Ch 1Numbers | Brain Grain (Term 1)
5-Mark Questions
The password to access my ATM card includes the digits 9, 4, 6, and 8. It is the smallest 4 digit even number. Find the password of my ATM card.
Given digits are 9, 4, 6, and 8. The smallest number with these digits is 4689 Given that it is an even number. It may be 4698. So password of the ATM card is 4698.
₹ 62,500 was equally distributed as a New Year bonus for 25 employees of a company. How much did each receive?
Total amount = Rs 62500 Total number of employees = 25 Bonus amount received by each employee = Rs 62500 ÷ 25 = RS \(\frac{62500}{25}\) = Rs 2500
2-Mark Questions
How many ten thousands are there in the smallest 6 digit number?
Smallest 6 digit number = 1,00,000 = \(\frac{100000}{10000}\) = 10 1 Lakh = 10 Ten Thousands
Using the digits 5, 2, 0, 7, 3 forms the largest 5 digit number and the smallest 5 digit number.
Given digits = 5, 2, 0, 7, 3 Largest 5 digit number – 75320 Smallest 5 digit number – 20357
Observe the commas and write down the place value of 7. (i) 56,74,56,345 (ii) 567,456,345
(i) 70,00,000 (ii) 7,000,000
1-Mark Questions (MCQ)
1 billion is equal to
(a) 100 crore
Ch 2Introduction to Algebra
5-Mark Questions
If ‘u’ is an even number, how would you represent (i) the next even number? (ii) the previous even number?
(i) Difference between two even numbers = 2 Given that ‘u’ is an even number. Next, the even number is u + 2. (ii) Previous even number is u – 2. Objective Type Questions
Find in the blanks. (i) The algebraic statement of ‘f’ decreased by 5 is _______ (ii) The algebraic statement of ‘s’ divided by 5 is _______ (iii) The verbal statement of ‘2m – 10’ is _______ (iv) If A’s age is ‘n’ years now, 7 years ago A’s age was ______ (v) If ‘p – 5’ gives 12 then ‘p’ is ______
(i) f – 5 (ii) \(\frac { s }{ 5 }\) (iii) 10 less than 2 times m (or) Take away 10 from the product of 2 and m (iv) n – 7 (v) 17 Hint: p – 5 = 12 ⇒ n = 12 + 5 = 17
2-Mark Questions
Use a variable to write the rule, which gives the number of ice candy sticks required to make the following patterns.
(a) No of ice candy sticks used = 3 × n = 3n (b) No of ice candy sticks used = 4 × n = 4n
The teacher forms groups of five students in a class. How many students will be there in ‘p’ groups?
No of students in a group = 5 No of students in ‘p’ groups = 5 × p = 5p
Arivazhagan is 30 years younger than his father. Write Arivazhagan’s age in terms of his father’s age.
Let Arivazhagan’s father’s age be x years According to the problem, Arivazhagan’s age = (x – 30) years
1-Mark Questions (MCQ)
Variable means that it
(c) can take different values
Ch 3Ratio and Proportion
5-Mark Questions
Find the simplified form of the following ratios. (i) 15 : 20 (ii) 32 : 24 (iii) 7 : 15 (iv) 12 : 27 (v) 75 : 100
(i) 15 : 20 = \(\frac{15}{20}\) = \(\frac{3}{4}\) = 3 : 4(ii) 32 : 24 = \(\frac{32}{24}\) = \(\frac{4}{3}\) = 4 : 3 (iii) 7 : 15 (iv) 12 : 27 = \(\frac{12}{27}\) = \(\frac{4}{9}\) = 4 : 9 (v) 75 : 100 = \(\frac{75}{100}\) = \(\frac{3}{4}\) = 3 : 4
Out of 50 students in a class, 30 are boys. Find the ratio of (i) number of boys to the number of girls. (ii) the number of girls to the total number of students. (iii) the number of boys to the total number of students.
