Samacheer Class 6 Maths Numbers Book Back Answers & Solutions

Q: How many ten thousands are there in the smallest 6 digit number?

Smallest 6 digit number = 1,00,000 = \frac{100000}{10000} = 10 1 Lakh = 10 Ten Thousands

Q: The number of employees in the Indian Railways is about 10 lakh. Write this in the International System of numeration.

1,000,000 (One Million) Objective Type Questions

Your Progress - Chapter 10% complete

1Book Back Questions62 questions

Q.1Fill in the blanks. The smallest 7 digit number is _______ The largest 8 digit number is _______ The place value of 5 in 7005380 is ________ The expanded form of the number 76,70,905 is _______v

Solution

10,00,000
9,99,99,999
5 × 1000 = 5000
7 × 10,00,000 + 6 × 1,00,000 + 7 × 10,000 + 0 + 9 × 100 + 0 + 5 × 1
(or)
70,00,000 + 6,00,000 + 70,000 + 900 + 5
Samacheer Kalvi 6th Maths Guide Term 1 Chapter 1 Set Language Ex 1.1

Answer:

Q.2Say True or False. In the Indian System of Numeration, the number 67999037 is written as 6,79,99,037 The successor of a one-digit number is always a one-digit number 9 + 1 = 10 The predecessor of a 3-digit number is always a 3 or 4 digit number 100 – 1 = 99 88888 = 8 × 10000 + 8 × 100 + 8 × 10 + 8 × 1v

Solution

True
False
False
False

Answer:

True
False
False
False

Q.4How many ten thousands are there in the smallest 6 digit number?v

Solution

Smallest 6 digit number = 1,00,000
= \(\frac{100000}{10000}\) = 10
1 Lakh = 10 Ten Thousands

Answer:

Smallest 6 digit number = 1,00,000
= \(\frac{100000}{10000}\) = 10
1 Lakh = 10 Ten Thousands

Q.5Using the digits 5, 2, 0, 7, 3 forms the largest 5 digit number and the smallest 5 digit number.v

Solution

Given digits = 5, 2, 0, 7, 3
Largest 5 digit number – 75320
Smallest 5 digit number – 20357

Answer:

Given digits = 5, 2, 0, 7, 3
Largest 5 digit number – 75320
Smallest 5 digit number – 20357

Q.6Observe the commas and write down the place value of 7. (i) 56,74,56,345 (ii) 567,456,345v

Solution

(i) 70,00,000
(ii) 7,000,000
Samacheer Kalvi 6th Maths Guide Term 1 Chapter 1 Set Language Ex 1.1

Answer:

(i) 70,00,000
(ii) 7,000,000
Samacheer Kalvi 6th Maths Guide Term 1 Chapter 1 Set Language Ex 1.1

Q.7Write the following numbers in the International System by using commas. 347056 7345671 634567105 1234567890v

Solution

347,056
7,345,671
634,567,105
1,234,567,890

Answer:

347,056
7,345,671
634,567,105
1,234,567,890

Q.8Write the largest six-digit number and put commas in the Indian and the International Systems.v

Solution

Largest 6 digit number = 9,99,999
Indian System: 9,99,999 (Nine Lakh Ninety-Nine Thousand Nine Hundred Ninety-Nine)
International System: 999,999 (Nine Hundred Ninety-Nine Thousand, Nine Hundred Ninety-Nine)
Samacheer Kalvi 6th Maths Guide Term 1 Chapter 1 Set Language Ex 1.1

Answer:

Q.9Write the number names of the following numerals in the Indian System. (i) 75,32,105 (ii) 9,75,63,453v

Solution

(i) Seventy-five lakh thirty-two thousand one hundred five.
(ii) Nine crore seventy-five lakh sixty-three thousand four hundred fifty-three.

Answer:

(i) Seventy-five lakh thirty-two thousand one hundred five.
(ii) Nine crore seventy-five lakh sixty-three thousand four hundred fifty-three.

