The game occurring the greatest number of times in the organised table is the most popular game.
Arrange and organise the collected favourite-game data in a table, then count the frequency of each game.
Counting the list gives Hockey a frequency of $8$, which is greater than the frequency of any other game.
Hockey.
Ask each classmate for one favourite game, make a frequency table, and identify the game with the highest frequency.
The answer depends on the data collected from the class.
Questions a and c ask about a group or locality and need fresh data collection. Questions b and d are fixed factual questions and can be answered without collecting new data.
a. $\checkmark$; b. $\times$; c. $\checkmark$; d. $\times$.
Read the tally marks in the table. Jalebi has $6$, Barfi has $3$, Gujiya has $13$, Rasgulla has $7$, and Gulab jamun has $9$ students.
a. $6$; b. $3$; c. $13$; d. $7$; e. $9$.
The table gives only how many students chose each sweet. It does not tell which student chose which sweet. An alternative is to group or list students according to their sweet preference.
No.
From the ordered data, the smallest value is $3$ and the largest value is $7$. Shoe size $5$ appears $10$ times. Sizes larger than $4$ are the ten $5$s, four $6$s, and one $7$, giving $10+4+1=15$ students.
a. $7$; b. $3$; c. $10$; d. $15$.
When equal sizes are placed together, we can count repetitions quickly and use the data without searching through an unordered list.
It made the smallest and largest sizes easy to see and made the frequency of each size easy to count.
A frequency table lists each shoe size once and records how many students have that size.
Yes, the data can be arranged in a frequency table.
If one symbol represents $10$ students and a half-symbol represents $5$ students, then totals such as $33$ or $27$ require parts representing $3$ or $7$ students, which are not easy to show accurately.
It would be difficult to represent the leftover $3$ or $7$ students accurately with symbols meant for $10$ students and half-symbols meant for $5$ students.
Reading the pictograph, Thursday has the fewest symbols and Saturday has the most. Adding the daily counts gives a total of $24$ books. A possible reason for the maximum on Saturday is that Sunday is a holiday, so students can read the books then.
a. Thursday; b. $24$ books; c. Saturday.
Since one symbol represents $100$ kites, Rani's $300$ kites require $3$ symbols. Poonam Ben purchased $700$ kites, the maximum. Jasmeet purchased $450$ kites and Chaman purchased $250$, so Jasmeet purchased more. Double Rani's purchase is $2\times300=600$; Poonam Ben purchased $700$, which is more than double.
a. $3$ symbols; b. Poonam Ben; c. Jasmeet; d. Yes.
The bar graph and table show $5$ absent students for Class 2.
$5$ students.
Class 8 has the tallest bar, representing $7$ absent students, which is the greatest value.
Class 8.
Full attendance means zero absences. The graph shows $0$ absent students for Class 5.
Class 5.
The hourly values are about $150, 1200, 1000, 800, 700,$ and $600$. Their sum is $150+1200+1000+800+700+600=4450$ cars.
$4450$ cars.
Traffic generally increases when offices, schools and markets begin. The 6-7 a.m. interval is earlier than those peak travel times.
A likely reason is that fewer people travel very early in the morning.
The bar for 7-8 a.m. is the longest. This interval commonly matches morning commute time, so traffic is expected to be high.
A likely reason is that many people travel to schools, offices and workplaces during this hour.
The bars become shorter after 8 a.m. This suggests that fewer vehicles pass the crossing once the peak travel period is over.
A likely reason is that the main morning commute reduces after most people have reached their destinations.
The expenses are Food $= Rs\ 3400$ and House rent $= Rs\ 3000$. These are the two largest amounts in the table.
Most on food and second most on house rent.
Education costs $Rs\ 800$ and electricity costs $Rs\ 400$. Since $400=\frac{1}{2}\times800$, electricity is one-half of education.
Yes.
Food costs $Rs\ 3400$, so one-fourth is $3400\div4=Rs\ 850$. Education costs $Rs\ 800$, and $800<850$.
Yes.
Use the insects as categories on one axis and the number seen on the other axis. A convenient scale is $1$ unit length $=1$ insect, giving bar heights $6,10,5,3,$ and $2$.
Draw bars for Mites $6$, Caterpillars $10$, Beetles $5$, Butterflies $3$, and Grasshoppers $2$.