Total no of students = 50 No of boys = 30 No of girls = 50 – 30 = 20 (i) Ratio of boys to girls = 30 : 20 = \(\frac{30}{20}\) = \(\frac{3}{2}\) = 3 : 2 (ii) Ratio of girls to the total number of students = 20 : 50 = \(\frac{20}{50}\) = \(\frac{2}{5}\) = 2 : 5 (iii) Ratio of boys to the total no of students = 30 : 50 = \(\frac{30}{50}\) = \(\frac{3}{5}\) = 3 : 5Objective Type Questions
2-Mark Questions
Akilan walks 10 km in an hour while Selvi walks 6 km in an hour. Find the simplest ratio of the distance covered by Akilan to that of Selvi.
Ratio of the distance covered by Akilan to that of Selvi = 10 km : 6 km = \(\frac{10}{6}\) = \(\frac{5}{3}\) = 5 : 3
The cost of parking a bicycle is Rs 5 and the cost of parking a scooter is Rs 15. Find the simplest ratio of the parking cost of a bicycle to that of a scooter.
Ratio of the parking cost of a bicycle to that of a scooter = Rs 5 : Rs 15 = \(\frac{5}{15}\) = \(\frac{1}{3}\) = 1 : 3
Team A wins 26 matches out of 52 matches. Team B wins three fourth of 52 matches played. Which team has a better winning record?
Team A = \(\frac{26}{52}\) = \(\frac{1}{2}\) Team B = \(\frac{3}{4}\) × 52 = 39 Team B has a better winning record.
1-Mark Questions (MCQ)
The ratio of ₹ 1 to 20 paise is _____
(d) 5 : 1 Hint: ₹ 1 = 100 paise
Ch 4Geometry | Brain Grain (Term 1)
5-Mark Questions
Construct a line segment using a ruler and compass. (1) \(\overline { AB } \) = 7.5 cm (2) \(\overline { CD } \) = 3.6 cm (3) \(\overline { QR } \) = 10 cm
(1)(i) Draw line 1 and mark a point A on it. (ii) Measure 7.5 cm using a compass, placing the pointer at ‘O’ and the pencil pointer at 7.5 cm. (iii) Place the pointer of the compass at A then draw a small arc on the line 1 with the pencil pointer. It cuts line 1 at a point and name that point as B. (iv) Now \(\overline { AB } \) is the required line segment of length 7.5 cm.(2)(i) Draw a line 1 and mark a point C on it. (ii) Measure 3.6 cm using a compass, placing the pointer at O and the pencil pointer at 3.6 cm. …
Think and write an object having (i) Parallel lines (1) ……….. (2) ………. (3) ……….. (ii) Perpendicular lines (1) ……… (2) ……… (3) ……….. (iii) Intersecting lines (1) ……….. (2) ………. (3) ……….
(i) Legs of the table, railway tracks, edges of the scale (ii) Adjacent sides of a Board, Crossbars of windows, Adjacent sides of the textbook (iii) Crossbars of windows, Ladder, blades of a scissor.
2-Mark Questions
Draw and label each of the angles. (i) ∠NAS = 90°n (ii) ∠BIG = 35° (iii) ∠SMC = 145°
Draw any line and mark any 3 points that are collinear.
Draw any line and mark any 4 points that are not collinear.
1-Mark Questions (MCQ)
A line is denoted as __________
(c) \(\overleftrightarrow {AB} \)
Ch 5Statistics
5-Mark Questions
Yasmin of class VI was given a task to count the number of books which are biographies, in her school library. The information collected by her is represented as follows. Observe the pictograph and answer the following questions. (i) Which title has the maximum number of biographies? (ii) Which title has the minimum number of biographies? (iii) Which title has exactly half the number of biographies as Novelists? (iv) How many biographies are there on the title of sportspersons? (v) What is the total number of biographies in the library?