Q.10Write the number of names in words using the International System. 345,678 8,343,710 103,456,789v

Solution

Three hundred forty-five thousand six hundred seventy-eight.
Eight million three hundred forty-three thousand seven hundred ten.
One hundred three million four hundred fifty-six thousand seven hundred eighty-nine.
Samacheer Kalvi 6th Maths Guide Term 1 Chapter 1 Set Language Ex 1.1

Answer:

Q.11Write the number name in numerals. Two crores thirty lakhs fifty-one thousand nine hundred eighty. Sixty-six million three hundred forty-five thousand twenty-seven. Seven hundred eighty-nine million, two hundred thirteen thousand four hundred fifty-six.v

Solution

2,30,51,980
66,345,027
789,213,456

Answer:

2,30,51,980
66,345,027
789,213,456

Q.12Tamil Nadu has about twenty-six thousand three hundred forty-five square kilometres of Forest land. Write the number mentioned in the statement in the Indian System.v

Solution

26,345

Answer:

26,345

Q.13The number of employees in the Indian Railways is about 10 lakh. Write this in the International System of numeration.v

Solution

1,000,000 (One Million)
Samacheer Kalvi 6th Maths Guide Term 1 Chapter 1 Set Language Ex 1.1
Objective Type Questions

Answer:

1,000,000 (One Million)
Samacheer Kalvi 6th Maths Guide Term 1 Chapter 1 Set Language Ex 1.1
Objective Type Questions

Q.141 billion is equal tov

A. 100 crore
B. 100 million
C. 100 lakh
D. 10000 lakh

Solution

(a) 100 crore

Answer:

(a) 100 crore

Q.15The successor of 10 million isv

A. 1000001
B. 10000001
C. 9999999
D. 100001

Solution

(b) 10000001

Answer:

(b) 10000001

Q.16The difference between successor and predecessor of 99999 isv

A. 90000
B. 1
C. 2
D. 99001

Solution

Answer:

Q.17The expanded form of the number 6,70,905 isv

A. 6 × 10000 + 7 × 1000 + 9 × 100 + 5 × 1
B. 6 × 10000 + 7 × 1000 + 0 × 100 + 9 × 100 + 0 × 10 + 5 × 1
C. 6 × 1000000 + 7 × 10000 + 0 × 1000 + 9 × 100 + 0 × 10 + 5 × 1
D. 6 × 100000 + 7 × 10000 + 0 × 1000 + 9 × 100 + 0 × 10 + 5 × 1

Solution

(d) 6 × 100000 + 7 × 10000 + 0 × 1000 + 9 × 100 + 0 × 10 + 5 × 1
Posted in Class 6 on January 19, 2025 January 20, 2025
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Answer:

Q.1Fill in the blanks with > or < or =. 48792 ………. 48972 1248654 ……… 1246854 658794 ……… 658794v

Solution

<
>
=
Samacheer Kalvi 6th Maths Guide Term 1 Chapter 1 Set Language Ex 1.2

Answer:

<
>
=
Samacheer Kalvi 6th Maths Guide Term 1 Chapter 1 Set Language Ex 1.2

Q.2Say True or False. The difference between the smallest number of seven digits and the largest number of six digits is 10. The largest 4 digit number formed by the digits 8, 6, 0, 9 using each digit only once is 9086 The total number of 4 digit number is 9000v

Solution

False
Hint: 1000000 – 999999 = 1
False
Hint: 9999 – 999 = 9000
True

Answer:

False
Hint: 1000000 – 999999 = 1
False
Hint: 9999 – 999 = 9000
True

Q.3Of the numbers 1386787215, 137698890, 86720560, which one is the largest? Which one is the smallest?v

Solution

We know that the number with more digits is greater.
The greatest number is 1386787215
The smallest number is 86720560
Samacheer Kalvi 6th Maths Guide Term 1 Chapter 1 Set Language Ex 1.2

Answer:

We know that the number with more digits is greater.
The greatest number is 1386787215
The smallest number is 86720560
Samacheer Kalvi 6th Maths Guide Term 1 Chapter 1 Set Language Ex 1.2

Q.4Arrange the following numbers in the descending order: 128435, 10835, 21354, 6348, 25840v

Solution

128435 > 25840 > 21354 > 10835 > 6348

Answer:

128435 > 25840 > 21354 > 10835 > 6348

Q.5Write any eight-digit number with 6 in ten lakhs place and 9 in ten-thousandth place.v

Solution

76594231
86493725

Answer:

76594231
86493725

Q.6Rajan writes a 3-digit number, using the digits 4, 7, and 9. What are the possible numbers he can write?v

Solution

974, 947, 479, 497, 749, 794
Samacheer Kalvi 6th Maths Guide Term 1 Chapter 1 Set Language Ex 1.2

Answer:

974, 947, 479, 497, 749, 794
Samacheer Kalvi 6th Maths Guide Term 1 Chapter 1 Set Language Ex 1.2

Q.7The password to access my ATM card includes the digits 9, 4, 6, and 8. It is the smallest 4 digit even number. Find the password of my ATM card.v

Solution

Given digits are 9, 4, 6, and 8.
The smallest number with these digits is 4689 Given that it is an even number.
It may be 4698.
So password of the ATM card is 4698.

Answer:

Given digits are 9, 4, 6, and 8.
The smallest number with these digits is 4689 Given that it is an even number.
It may be 4698.
So password of the ATM card is 4698.

Q.8Postal Index Number consists of six digits. The first three digits are 6, 3, and 1. Make the largest and the smallest Postal Index Number by using the digits 0, 3, and 6 each only once.v

Solution

Largest Postal Index Number = 631603
Smallest Postal Index Number = 631036
Samacheer Kalvi 6th Maths Guide Term 1 Chapter 1 Set Language Ex 1.2

Answer:

Largest Postal Index Number = 631603
Smallest Postal Index Number = 631036
Samacheer Kalvi 6th Maths Guide Term 1 Chapter 1 Set Language Ex 1.2

Q.10Which list of numbers is in order from the smallest to the largest?v

A. 1468, 1486, 1484
B. 2345, 2435, 2235
C. 134205, 134208, 154203
D. 383553, 383548, 383642

Solution

Answer:

Q.11The Arabian Sea has an area of 1491000 square miles. This area lies between which two numbers?v

A. 1489000 and 1492540
B. 1489000 and 1490540
C. 1490000 and 1490100
D. 1480000 and 1490000

Solution

(a) 1489000 and 1492540

Answer:

(a) 1489000 and 1492540

Q.12The chart below shows the number of newspapers sold as per the Indian Readership Survey in 2018. Which could be the missing number in the table? Samacheer Kalvi 6th Maths Guide Term 1 Chapter 1 Set Language Ex 1.2 2

Samacheer Kalvi 6th Maths Guide Term 1 Chapter 1 Set Language Ex 1.2 2

A. 8
B. 52
C. 77
D. 26

Solution

(d) 26
Samacheer Kalvi 6th Maths Guide Term 1 Chapter 1 Set Language Ex 1.2
Posted in Class 6 on January 19, 2025 January 20, 2025
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Answer:

Q.1Fill in the blanks. If Arulmozhi saves ₹ 12 per day then she saves ₹ ____ in 30 days. If a person ‘A’ earns ₹ 1800 in 12 days, then he earns ₹ ____ in a day. 45 ÷ (7 + 8) – 2 = _____v

Solution

12 × 30 = ₹ 360
\(\frac{1800}{12}=150\)
45 ÷ 15 – 2 = 3 – 2 = 1
Samacheer Kalvi 6th Maths Guide Term 1 Chapter 1 Set Language Ex 1.3

Answer:

12 × 30 = ₹ 360
\(\frac{1800}{12}=150\)
45 ÷ 15 – 2 = 3 – 2 = 1
Samacheer Kalvi 6th Maths Guide Term 1 Chapter 1 Set Language Ex 1.3

Q.2Say True or False 3 + 9 × 8 = 96 7 × 20 – 4 = 136 40 + (56 – 6) ÷ 2 = 45v

Solution

False
Hint: 3 + 9 × 8 = 3 + 72 = 75
True
Hint: 7 × 20 – 4 = 140 – 4 = 136
False
Hint: 40 + 50 ÷ 2 = 40 + 25 = 65

Answer:

False
Hint: 3 + 9 × 8 = 3 + 72 = 75
True
Hint: 7 × 20 – 4 = 140 – 4 = 136
False
Hint: 40 + 50 ÷ 2 = 40 + 25 = 65

Q.3The number of people who visited the Public Library for the past 5 months was 1200, 2000, 2450, 3060 and 3200 respectively. How many people visited the library in the last 5 months.v

Solution

People visited the library for past 5 months = 1200 + 2000 + 2450 + 3060 + 3200 = 11910
Total people visited = 11910
Samacheer Kalvi 6th Maths Guide Term 1 Chapter 1 Set Language Ex 1.3

Answer:

People visited the library for past 5 months = 1200 + 2000 + 2450 + 3060 + 3200 = 11910
Total people visited = 11910
Samacheer Kalvi 6th Maths Guide Term 1 Chapter 1 Set Language Ex 1.3

Q.4Cheran had a bank savings of ₹ 7,50,250. He withdrew ₹ 5,34,500 for educational purposes. Find the balance amount in his account.v

Solution

Bank Savings of Cheran = ₹ 7,50,250
Withdrew Amount = ₹ 5,34,500
Balance Amount = ₹ 2,15,750

Answer:

Bank Savings of Cheran = ₹ 7,50,250
Withdrew Amount = ₹ 5,34,500
Balance Amount = ₹ 2,15,750

Q.5In a cycle factory, 1560 bicycles were manufactured every day. Find the number of bicycles manufactured in 25 days.v

Solution

Bicycles manufactured in one day = 1560
Bicycles manufactured in 25 days = 1560 × 25
= 39,000 bicycles
Samacheer Kalvi 6th Maths Guide Term 1 Chapter 1 Set Language Ex 1.3

Answer:

Bicycles manufactured in one day = 1560
Bicycles manufactured in 25 days = 1560 × 25
= 39,000 bicycles
Samacheer Kalvi 6th Maths Guide Term 1 Chapter 1 Set Language Ex 1.3

Q.6₹ 62,500 was equally distributed as a New Year bonus for 25 employees of a company. How much did each receive?v

Solution

Total amount = Rs 62500
Total number of employees = 25
Bonus amount received by each employee = Rs 62500 ÷ 25
= RS \(\frac{62500}{25}\)
= Rs 2500

Answer:

Total amount = Rs 62500
Total number of employees = 25
Bonus amount received by each employee = Rs 62500 ÷ 25
= RS \(\frac{62500}{25}\)
= Rs 2500

Q.7Simplify the following numerical expressions: (i) (10 + 17) ÷ 3 (ii) 12 – [3 – {6 – (5 – 1)}] (iii) 100 + 8 ÷ 2 + {(3 × 2) -6 ÷ 2}v

Solution

(i) (10 + 17) ÷ 3
= 27 ÷ 3
= 9
Samacheer Kalvi 6th Maths Guide Term 1 Chapter 1 Set Language Ex 1.3
(ii) 12 – [3 – {6 – (5 – 1)}]
= 12 – [3 – (6 – 4)]
= 12 – [3 – 2]
= 12 – 1
= 11
(iii) 100 + 8 ÷ 2 + {(3 × 2) – 6 ÷ 2}
= 100 + 8 ÷ 2 + {6 – 3}
= 100 + 8 ÷ 2 + 3
= 100 + 4 + 3
= 107

Objective Type Questions

Answer:

Q.9The value of 24 ÷ {8 – (3 × 2)} is ______v

A. 0
B. 12
C. 3
D. 4

Solution

(b) 12
24 ÷ {8 – 3 × 2} = 24 ÷ {8 – 6} = 24 ÷ 2 = 12
Samacheer Kalvi 6th Maths Guide Term 1 Chapter 1 Set Language Ex 1.3

Answer:

(b) 12
24 ÷ {8 – 3 × 2} = 24 ÷ {8 – 6} = 24 ÷ 2 = 12
Samacheer Kalvi 6th Maths Guide Term 1 Chapter 1 Set Language Ex 1.3

Q.10Use BIDMAS and put the correct operator in the box. 2 ….. 6 – 12 ÷ (4 + 2) = 10v

