Secondary
(ii) The upper limit of the class interval (25-35) is ________ .
35
(iii) The range of the data 200, 15, 20, 103, 3, 196, is ________ .
197
(iv) If a class size is 10 and range is 80 then the number of classes are ________ .
8
(v) Pie chart is a ________ graph.
circular
Secondary
(ii) The upper limit of the class interval (25-35) is ________ .
35
(iii) The range of the data 200, 15, 20, 103, 3, 196, is ________ .
197
(iv) If a class size is 10 and range is 80 then the number of classes are ________ .
8
(v) Pie chart is a ________ graph.
circular
False
(ii) Comparison of parts of a whole may be done by a pie chart.
True
(iii) Media and business people use pie charts.
True
(iv) A pie diagram is a circle broken down into component sectors.
True
False
(ii) Comparison of parts of a whole may be done by a pie chart.
True
(iii) Media and business people use pie charts.
True
(iv) A pie diagram is a circle broken down into component sectors.
True
The data given is raw data.
Ascending order : 0, 1, 2, 3, 4, 5, 6
∴ Tabulating in frequency distribution table we get
The data given is raw data.
Ascending order : 0, 1, 2, 3, 4, 5, 6
∴ Tabulating in frequency distribution table we get
Maximum mark obtained = 495
Minimum marks obtained = 157
Range = Maximum value – Minimum value
Range = 495 – 157
= 338
If we take the class size as 50 then the number of class intervals possible
= \(\frac{338}{50}\) = 6.76
≅ 7
The percentage difference calculator is here to help you compare two numbers.
Maximum mark obtained = 495
Minimum marks obtained = 157
Range = Maximum value – Minimum value
Range = 495 – 157
= 338
If we take the class size as 50 then the number of class intervals possible
= \(\frac{338}{50}\) = 6.76
≅ 7
The percentage difference calculator is here to help you compare two numbers.
vTotal percentage of students = 100 %
∴ 50students = 100% – (30% + 20% + 25% + 15%)
= 100% – 90%
50 students = 10%
10% of total students = 50
∴ \(\frac { 10 }{ 100 }\) (Total students) = 50
Total students = \(\frac{50 \times 100}{10}\) = 500.
Total students = 500.
(i) 20% of the students like red colour.
(ii) 15% of the students liked green colour.
\(\frac{15}{100}\) × 500 = 75 students liked green colour.
(iii) 25% students liked blue students liked blue.
⇒ \(\frac{25}{100}\) students liked blue.
⇒ \(\frac{1}{4}\) students liked blue.
(iv) Percentage of students liked red colour
= 20%
Percentage of students did not like red colour
= 100% – 20%
= 80%
∴ Number of students did not like red colour
= 80% of 500
= \(\frac{80}{100}\) × 500 = 400
400 students did not like red colour.
(v) Students liked pink or blue = students liked pink + students liked blue.
= 30% of 500 + 25% of 500
= \(\frac{30}{100}\) × 500 + \(\frac{25}{100}\) × 500
= 150 + 125
= 275
(vi) Total number of students = 500
500 students were asked about their favourite colour.
Total percentage of students = 100 %
∴ 50students = 100% – (30% + 20% + 25% + 15%)
= 100% – 90%
50 students = 10%
10% of total students = 50
∴ \(\frac { 10 }{ 100 }\) (Total students) = 50
Total students = \(\frac{50 \times 100}{10}\) = 500.
Total students = 500.
(i) 20% of the students like red colour.
(ii) 15% of the students liked green colour.
\(\frac{15}{100}\) × 500 = 75 students liked green colour.
(iii) 25% students liked blue students liked blue.
⇒ \(\frac{25}{100}\) students liked blue.
⇒ \(\frac{1}{4}\) students liked blue.
(iv) Percentage of students liked red colour
= 20%
Percentage of students did not like red colour
= 100% – 20%
= 80%
∴ Number of students did not like red colour
= 80% of 500
= \(\frac{80}{100}\) × 500 = 400
400 students did not like red colour.
(v) Students liked pink or blue = students liked pink + students liked blue.
= 30% of 500 + 25% of 500
= \(\frac{30}{100}\) × 500 + \(\frac{25}{100}\) × 500
= 150 + 125
= 275
(vi) Total number of students = 500
500 students were asked about their favourite colour.
vTotal number of people = 160 + 90 + 80 + 50 + 30 + 40 = 450
Converting the number of people prefer various food items into components part of 360°
Food items are preferred by people.
Total number of people = 160 + 90 + 80 + 50 + 30 + 40 = 450
Converting the number of people prefer various food items into components part of 360°
Food items are preferred by people.