(i) ‘The title Novelists’ have the maximum number of biographies (ii) ‘The title Scientists’ have a minimum number of biographies. (iii) ‘Sportspersons’ title has exactly half the number of biographies as Novelist. (iv) \((1 \times 20)+\frac{20}{4}=20+5=25\) biographies are there in the title sportsperson. (v) 8 × 20 = 160 biographies are there in the library.
2-Mark Questions
Viji threw a die 30 times and noted down the result each time as follows. Prepare a table on the numbers shown using Tally Marks. 1, 4, 3, 5, 5, 6, 6, 4, 3, 5, 4, 5, 6, 5, 2, 4, 2, 6, 5, 5, 6, 6, 4, 5, 6, 6, 5, 4, 1, 1
The following table shows the number of tourists who visited the places in the month of May. Draw a pictograph (Choose your own suitable scale)
Number of Tourists who visited the places in the month of May.
The heights (in centimeters) of 40 children are. Prepare a tally marks table.
1-Mark Questions (MCQ)
The plural form of ‘datum’ is ____
(c) data
Ch 6Information Processing | Brain Grain (Term 1)
5-Mark Questions
You have two red and two blue blocks. How many different towers can you build that are four blocks high using these blocks? List all the possibilities.
6 Possibilities, R – B – R – B R – R – B – B B – R – R – B B – R – B – R B – B – R – R R – B – B – R
2-Mark Questions
Suppose, you have two pairs of shorts, one is black and the other one is blue; three shirts which are white, blue and red. You again wish to make different combinations, but you always want to make sure that the shorts and shirt that you wear are of different colours. List and check how many combinations are possible now.
6 combinations are possible Black-White Black-Blue Black-Red Blue-White Blue-Blue Blue-Red
Ch 7Numbers | Brain Grain (Term 2)
5-Mark Questions
Find the prime factorisation of each number by factor tree method and division method. (i) 60 (ii) 128 (iii) 144 (iv) 198 (v) 420 (vi) 999
60 = 2 × 30 = 2 × 2 × 15 = 2 × 2 × 3 × 5128 = 2 × 2 × 2 × 2 × 2 ×2 × 2 128 = 2 × 64 = 2 × 2 × 32 = 2 × 2 × 2 × 16 = 2 × 2 × 2 × 2 × 8 128 = 2 × 2 × 2 × 2 × 2 × 4 = 2 × 2 × 2 × 2 × 2 × 2 × 2144 = 2 × 2 × 2 × 2 × 3 × 3 144 = 2 × 72 = 2 × 2 × 36 = 2 × 2 × 2 × 18 = 2 × 2 × 2 × 2 × 9 = 2 × 2 × 2 × 2 × 3 × 3198 = 2 × 3 × 3 × 11 198 = 2 × 99 = 2 × 3 × 33 = 2 × 3 × 3 × 11420 = 2 × 210 = 2 × 2 × 105 = 2 × 2 × 3 × 35 = 2 × 2 × 3 × 5 × 7999 = 3 × 333 = 3 × 3 × 111 = 3 × 3 × 3 × 37
Find the HCF of each set of numbers using the prime factorisation method. (i) 18, 24 (ii) 51, 85 (iii) 61, 76 (iv) 84, 120 (v) 27, 45, 81 (vi) 45, 55, 95
(i) 18, 24HCF = 2 × 3 = 6 (ii) 51, 85HCF = 17(iii) 61, 76 61 = 1 × 61 For 61, 76, the common factor is 1 HCF = 1 (iv) 84, 120HCF = 2 × 2 × 3 = 12 (v) 27, 45, 81HCF = 3 × 3 = 9 (vi) 45, 55, 95Factors of 55 = 5 × 11 Factors of 45 = 3 × 3 × 5 Factors of 95 = 5 × 19 HCF = 5
2-Mark Questions
Write the smallest and the biggest two-digit prime number.
Smallest two-digit prime number – 11 Biggest two-digit prime number – 97.
Write the smallest and the biggest three-digit composite number.