A. +
B. –
C. ×
D. ÷

Solution

(c) ×
2 ….. 6 – 12 ÷ 6 = 10
⇒ 2 ….. 6 – 2 = 10
⇒ 2 × 6 – 2 = 10
Posted in Class 6 on January 19, 2025 January 20, 2025
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Answer:

Q.1Fill in the blanks. (i) The nearest 100 of 843 is _____ (ii) The nearest 1000 of 756 is ______ (iii) The nearest 10,000 of 85654 is ______v

Solution

(i) 800.
The digit in tens place is 4 < 5
(ii) 1000.
The digit in hundred places is 7 ≥ 5
(iii) 90,000.
The digit in a thousand places is 5 ≥ 5
Samacheer Kalvi 6th Maths Guide Term 1 Chapter 1 Set Language Ex 1.4

Answer:

Q.2Say True or False (i) 8567 is rounded off as 8600 to the nearest 10. (ii) 139 is rounded off as 100 to the nearest 100. (iii) 1,70,51,972 is rounded off as 1,70,00,000 to the nearest lakh.v

Solution

(i) False
Hint: In one’s place the digit is 7 ≥ 5. So 8580
(ii) True
Hint: In tens place, we have 3 < 5. So 100
(iii) False
Hint: In ten thousand places the digit is 5 ≥ 5. So 1,71,000,000

Answer:

(i) False
Hint: In one’s place the digit is 7 ≥ 5. So 8580
(ii) True
Hint: In tens place, we have 3 < 5. So 100
(iii) False
Hint: In ten thousand places the digit is 5 ≥ 5. So 1,71,000,000

Q.3Round off the following to the given nearest place. (i) 4,065; hundred (ii) 44,555; thousand (iii) 86,943; ten thousand (iv) 50,81,739; lakh (v) 33,75,98,482; ten crorev

Solution

(i) 4100
(ii) 45,000
(iii) 90,000
(iv) 51,00,000
(v) 30,00,00,000
Samacheer Kalvi 6th Maths Guide Term 1 Chapter 1 Set Language Ex 1.4

Answer:

(i) 4100
(ii) 45,000
(iii) 90,000
(iv) 51,00,000
(v) 30,00,00,000
Samacheer Kalvi 6th Maths Guide Term 1 Chapter 1 Set Language Ex 1.4

Q.4Estimate the sum of 157826 and 32469 rounded off to the nearest ten thousand.v

Solution

= 157826 + 32469
= 190295
When rounded off to nearest ten thousand = 1,90,000
Decimal numbers can be rounded to the nearest hundredth by observing the digit in the thousandths place.

Answer:

= 157826 + 32469
= 190295
When rounded off to nearest ten thousand = 1,90,000
Decimal numbers can be rounded to the nearest hundredth by observing the digit in the thousandths place.

Q.5Estimate by rounding off each number to the nearest hundred. (i) 8074 + 4178 (ii) 1768977 + 130589v

Solution

(i) 8074 + 4178 = 12,252
When rounded off to nearest hundred 12,300
(ii) 1768977 + 130589 = 18,99,566
When rounded off to nearest hundred = 18,99,600
Samacheer Kalvi 6th Maths Guide Term 1 Chapter 1 Set Language Ex 1.4

Answer:

Q.6The population of a city was 43,43,645 in the year 2001 and 46,81,087 in the year 2011. Estimate the increase in population by rounding off to the nearest thousands.v

Solution

Population in 2001 = 43,43,645
Population in 2011 = 46,81,087
Increase in population = 46,81,087 – 43,43,645 = 3,37,442
When rounded off to the nearest thousand = 3,37,000
Samacheer Kalvi 6th Maths Guide Term 1 Chapter 1 Set Language Ex 1.4
Objective Type Questions

Answer:

Q.7The number which on rounding off to the nearest thousand gives 11000 isv

A. 10345
B. 10855
C. 11799
D. 10056

Solution

(b) 10855

Answer:

(b) 10855

Q.8The estimation to the nearest hundredth of 76812 isv

A. 77000
B. 76000
C. 76800
D. 76900

Solution

(c) 76800
In tens place the digit is 1 < 5, So 76800
Samacheer Kalvi 6th Maths Guide Term 1 Chapter 1 Set Language Ex 1.4

