Secondary(ii) The upper limit of the class interval (25-35) is ________ .
35
(iii) The range of the data 200, 15, 20, 103, 3, 196, is ________ .
197
(iv) If a class size is 10 and range is 80 then the number of classes are ________ .
8
(v) Pie chart is a ________ graph.
circular
False
(ii) Comparison of parts of a whole may be done by a pie chart.
True
(iii) Media and business people use pie charts.
True
(iv) A pie diagram is a circle broken down into component sectors.
True
The data given is raw data.
Ascending order : 0, 1, 2, 3, 4, 5, 6∴ Tabulating in frequency distribution table we get
Maximum mark obtained = 495
Minimum marks obtained = 157
Range = Maximum value – Minimum value
Range = 495 – 157
= 338
If we take the class size as 50 then the number of class intervals possible= \(\frac{338}{50}\) = 6.76
≅ 7The percentage difference calculator is here to help you compare two numbers.
Total percentage of students = 100 %
∴ 50students = 100% – (30% + 20% + 25% + 15%)
= 100% – 90%
50 students = 10%
10% of total students = 50
∴ \(\frac { 10 }{ 100 }\) (Total students) = 50
Total students = \(\frac{50 \times 100}{10}\) = 500.
Total students = 500.
(i) 20% of the students like red colour.
(ii) 15% of the students liked green colour.
\(\frac{15}{100}\) × 500 = 75 students liked green colour.(iii) 25% students liked blue students liked blue.
⇒ \(\frac{25}{100}\) students liked blue.
⇒ \(\frac{1}{4}\) students liked blue.
(iv) Percentage of students liked red colour
= 20%
Percentage of students did not like red colour
= 100% – 20%
= 80%
∴ Number of students did not like red colour
= 80% of 500
= \(\frac{80}{100}\) × 500 = 400
400 students did not like red colour.
(v) Students liked pink or blue = students liked pink + students liked blue.
= 30% of 500 + 25% of 500
= \(\frac{30}{100}\) × 500 + \(\frac{25}{100}\) × 500
= 150 + 125
= 275(vi) Total number of students = 500
500 students were asked about their favourite colour.
Total number of people = 160 + 90 + 80 + 50 + 30 + 40 = 450
Converting the number of people prefer various food items into components part of 360°Food items are preferred by people.
Monthly expenditure of kumaran’s family.1. Given Kumaran spends ₹ 6000 for Rent.
∴ 15% of’ total expenditure = 6000
\(\frac{15}{100}\) (Total Expenditure) = 6000
Total Expenditure = \(\frac{6000 \times 100}{15}\)
Total Expenditure = ₹ 40,000
Amount spend l’or education = 20% of total expenditure.
\(\frac{20}{100}\) × 40,000
= ₹ 80002. Total salary of Kumaran = ₹ 40,000
3. Amount spend for food = 50% of (40,000)
Amount spend for the food than education
= 20,000 – 8,000
= ₹ 12,000
Yes
(ii) Production of cycles in different years.
No(iii) The number of students in each class of a school.
No
(iv) The number votes polled from 7 am to 6 pm in an election.
Yes
(v) The wickets fallen from 1 over to 50th over in a one day cricket match.
Yes
proportional
(ii) A graph that displays data that changes continuously over the periods of time is _________ .
Histogram
(iii) Histogram is a graphical representation of_________ data.
grouped
330 people (110 + 220)
(ii) How many of them use the cell phone for more than 5 hours?
150 of them (100 + 50)
(iii) Are people using cell phone for less than 1 hour?
No
- A. numbers
- B. words
- C. measurements
- D. all the three
(D) all the three
- A. tally marks
- B. data
- C. frequency
- D. none of these
(C) frequencyThis age difference calculator lets you quickly determine the age gap between two people.
- A. range
- B. frequency
- C. variable
- D. none of these
(A) range
- A. ungrouped
- B. grouped
- C. frequency
- D. none of these
(B) grouped
- A. continuous
- B. discontinuous
- C. both
- D. none of these
(B) discontinuous
- A. Inclusive
- B. exclusive
- C. ungrouped
- D. none of these
(B) exclusive
- A. histogram
- B. frequency polygon
- C. pie chart
- D. all the three
(C) pie chart
- A. continuous
- B. discontinuous
- C. discrete
- D. none of these
(A) continuous
- A. frequency polygon
- B. histogram
- C. pie chart
- D. bar graph
(A) frequency polygon
- A. bar graph
- B. pictograph
- C. pie chart
- D. histogram
(D) histogram
Converting the percentage into components parts of 360°. we haveMode of Transport by students.
Converting into continuous distribution we have
Class interval
No. of persons
0 – 5
1
5 – 10
11
10 – 15
7
15 – 20
7
20 – 25
1
25 – 30
8
30 – 35
3
35 – 40
7
40 – 45
3
45 – 50
5
Total
53
1 Rupee = 100 paise.Expenditure of a cloth manufacturing company.
Ascending order: 4, 4, 7, 9, 10, 13, 25, 31, 34, 40, 42.
Descending order: 42, 40, 34, 31, 25, 13, 10, 9, 7, 4, 4
Ascending order of the given data:
4, 6, 9, 14, 20, 26, 31, 39, 42, 53, 57, 61, 63
Here largest value = 63
Smallest value = 4
∴ Range = Largest value – smallest value
= 63 – 4 = 59
Try These (Text Book page No. 217)
Ascending order of the given data.
1, 1, 1, 2, 2, 2, 2, 3, 3, 3, 3, 4, 4, 4, 5, 5, 6, 6
The distribution table:
Data
Tally marks
Frequency
1
|||
3
2
||||
4
3
||||
4
4
|||
3
5
||
2
6
||
2
∴ Frequency Table:
Largest value = 47
Smallest value = 3
Range = Largest value – Smallest value
= 47 – 3 = 44
Suppose we take class size as 10, then Number of class intervals possibleApppbcnmxdfsmadnksa 5