Smallest three-digit composite number – 100 Biggest three-digit composite number – 999
The digits of the prime number 13 can be reversed to get another prime number 31. Find if any such pair exists up to 100.
(17, 71), (37, 73) and (79, 97)
1-Mark Questions (MCQ)
The difference between two successive odd numbers is
(b) 2
Ch 8Measurements
5-Mark Questions
Convert into indicated units: (i) 10 l and 50 ml into ml (ii) 4 km and 300 m into m (iii) 300 mg into g
(i) 10 l and 50 ml = 10 × 1000 ml + 50 ml = (10000 + 50)ml = 10050 ml (ii) 4 km and 300 m = 4 × 1000 + 300 m = (4000 + 300) m = 4300 m (iii) 300 mg = \(\frac{300}{1000}\)g = 0.3 g
Convert into higher units: (i) 13000 mm (km, m, cm)
13000 mm = \(\frac{13000}{10}\) cm = 1300 cm = \(\frac{13000}{1000}\) m = 13000 mm = 13 m = \(\frac{13000}{1000000}\) km = 13000 mm = 0.013 km (ii) 8257 ml (kl, l) 8257 ml = \(\frac{8257}{1000}\) l = 8.257 l = 8257 ml = \(\frac{8257}{1000000}\) kl = 0.008257 kl
2-Mark Questions
9 m 4 cm is equal to …….. (i) 94 cm (ii) 904 cm (iii) 9.4 cm (iv) 0.94 cm
(ii) 904 cm
Every day 150 l of water is sprayed in the garden. Water sprayed in a week is …… (i) 700 l (ii) 1000 l (iii) 950 l (iv) 1050 l
(iv) 1050 l
Change the following into 12 hour format (i) 02:00 hours (ii) 08:45 hours (iii) 21:10 hours (iv) 11:20 hours (v) 00:00 hours
(i) 2 am (ii) 08:45 am (iii) 9:10 pm (iv) 11:20 am (v) 12 midrid
1-Mark Questions (MCQ)
1006 g is equal to ____
(a) 1 kg 6 g
Ch 9Bill, Profit and Loss
5-Mark Questions
A man buys a chair for ₹ 1500. He wants to sell it at a profit of ₹ 250 after making a discount of ₹ 100. What is the M.P of the chair?
CP = Rs 1,500 Profit = Rs 250 SP = CP + Profit = Rs 1,500 + Rs 250 = Rs 1,750 Discount = Rs 100 SP = MP – Discount MP = SP + Discount = Rs 1,750 + Rs 100 = Rs 1,850
Valavan bought 24 eggs for ₹ 96. Four of them were broken and also he had a loss of ₹ 36 on selling them. What is the selling price of one egg?
Cost of 24 eggs = Rs 96 Since 4 of the eggs were broken, the number of remaining eggs = 24 – 4 = 20 Since the loss is Rs 36 The selling price of 20 eggs SP = CP – Loss = Rs 96 – Rs 36 = Rs 60 ∴ Cost of 1 egg = Rs 60 / 20 = Rs. 3
2-Mark Questions
Prepare a bill for the following books of biographies purchased from Maruthu Book Store, Chidambaram on 12.04.2018 bearing the bill number 507. 10 copies of Subramanya Bharathiar @ Rs 55 each, 15 copies of Thiruvalluvar @ Rs 75 each, 12 copies of Veeramamunivar @ Rs 60 each, and 12 copies of ThiruviKa @ Rs 70 each.
Rani bought a set of bangles for ₹ 310. Her neighbour liked it the most. So Rani sold it to her for ₹ 325. Find the profit or loss to Rani.
CP = Rs 310 SP = Rs 325 Profit = SP – CP = Rs 325 – Rs 310 = Rs 15
Sugan bought a pair of jeans pant for Rs 750 not fit him. He sold it to his friend for Rs 710, Find the profit or loss to sugan.