The table gives Vidisha $24$, Jabalpur $20$, Seoni $16$, Indore $28$, and Sagar $16$. Since Vidisha has $24$ tickets and a bar of $6$ unit lengths, the scale is $24\div6=4$ tickets per unit. Sagar's $16$ tickets need $16\div4=4$ unit lengths, and Indore's $28$ tickets need $28\div4=7$ unit lengths.
a. $24$; b. $20$; c. $1$ unit length $=4$ tickets; d. Sagar's bar should represent $16$ tickets; e. mark the vertical axis in steps of $4$ tickets; f. Seoni is correct, Indore is incorrect.
Counting each vehicle type in the list gives the frequency table. The largest frequency is Bike with $13$, so it was used the most. For data collection, prepare a two-column table, list each vehicle type as it passes, mark tallies, and convert tallies into frequencies.
a. Bike $13$, Car $6$, Bicycle $8$, Auto Rickshaw $8$, Scooter $9$, Bus $4$, Bullock Cart $2$; b. Bike; c. Record each passing vehicle using tally marks and then total the tallies.
Make a table with die faces $1$ to $6$. For each roll, add one tally mark in the corresponding row. Count the tallies to find the least frequent face, the most frequent face, and any faces with equal frequencies.
The answer depends on the actual outcomes obtained in the 30 die rolls.
To get total wickets, multiply each wicket count by the number of matches: $0\times2+1\times4+2\times6+3\times8+4\times3+5\times5+6\times1+7\times1=0+4+12+24+12+25+6+7=90$. Adding only $0+1+2+\cdots+7$ ignores how many matches had each wicket count.
a. It shows how many matches had each wicket count from $0$ to $7$; b. Wickets Taken by Jaspreet Bumrah in Last 30 Matches; c. One notable point is that he took $7$ wickets in one match; d. $3$ matches; e. No; f. the total number of wickets is $90$.
Read the pictograph with one symbol representing one tractor. Village C has the largest count, Village D the smallest count, and Village C has $3$ more tractors than Village B. Village D's count is half of Village E's count.
a. Village D; b. Village C; c. $3$ tractors; d. Yes.
The key is one full symbol $=4$ girls. Reading the pictograph, Class 8 has the least number of girls. The difference between Classes 5 and 6 is $6$. Adding $2$ girls to Class 2 converts its half-symbol into a full symbol. Class 7 has $12$ girls.
a. Class 8; b. $6$; c. the last half-symbol for Class 2 would become a full symbol; d. $12$ girls.
All the numbers are multiples of $6$, so one symbol can represent $6$ dogs. Village B has $36$ dogs, so it needs $36\div6=6$ symbols. Villages B and D together have $36+48=84$ dogs. The other four villages have $18+12+18+24=72$ dogs. Since $84>72$, Kamini is right.
a. Use one symbol for $6$ dogs; b. $6$ symbols; c. Yes.
With scale $1$ unit length $=5$ students, the bar heights are Playing $45\div5=9$, Reading story books $30\div5=6$, Watching TV $20\div5=4$, Listening to music $10\div5=2$, and Painting $15\div5=3$ units. Excluding Playing, Reading story books has the greatest count.
Reading story books.
Reading the bar graph gives Wednesday plus Thursday as $70$ saplings and the whole-week total as $310$ saplings. The tallest bar is Saturday and the shortest bar is Wednesday. Possible reasons include rainy weather or different numbers of students being present on different days; these can be checked by comparing with attendance and weather records.
a. $70$; b. $310$; c. greatest on Saturday and least on Wednesday.
The table lists 2006: $1400$, 2010: $1700$, 2014: $2200$, 2018: $3000$, and 2022: $3700$. The bars should be redrawn to these values on the given scale.
The bars for 2006, 2010, 2014, and 2018 are incorrect and should be corrected to match the table.
Heights are measured upward from the ground, so vertical bars make the comparison of heights intuitive. A horizontal bar graph could also be used, but vertical bars are more natural for height data.
A vertical bar graph is suitable.
River length is a horizontal feature, so horizontal bars make it easy to compare lengths visually. The exact table depends on the river-length data collected for each continent.
A horizontal bar graph is suitable.