

$\angle PQR=45^\circ$, $\angle PQS=100^\circ$ and $\angle PQT=150^\circ$.

Q.8In Fig. 2.23, list all the angles possible. Did you find them all? Now, guess the measures of all the angles. Then, measure the angles with a protractor. Record all your numbers in a table. See how close your guesses are to the actual measures.v
Solution

List angles by choosing a vertex where two segments or rays meet, then name one point on each arm with the vertex in the middle. Measures should be found with a protractor.

Answer:

Some angles possible are $\angle CAP$, $\angle ACD$, $\angle APL$, $\angle DLP$, $\angle RPL$, $\angle SLP$, $\angle PRS$, $\angle LSR$, $\angle BRS$ and $\angle CLP$.

11Figure it Out (Where are the angles?)4 questions
Q.1Angles in a clock: a. The hands of a clock make different angles at different times. At 1 o'clock, the angle between the hands is 30°. Why? b. What will be the angle at 2 o'clock? And at 4 o'clock? 6 o'clock? c. Explore other angles made by the hands of a clock.v
Solution

Each hour step corresponds to $30^\circ$. Multiply $30^\circ$ by the number of hour steps between the hands.

Answer:

a. The clock face is divided into 12 equal parts, so each part is $360^\circ\div12=30^\circ$. b. At 2 o'clock the angle is $60^\circ$, at 4 o'clock it is $120^\circ$, and at 6 o'clock it is $180^\circ$. c. For example, at 3 o'clock the smaller angle is $90^\circ$.

Q.2The angle of a door: Is it possible to express the amount by which a door is opened using an angle? What will be the vertex of the angle and what will be the arms of the angle?v
Solution

The amount of opening is the rotation of the door about the hinge.

Answer:

Yes. The vertex is at the hinge where the door meets the wall. The arms are the edge or position of the door and the wall or closed-door position.

Q.3Vidya is enjoying her time on the swing. She notices that the greater the angle with which she starts the swinging, the greater is the speed she achieves on her swing. But where is the angle? Are you able to see any angle?v
Solution

The swing moves by rotation about its support. The starting angle measures how far the rope has been turned from its resting position.

Answer:

The angle can be seen between the resting vertical position of the swing rope and the pulled-back position of the rope before release.

Q.4Here is a toy with slanting slabs attached to its sides; the greater the angles or slopes of the slabs, the faster the balls roll. Can angles be used to describe the slopes of the slabs? What are the arms of each angle? Which arm is visible and which is not?v
Solution

A slope can be described by the angle made between the slanting surface and a reference line.

Answer:

Yes. Angles can describe the slopes of the slabs. One arm is along the slanting slab and the other arm can be taken as the horizontal or vertical reference direction. The slanting slab arm is visible; the reference arm may be imagined and may not be visible in the toy.

12Figure it Out (Section 2.11)7 questions
Q.1In each of the below grids, join A to other grid points in the figure by a straight line to get: a. An acute angle b. An obtuse angle c. A reflex angle Mark the intended angles with curves to specify the angles. One has been done for you.v
Solution

Use the degree-measure definitions of acute, obtuse and reflex angles to choose suitable rays from $A$.

Answer:

Draw from $A$ to a grid point making an angle less than $90^\circ$ for an acute angle, between $90^\circ$ and $180^\circ$ for an obtuse angle, and greater than $180^\circ$ but less than $360^\circ$ for a reflex angle.

Q.2Use a protractor to find the measure of each angle. Then classify each angle as acute, obtuse, right, or reflex.v
Solution

Classify using the measure: acute is less than $90^\circ$, obtuse is between $90^\circ$ and $180^\circ$, and reflex is between $180^\circ$ and $360^\circ$.

Answer:

a. $\angle PTR=30^\circ$ (acute). b. $\angle PTQ=60^\circ$ (acute). c. $\angle PTW=102^\circ$ (obtuse). d. $\angle WTP=258^\circ$ (reflex).

Q.3Make any figure with three acute angles, one right angle and two obtuse angles.v
Solution

Any drawing is acceptable if it contains exactly the required types of angles: three less than $90^\circ$, one equal to $90^\circ$, and two between $90^\circ$ and $180^\circ$.

Answer:

One valid figure can have angles $40^\circ$, $50^\circ$, $60^\circ$ as the three acute angles, $90^\circ$ as the right angle, and $110^\circ$, $120^\circ$ as the two obtuse angles.

Q.4Draw the letter 'M' such that the angles on the sides are 40° each and the angle in the middle is 60°.v
Solution

Use a protractor to mark the two side turns as $40^\circ$ and the central turn as $60^\circ$, then join the arms to form the letter M.

Answer:

Draw an M whose left and right side angles are each $40^\circ$ and whose middle angle is $60^\circ$.

Q.5Draw the letter 'Y' such that the three angles formed are 150°, 60° and 150°.v
Solution

The three angles around the joining point must add to $360^\circ$: $150^\circ+60^\circ+150^\circ=360^\circ$.

Answer:

Draw a Y with the upper two arms separated by $60^\circ$, and each upper arm making $150^\circ$ with the lower stem on the outside.

Q.6The Ashoka Chakra has 24 spokes. What is the degree measure of the angle between two spokes next to each other? What is the largest acute angle formed between two spokes?v
Solution

A full turn is $360^\circ$. With 24 equally spaced spokes, adjacent spokes make $360^\circ\div24=15^\circ$. Acute multiples are $15^\circ,30^\circ,45^\circ,60^\circ,75^\circ$; the next, $90^\circ$, is right, so the largest acute angle is $75^\circ$.

Answer:

The angle between two neighbouring spokes is $15^\circ$. The largest acute angle formed between two spokes is $75^\circ$.

Q.7Puzzle: I am an acute angle. If you double my measure, you get an acute angle. If you triple my measure, you will get an acute angle again. If you quadruple (four times) my measure, you will get an acute angle yet again! But if you multiply my measure by 5, you will get an obtuse angle measure. What are the possibilities for my measure?v
Solution

Let the angle be $x^\circ$. Since $4x$ is acute, $4x<90$, so $x<22.5$. Since $5x$ is obtuse, $90<5x<180$, so $x>18$. Whole-number values satisfying both are $19,20,21,22$.

Answer:

For whole-number degree measures, the possibilities are $19^\circ$, $20^\circ$, $21^\circ$ and $22^\circ$.

13Let's Explore (Section 2.11)1 questions
Q.1In this figure, ∠TER = 80°. What is the measure of ∠BET? What is the measure of ∠SET?v
Solution

$\angle REB$ is a straight angle, so it measures $180^\circ$. Since $\angle TER=80^\circ$, $\angle BET=180^\circ-80^\circ=100^\circ$. Also, $\angle BES=90^\circ$, so $\angle SET=100^\circ-90^\circ=10^\circ$.

Answer:

$\angle BET=100^\circ$ and $\angle SET=10^\circ$.