CP = Rs 750 SP = Rs 710 CP > SP Loss = CP – SP = Rs 750 – Rs 710 = Rs 40
1-Mark Questions (MCQ)
Discount is subtracted from ______ to get S.P.
(a) M.P
Ch 10Geometry | Brain Grain (Term 2)
5-Mark Questions
Can a triangle be formed with the following sides? If yes, name the type of triangle. (i) 8 cm, 6 cm, 4 cm (ii) 10 cm, 8 cm, 5 cm (iii) 6.2 cm, 1.3 cm, 3.5 cm (iv) 6 cm, 6 cm, 4 cm (v) 3.5 cm, 3.5 cm, 3.5 cm (vi) 9 cm, 4 cm, 5 cm
(i) Sum of two smaller sides of the triangle = 6 + 4 = 10 cm > 8 cm It is greater than the third side. So, a triangle can be formed a scalene triangle. (ii) Sum of two smaller sides of the triangle = 8 + 5 = 13 cm > 10 cm It is greater than the third side. So, a triangle can be formed a scalene triangle. (iii) Sum of two smaller sides of the triangle = 1.3 + 3.5 = 4.8 cm < 6.2 cm It is not greater than the third side. So, a triangle cannot be formed. (iv) Two sides are equal. So, a triangle can be formed. Isosceles triangle. (v) Three sides are equal. …
Can a triangle be formed with the following angles? If yes, name the type of triangle. (i) 60°, 60°, 60° (ii) 60°, 40°, 42° (iii) 90°, 55°, 35° (iv) 60°, 90°, 90° (v) 70°, 60°, 50° (vi) 100°, 50°, 30°
(i) 60°, 60°, 60° Sum of the angles = 60°+ 60°+ 60° = 180° A triangle can be formed as an acute-angled triangle. (ii) 60°, 40°, 42° Sum of the angles = 60° + 40° + 42° = 142° A triangle cannot be formed. (iii) 90°, 50°, 35° Sum of the angles = 90° + 55° + 35° = 180° A triangle can be formed Right-angled triangle. (iv) 60°, 90°, 90° No, a triangle can not be formed. A triangle cannot have more than one right angle. (v) 70°, 60°, 50° Sum of the angles = 70° + 60° + 50° = 180° A triangle can be formed as an acute-angled triangle. …
2-Mark Questions
I am a closed figure with each of my three angles is 60°. Who am I?
Equilateral triangle
The diagram shows a square ABCD. If the line segment joins A and C, then mention the type of triangle so formed.
Isosceles right-angled triangles
Draw a line segment AB of length 6 cm. At each end of this line segment AB, draw a line perpendicular to the line segment AB. Are these lines parallel?
yes, they are parallel Challenge Problems
1-Mark Questions (MCQ)
In ΔABC, name the
(a) \(\overline{\mathrm{AB}}, \overline{\mathrm{BC}}, \overline{\mathrm{CA}}\) (b) ∠ABC, ∠BCA, ∠CAB or ∠A, ∠B, ∠C (c) A, B, C
Ch 11Information Processing | Brain Grain (Term 2)
5-Mark Questions
A football team gains 3 and 4 points for successive 2 days and loses 5 points on the third day. Find the total points scored by the team and also represent this in tree diagram.
2-Mark Questions
Convert the following numerical expressions into Tree diagrams (i) 8 + (6 × 2) (ii) 9 – (2 × 3) (iii) (3 × 5) – (4 – 2) (iv) [(2 × 4) + 2] × (8 – 2)] (v) [(6 + 4) × 7] – [2 × (10 – 5)] (vi) [(4 × 3) – 2] + [8 × (5 – 3)]
Convert the following algebraic expressions into tree diagrams. (i) 10 v (ii) 3a – b (iii) 5x + y (iv) 20t × p (v) 2(a + b) (vi) (x × y) – (y × z) (vii) 4x + 5y (viii) (Im – n) ÷ (pq + r)
Convert ti e following questions into tree diagrams: (i) The number of people who visited a library in the last 5 months were 1210, 2100, 2550, 3160 and 3310. Draw the tree diagram of the total number of people who had used the library for the 5 months. (ii) Ram had a bank deposit of Rs. 7,55,250 and he had withdrawn Rs. 5,34,500 for educational purpose. Find the amount left in his account. Draw a tree diagram for this. (iii) In a cycle factory, 1,600 bicycles were manufactured on a day. Draw tree diagram to find the number of bicycle produced in 20 days. (iv) A company with 30 employees decided to distribute Rs. 90, 000 as a special bonus equally among its employees. Draw tree diagram to show how much will each receive?