Answer:

(c) 76800
In tens place the digit is 1 < 5, So 76800
Samacheer Kalvi 6th Maths Guide Term 1 Chapter 1 Set Language Ex 1.4

Q.9The number 9785764 is rounded off to the nearest lakh asv

A. 9800000
B. 9786000
C. 9795600
D. 9795000

Solution

(a) 9800000

Answer:

(a) 9800000

Q.10The estimated difference of 167826 and 2765 rounded off to the nearest thousand isv

A. 180000
B. 165000
C. 140000
D. 155000

Solution

(b) 165000
Samacheer Kalvi 6th Maths Guide Term 1 Chapter 1 Set Language Ex 1.4
Posted in Class 6 on January 3, 2025 January 4, 2025
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Answer:

Q.1Fill in the blanks. (i) The difference between the smallest natural number and the smallest whole number is ………. (ii) 17 × …….. = 34 × 17 (iii) When ……… is added to a number, it remains the same. (iv) Division by ………. is not defined. (v) Multiplication by ……… leaves a number unchanged.v

Solution

(i) 1
(ii) 34
(iii) Zero
(iv) 0
(v) 1
Samacheer Kalvi 6th Maths Guide Term 1 Chapter 1 Set Language Ex 1.5

Answer:

(i) 1
(ii) 34
(iii) Zero
(iv) 0
(v) 1
Samacheer Kalvi 6th Maths Guide Term 1 Chapter 1 Set Language Ex 1.5

Q.2Say True or False. 0 is the identity for multiplication of whole numbers. The Sum of two whole numbers is always less than their product. Both addition and multiplication are associative for whole numbers. Both addition and multiplication are commutative for whole numbers. Multiplication is distributive over addition for whole numbers.v

Solution

False
False
True
True
True
Samacheer Kalvi 6th Maths Guide Term 1 Chapter 1 Set Language Ex 1.5

Answer:

False
False
True
True
True
Samacheer Kalvi 6th Maths Guide Term 1 Chapter 1 Set Language Ex 1.5

Q.3Name the property being illustrated in each of the cases given below. 75 + 34 = 34 + 75 (12 × 4) × 8 = 12 × (4 × 8) 50 + 0 = 50 50 × 1 = 50 50 × 42 = 50 × 40 + 50 × 2v

Solution

Commutativity for addition
Associativity for multiplication
Zero is the additive identity
One is the multiplicative identity
Distributivity of multiplication over addition
Samacheer Kalvi 6th Maths Guide Term 1 Chapter 1 Set Language Ex 1.5

Answer:

Q.4Use the properties of whole numbers and simplify. (i) 50 × 102 (ii) 500 × 689 – 500 × 89 (iii) 4 × 132 × 25 (iv) 196 + 34 + 104v

Solution

(i) 50 × 102
= 50 × (100 + 2)
= (50 × 100) + (50 × 2)
= 5000 + 100 = 5100
(ii) 500 × 689 – 500 × 89
= 500 × (689 – 89)
= 344500 – 44500
= 300000
= 500 × (689 – 89)
= 500 × 600
= 3,00000
(iii) (4 × 132) × 25
= 4 × (132 × 25)
= (4 × 132) × 25
= 528 × 25
= 13200
= 4 × (132 × 25)
= 4 × 3300
= 13200
(iv) (196 + 34) + 104 = 196 + (34 + 104)
(196 + 34) + 104 = 230 + 104 = 334
196 + (34 + 104) = 196 + 138 = 334
Samacheer Kalvi 6th Maths Guide Term 1 Chapter 1 Set Language Ex 1.5
Objective Type Questions

Answer:

Q.5(53 + 49) × 0 isv

A. 102
B. 0
C. 1
D. 53 + 49 × 0

Solution

(b) 0

Answer:

(b) 0

Q.7The product of a non-zero whole number and its successor is alwaysv

A. an even number
B. an odd number
C. zero
D. none of these

Solution

(a) an even number

Answer:

(a) an even number

Q.8The whole number that does not have a predecessor isv

A. 10
B. 0
C. 1
D. none of these

Solution

(b) 0
Samacheer Kalvi 6th Maths Guide Term 1 Chapter 1 Set Language Ex 1.5

Answer:

(b) 0
Samacheer Kalvi 6th Maths Guide Term 1 Chapter 1 Set Language Ex 1.5

Q.9Which of the following expressions is not zero?v

A. 0 × 0
B. 0 + 0
C. \(\frac{2}{0}\)
D. \(\frac{0}{2}\)

Solution

Answer:

Q.10Which of the following is not true?v

A. (4237 + 5498) + 3439 = 4237 + (5498 + 3439)
B. (4237 × 5498) × 3439 = 4237 × (5498 × 3439)
C. 4237 + 5498 × 3439 = (4237 + 5498) × 3439
D. 4237 × (5498 + 3439) = (4237 × 5498) + (4237 × 3439)

Solution

(c) 4237 + 5498 × 3439 = (4237 + 5498) × 3439
Samacheer Kalvi 6th Maths Guide Term 1 Chapter 1 Set Language Ex 1.5
Posted in Class 6 on January 19, 2025 January 20, 2025
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Answer:

Q.1Try to open my locked suitcase which has the biggest 5 digit odd number as the password comprising the digits 7, 5, 4, 3 and 8. Find the password.v

Solution

87543

Answer:

87543

Q.4Mullaikodi has 25 bags of apples. In each bag, there are 9 apples. She shares them equally amongst her 6 friends. How many apples does each get? Are there any apples left over?v

Solution

No of apple bags = 25
Apples in each bag = 9
Total no of apples = 25 × 9 = 225
Apples shared among her 6 friends = 225 ÷ 6
So, among her 6 friends, each of them gets 37 apples and 3 apples are leftover.
Samacheer Kalvi 6th Maths Guide Term 1 Chapter 1 Set Language Ex 1.6

Answer:

Q.5Poultry has produced 15472 eggs and fits 30 eggs in a tray. How many trays do they need?v

Solution

No of eggs produced = 15472
No of eggs fits in a tray = 30
No of trays required = 15472 ÷ 30
Trays required = 515 + 1 (to fit the remaining 22 eggs) = 516
Quotient = 515
Remainder = 22
Samacheer Kalvi 6th Maths Guide Term 1 Chapter 1 Set Language Ex 1.6
Challenging Problems

Answer:

Q.7Anbu asks Arivu Selvi to guess a five-digit odd number. He gives the following hints. The digit in the 1000s place is less than 5 The digit in the 100s place is greater than 6 The digit in the 10s place is 8. What is Arivu Selvi’s answer? Does she give more than one answer?v

Solution

There are more than one answers.
One of them is 54781
Some of the other numbers maybe 64783, 74785, 84787 and so on.

Answer:

There are more than one answers.
One of them is 54781
Some of the other numbers maybe 64783, 74785, 84787 and so on.

Q.8A Music concert is taking place in a stadium. A total of 7,689 chairs are to be put in rows of 90. (i) How many rows will there be? (ii) Will there be any chairs left over?v

Solution

Total no of chairs to be put = 7,689
Chairs in each row = 90
No of rows = 7689 ÷ 90
Hence, 84 + 1 = 85 rows are required to fill 7650 chairs
Chairs left over = 79 (If the no of rows = 84)
Samacheer Kalvi 6th Maths Guide Term 1 Chapter 1 Set Language Ex 1.6

Answer:

Q.9Round off the seven-digit number 29,75,842 to the nearest lakhs and ten lakhs. Are they the same?v

Solution

Yes. Both are same (30,00,000)

Answer:

Yes. Both are same (30,00,000)

Q.10Find the 5 or 6 or 7 digit numbers from a newspaper or a magazine to get a rounded number to the nearest ten thousand.v

Solution

(i) 14276 \(\simeq\) 10000
(ii) 1,86945 \(\simeq\) 1,90000
Samacheer Kalvi 6th Maths Guide Term 1 Chapter 1 Set Language Ex 1.6
Posted in Class 6 on January 19, 2025 January 20, 2025
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