CBSE · NCERT · Class 8 Maths · Chapter 9

NCERT Solutions: Class 8 Maths Chapter 9 - Mensuration

6 textbook Q&A6 verifiedFree Content

Chapter-wise NCERT intext questions and exercise answers for Mensuration, grounded in the official textbook.

Questions are taken verbatim from the NCERT textbook; answers were grounded against the chapter's content during generation. Items needing review are marked.
Sections in this chapter
Exercises 6
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1Exercises6 questions
Q.1Find the area of a trapezium whose parallel sides are 8 cm and 12 cm and height is 5 cm.v
Solution

Area $=\dfrac12(a+b)h=\dfrac12(8+12)5=50$.

Answer:

$50\text{ cm}^2$.

Q.2Find the area of a rhombus whose diagonals are 16 cm and 12 cm.v
Solution

Area $=\dfrac12 d_1d_2=\dfrac12\times16\times12=96$.

Answer:

$96\text{ cm}^2$.

Q.3Find the area of a polygon by splitting it into triangles and rectangles.v
Solution

The chapter method is decomposition into rectangles, triangles or trapezia.

Answer:

Split the polygon into known shapes, find each area separately, and add them.

Q.4Find the curved surface area of a cylinder of radius 7 cm and height 10 cm.v
Solution

Curved surface area $=2\pi rh=2\times\dfrac{22}{7}\times7\times10=440$.

Answer:

$440\text{ cm}^2$ using $\pi=\dfrac{22}{7}$.

Q.5Find the volume of a cuboid of length 12 cm, breadth 8 cm and height 5 cm.v
Solution

Volume $=lbh=12\times8\times5=480$.

Answer:

$480\text{ cm}^3$.

Q.6Find the volume of a cylinder of radius 7 cm and height 10 cm.v
Solution

Volume $=\pi r^2h=\dfrac{22}{7}\times49\times10=1540$.

Answer:

$1540\text{ cm}^3$ using $\pi=\dfrac{22}{7}$.