Ch 12Fractions
5-Mark Questions
Multiply the following: (i) \(\frac{2}{3}\) × 6 (ii) 8\(\frac{1}{3}\) × 5 (iii) \(\frac{3}{8}\) × \(\frac{4}{5}\) (iv) 3\(\frac{5}{7}\) × 1\(\frac{1}{13}\)
(i) \(\frac{2}{3}\) × 6 = 4 (ii) 8\(\frac{1}{3}\) × 5 = \(\frac{25}{3}\) × 5 = \(\frac{125}{3}\) = 41\(\frac{2}{3}\) (iii) \(\frac{3}{8}\) × \(\frac{4}{5}\) = \(\frac{12}{40}\) = \(\frac{3}{10}\) (iv) 3\(\frac{5}{7}\) × 1\(\frac{1}{13}\) = \(\frac{26}{7}\) × \(\frac{14}{13}\) = \(\frac{4}{1}\) = 4
By using the following clues, find who am I? (i) Each of my numerator and denominator is a single-digit number. (ii) The sum of my numerator and denominator is a multiple of 3. (iii) The product of my numerator and denominator is a multiple of 4.
The numerator may be any one of!, 2, 3,4, 5, 6, 7, 8, 9 and the denominator may be any one of 1, 2,3,4, 5,6, 7,8,9. Sum of numerator and denominator is a multiple of 3. ∴ Possible proper fractions are \(\frac{1}{2}, \frac{1}{5}, \frac{1}{8}, \frac{2}{4}, \frac{2}{7}, \frac{3}{6}, \frac{3}{9}, \frac{4}{5}, \frac{4}{8}, \frac{5}{7}, \frac{6}{9}\) Also given the product of numerator and denominator is a multiple of 4. ∴ Possible fractions are \(\frac{1}{8}, \frac{2}{4}, \frac{4}{5}, \frac{4}{8}\)
2-Mark Questions
Answer the following: (i) Find the sum of \(\frac{1}{7}\) and \(\frac{3}{9}\). (ii) What is the total of 3\(\frac{1}{3}\) and 4\(\frac{1}{6}\)? (iii) Simplify: 1\(\frac{3}{5}\)+5\(\frac{4}{7}\). (iv) Find the difference between \(\frac{8}{9}\) and \(\frac{2}{7}\) (v) Subtract: 1\(\frac{3}{5}\) from 2\(\frac{1}{3}\). (vi) Simplify: 7\(\frac{2}{7}\) – 3\(\frac{4}{21}\)
(i) \(\frac{1}{7}\) + \(\frac{3}{9}\) = \(\frac{9+21}{63}\) = \(\frac{30}{63}\) = \(\frac{10}{21}\)
Convert mixed fractions into improper fractions and vice versa: (i) 3\(\frac{7}{18}\) (ii) \(\frac{99}{7}\) (iii) \(\frac{47}{6}\) (iv) 12\(\frac{1}{9}\)
(i) 3\(\frac{7}{18}\) = \(\frac{61}{18}\) (ii) \(\frac{99}{7}\) = 14\(\frac{1}{7}\) (iii) \(\frac{47}{6}\) = 7\(\frac{5}{6}\) (iv) 12\(\frac{1}{9}\) = \(\frac{109}{9}\)
Divide the following (i) \(\frac{3}{7}\) ÷ 4 (ii) \(\frac{4}{3}\) ÷ \(\frac{5}{9}\) (iii) 4\(\frac{1}{5}\) ÷ 3\(\frac{3}{4}\) (iv) 9\(\frac{2}{3}\) ÷ 1\(\frac{2}{3}\)
(i) \(\frac{3}{7}\) ÷ 4 = \(\frac{3}{7}\) × \(\frac{1}{4}\) = \(\frac{3}{28}\) (ii) \(\frac{4}{3}\) ÷ \(\frac{5}{9}\) = \(\frac{4}{3}\) × \(\frac{9}{5}\) = \(\frac{12}{5}\) = 2\(\frac{2}{5}\)
1-Mark Questions (MCQ)
Which of the following statement is incorrect?
