Term 1 · Class 7 Maths · Chapter 6

Samacheer Class 7 Maths - Information Processing Intext Questions

11 textbook Q&A11 verifiedFree Content

Chapter-wise textbook exercise answers for Information Processing Intext Questions with validation-aware solutions.

Answers marked verified were checked during generation against the chapter context and source question text.
Sections in this chapter
Book Back Questions 11
Your Progress - Chapter 60% complete
1Book Back Questions11 questions
Q.1Observe the pictures and answer the following. (i) Find all the possible routes from house to school via fire station. (ii) Find all the possible routes between central park and school with distance. Mention the shortest route? (iii) Calculate the shortest distance between bank and school.v
Answer:

(i) (a) House ➝ Fire station ➝ Library ➝ Central Park ➝ Hotel ➝ Fruit shop ➝ School.
(b) House ➝ Fire station ➝ Library ➝ Fruit shop ➝ School.
(c) House ➝ Fire station ➝ Library ➝ School.
(ii) Possible routes between Central park and school and their distances are
(a) School ➝ Fruit shop ➝ Hotel ➝ Central park.
Distance ➝ (150 + 300 + 100)m = 550 m
(b) School ➝ Fruit shop ➝ Library ➝ Central park Distance ➝(150 + 100 + 200)m
= 450 m
(c) School ➝ Library ➝ Central park
Distance = (20 + 200 m)
= 220 m
(d) School ➝ Library ➝ Fire station ➝ House ➝ central park Distance = (20 + 50 + 300 + 150) m
= 520 m
(e) School ➝ Emit shop ➝ Hotel ➝ Bank ➝ House ➝ Central park
Distance ➝ (150 + 300 + 150 + 200 + 150) m
= 950 m
(f) School ➝ fruit shop ➝ Hotel ➝ Bank ➝ House ➝ Fire station ➝ Library ➝ central park
Distance = (150 + 300 + 150 + 200 + 300 + 50 + 200)m = 1350 m
∴ Route (c) is the shortest path (i.e.,) School ➝ Library ➝ Central park
(iii) Shortest distance between school and Bank is calculated as follows Bank ➝ Hotel ➝ Central park ➝ Library ➝ school.
Distance = (150 + 100 + 200 + 20)m
= 470 m

✓ Verified and validated
Q.1A tetromino is a shape obtained by …… squares together.v
Answer:

4

✓ Verified and validated
Q.2Draw a tetromino which passes symmetry ……..v
Answer:

✓ Verified and validated
Q.4Shade the figure completely, by using five tetrominoes shapes only once. v
Answer:

✓ Verified and validated
Q.1Make a model of a fish using the given tetromino shapes Complete the given rectangle using the given tetromino shapes.v
Answer:

✓ Verified and validated
Q.3Shade the figure completely, by using five Tetromino shapes only once. v
Answer:

✓ Verified and validated
Q.4Using the given tetrominoes with numbers on it complete the 4 × 4 magic square? v
Answer:

✓ Verified and validated
Q.5Find the shortest route to Vivekanandar Memorial Hall from the Mandapam using the given map. v
Answer:

Possible routes from Mandapam to Vivekandar Memorial are
route 1:
(a) Mandapam ➝ Pullivasal Island ➝ Krusadai Island ➝ Vivekanandar Memorial Hall.
Distance = 6 Km + 2 Km + 1.5 Km = 9.5 Km
route 2:
(b) Mandapam ➝ Krusadai Island ➝ Vivekanandar Memorial Hall.
Distance = 7 Km + 1.5 Km = 8.5 Km
8.5 km < 9.5 km
∴ Shortest route : Mandapam ➝ Krusadai Island ➝ Vivekanandar Memorial Hall.
Challenge Problems

✓ Verified and validated
Q.6Fill in 4 × 10 rectangle completely, using all the five tetrominoes twice.v
Answer:

(more possible ways are there)

✓ Verified and validated
Q.7Fill in 8 × 5 rectangle completely, using all the five tetrominoes twice.v
Answer:

(more possible way are there)

✓ Verified and validated
Q.8Observe the picture and answer the following. (i) Find all the possible routes from A to D. (ii) Find the shortest distance between E and C. (iii) Find all the possible routes between B and F with distance. Mention the shortest route. v
Answer:

(i) All possible routes from A to D are :
(a) A ➝ G ➝ F ➝ E ➝ D
(b) A ➝ G ➝ D
(c) A ➝ B ➝ C ➝ D
(d) A ➝ B ➝ D
(ii) Distance between E and C are
(a) Route 1: E ➝ D ➝ C
Distance: 120 m + 200 m = 320 m.
(b) Route 2: E ➝ D ➝ B ➝ C
Distance = 120 + 100 m + 120 m
= 340 m.
∴ Shortest distance is 320 m.
(iii) All possible routes between B and F are :
(a) Route 1: B ➝ A ➝ G ➝ F
Distance = 250 m + 100 m + 150 m = 600 m.
(b) Route 2: 2 ➝ D ➝ E ➝ F
Distance = 100 m + 120 m + 300 m
= 520 m.
(c) Route 3: B ➝ D ➝ G ➝ F
Distance = 100 m + 200 m + 150 m
= 450 m.
(d) Route 4: B ➝ C ➝ D ➝ E ➝ F
Distance = 120 m + 200 m + 120 m + 300 m
= 740 m.
We find that Route 3 is shortest.
ie B ➝ D ➝ G ➝ F is the shortest route.
About Us
Privacy Policy
Disclaimer
Contact Us

✓ Verified and validated
Back: Ch.5
Next: Ch.1