(d) \(\frac{10}{11}\) > \(\frac{9}{10}\)
Ch 13Integers
5-Mark Questions
Find the opposite of the following numbers. (i) 44 (ii) -19 (iii) 0 (iv) -312 (v) 789
(i) Opposite of 44 is – 44 (ii) Opposite of-19 is + 19 or 19 (iii) Opposite of 0 is 0 (iv) Opposite of-312 is + 312 or 312 (v) Opposite of 789 is – 789.
From the following number lines, identify the correct and the wrong representations with reason.
(i) Wrong, Integers are not continuously marked (ii) Correct, Integers are correctly marked. (iii) Wrong, Integer -2 is marked wrongly. (iv) Correct, Integers are marked at equal distance. (v) Wrong, negative integers marked wrongly.
2-Mark Questions
Mark the numbers 4, -3, 6, -1 and -5 on the number line.
On the number line, which number is (i) 4 units to the right of -7? (ii) 5 units to the left of 3?
(i) -3 (ii) -2
If 15 km east of a place is denoted as +15 km, What is the integer that represents 15 km west of it?
Opposite of east is west. ∴ If 15 km east is + 15 km, then 15 km west is – 15 km.
1-Mark Questions (MCQ)
There are ……… positive integers from -5 to 6.
(c) 7
Ch 14Perimeter and Area
5-Mark Questions
Find the perimeter and the area of the rectangle whose length is 6 m and breadth is 4m?
l = 6 m, b = 4 m Perimeter of the rectangle = 2 (l + b) units = 2 (6 + 4) m = 2 (10) m = 20 m Area of the rectangle = l × b sq units = 4 × 6 m² = 24 m²
Find the perimeter and area of a square whose side is 8 cm.
a = 8 cm The perimeter of a square = 4a units = 4 × 8 cm = 32 cm Area of the square = a × a sq units = 8 × 8 cm² = 64 cm²
2-Mark Questions
From one vertex of an equilateral triangle with a side of 40 cm, an equilateral triangle with 6 cm side is removed. What is the perimeter of the remaining portion? The perimeter of the remaining portion
= (40 + 34 + 6 + 34) cm = 114 cm
1-Mark Questions (MCQ)
If two identical rectangles of perimeter 30 cm are joined together, then the perimeter of the new shape will be
(b) less than 60 cm
Ch 15Symmetry
2-Mark Questions
Using the given horizontal line/ vertical line as a line of symmetry, complete each alphabet to discover the hidden word.
(i) DECODE (ii) KICK (iii) BED (iv) WAY (v) MATY (vi) TOMATO
Draw and answer the following. (i) A triangle which has no line of symmetry. (ii) A triangle which has only one line of symmetry (iii) A triangle which has three lines of symmetry.
(i) Scalene triangle (ii) Isosceles triangle (iii) Equilateral triangle
The three-digit number 101 has rotational and reflection symmetry. Give five more examples of three-digit numbers that have both rotational and reflection symmetry
The digits 0, 1, 8 have rotational and reflection symmetry. ∴ The three digits numbers 181, 111, 808, 818, 888 have both rotational and reflection symmetry.
1-Mark Questions (MCQ)
Which of the following letter does not have a line of symmetry? Hint: A, T, U have one line of symmetry
(b) P
Ch 16Information Processing | Brain Grain (Term 3)
5-Mark Questions
Find next three numbers in the following number patterns. (i) 50, 51, 53, 56, 60…… (ii) 77, 69, 61, 53, …… (iii) 10, 20, 40, 80,… (iv) \(\frac{21}{33}\), \(\frac{321}{444}\), \(\frac{4321}{555}\)
i) The pattern generating these numbers is 50, 50 + 1, 51 + 2, 53 + 3, 56 + 4, 60 + 5, 65 + 6, 71 + 7, ∴ 50, 51, 53, 56, 60, 65, 71, 78, …… ∴ The next three numbers will be 65, 71, 78 ii) The pattern generating these numbers is 77, 77 – 8, 69 – 8, 61 – 8, 53 – 8, 45 – 8, 37 – 8, 29 77, 69, 61, 53, 45, 37, 29, 21, ∴ The next three numbers will be 45, 37, 29. iii) The pattern generating these numbers is 10, 10 + 10, 20 + 20, 40 + 40, 80 + 80, 160 + 160, 320 + 320,…. 10, 20, 40, 80, 160, 320, 640,…. ∴ The next three numbers will be 160, 320, 640. …
Find the HCF of the following pair of numbers by Euclid’s game (i) 25 and 35 (ii) 36 and 12 (iii) 15 and 29
(i) HCF of (25, 35 – 25) 25 = 5 × 5 10 = 2 × 5 HCF of (25, 10) = 5 (ii) HCF of (36, 36 – 12) 36 = 2 × 2 × 3 × 3 24 = 2 × 2 × 2 × 3 HCF of (36, 24) = 2 × 2 × 3 = 12 (iii) HCF of (15, 29 -15) 15 = 3 × 5 × 1 14 = 2 × 7 × 1 HCF of (15, 14) = 1
2-Mark Questions
Arrange the name of your classmates alphabetically.
Follow and execute the instructions given below. (i) Write the number 10 in the place common to the three figures (ii) Write the number 5 in the place common for square and circle only. (iii) Write the number 7 in the place common for triangle and circle only. (iv) Write the number 2 in the place common for triangle and square only. (v) Write the numbers 12, 14, and 8 only in square, circle, and triangle respectively.
Assign the number for English alphabets as 1 for A, 2 for B upto 26 for Z. Find the meaning of
GOOD MORNING
1-Mark Questions (MCQ)
The next term in the sequence 15, 17, 20, 22, 25, … is Hint: Add 2 and 3 alternatively
(c) 27
Frequently asked questions
- The password to access my ATM card includes the digits 9, 4, 6, and 8. It is the smallest 4 digit even number. Find the password of my ATM card.
- Given digits are 9, 4, 6, and 8. The smallest number with these digits is 4689 Given that it is an even number. It may be 4698. So password of the ATM card is 4698.
- ₹ 62,500 was equally distributed as a New Year bonus for 25 employees of a company. How much did each receive?
- Total amount = Rs 62500 Total number of employees = 25 Bonus amount received by each employee = Rs 62500 ÷ 25 = RS \(\frac{62500}{25}\) = Rs 2500
- How many ten thousands are there in the smallest 6 digit number?
- Smallest 6 digit number = 1,00,000 = \(\frac{100000}{10000}\) = 10 1 Lakh = 10 Ten Thousands
- Using the digits 5, 2, 0, 7, 3 forms the largest 5 digit number and the smallest 5 digit number.
- Given digits = 5, 2, 0, 7, 3 Largest 5 digit number – 75320 Smallest 5 digit number – 20357
These important questions are selected from the Samacheer Kalvi Class 6 Maths textbook book-back exercises to help you revise the most useful questions. Mark weightage (5/2/1) follows the usual exam pattern and may vary by exam — always check your latest syllabus and question pattern. Open each chapter for the complete set of questions and answers.