Also 1. Find the amount spent for education if Kumaran spends ₹ 6000 for Rent. 2. What is the total salary of Kumaran? 3. How much did he spend more for food than education?v
Monthly expenditure of kumaran’s family.
1. Given Kumaran spends ₹ 6000 for Rent.
∴ 15% of’ total expenditure = 6000
\(\frac{15}{100}\) (Total Expenditure) = 6000
Total Expenditure = \(\frac{6000 \times 100}{15}\)
Total Expenditure = ₹ 40,000
Amount spend l’or education = 20% of total expenditure.
\(\frac{20}{100}\) × 40,000
= ₹ 8000
2. Total salary of Kumaran = ₹ 40,000
3. Amount spend for food = 50% of (40,000)
Amount spend for the food than education
= 20,000 – 8,000
= ₹ 12,000
Posted in Class 8 on January 5, 2025 January 6, 2025
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Monthly expenditure of kumaran’s family.
1. Given Kumaran spends ₹ 6000 for Rent.
∴ 15% of’ total expenditure = 6000
\(\frac{15}{100}\) (Total Expenditure) = 6000
Total Expenditure = \(\frac{6000 \times 100}{15}\)
Total Expenditure = ₹ 40,000
Amount spend l’or education = 20% of total expenditure.
\(\frac{20}{100}\) × 40,000
= ₹ 8000
2. Total salary of Kumaran = ₹ 40,000
3. Amount spend for food = 50% of (40,000)
Amount spend for the food than education
= 20,000 – 8,000
= ₹ 12,000
Posted in Class 8 on January 5, 2025 January 6, 2025
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Yes
(ii) Production of cycles in different years.
No
(iii) The number of students in each class of a school.
No
(iv) The number votes polled from 7 am to 6 pm in an election.
Yes
(v) The wickets fallen from 1 over to 50th over in a one day cricket match.
Yes
Yes
(ii) Production of cycles in different years.
No
(iii) The number of students in each class of a school.
No
(iv) The number votes polled from 7 am to 6 pm in an election.
Yes
(v) The wickets fallen from 1 over to 50th over in a one day cricket match.
Yes
proportional
(ii) A graph that displays data that changes continuously over the periods of time is _________ .
Histogram
(iii) Histogram is a graphical representation of_________ data.
grouped
proportional
(ii) A graph that displays data that changes continuously over the periods of time is _________ .
Histogram
(iii) Histogram is a graphical representation of_________ data.
grouped
(i) How many people use the cell phone for less than 3 hours?v330 people (110 + 220)
(ii) How many of them use the cell phone for more than 5 hours?
150 of them (100 + 50)
(iii) Are people using cell phone for less than 1 hour?
No
330 people (110 + 220)
(ii) How many of them use the cell phone for more than 5 hours?
150 of them (100 + 50)
(iii) Are people using cell phone for less than 1 hour?
No
- A. numbers
- B. words
- C. measurements
- D. all the three
(D) all the three
(D) all the three
- A. tally marks
- B. data
- C. frequency
- D. none of these
(C) frequency
This age difference calculator lets you quickly determine the age gap between two people.
(C) frequency
This age difference calculator lets you quickly determine the age gap between two people.
- A. range
- B. frequency
- C. variable
- D. none of these
(A) range
(A) range
- A. ungrouped
- B. grouped
- C. frequency
- D. none of these
(B) grouped
(B) grouped
- A. continuous
- B. discontinuous
- C. both
- D. none of these
(B) discontinuous
(B) discontinuous
- A. Inclusive
- B. exclusive
- C. ungrouped
- D. none of these
(B) exclusive
(B) exclusive
- A. histogram
- B. frequency polygon
- C. pie chart
- D. all the three
(C) pie chart
(C) pie chart
- A. continuous
- B. discontinuous
- C. discrete
- D. none of these
(A) continuous
(A) continuous
- A. frequency polygon
- B. histogram
- C. pie chart
- D. bar graph
(A) frequency polygon
(A) frequency polygon
- A. bar graph
- B. pictograph
- C. pie chart
- D. histogram
(D) histogram
Posted in Class 8 on January 5, 2025 January 6, 2025
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(D) histogram
Posted in Class 8 on January 5, 2025 January 6, 2025
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vConverting the percentage into components parts of 360°. we have
Mode of Transport by students.
Converting the percentage into components parts of 360°. we have
Mode of Transport by students.
Converting into continuous distribution we have
Class interval
No. of persons
0 – 5
1
5 – 10
11
10 – 15
7
15 – 20
7
20 – 25
1
25 – 30
8
30 – 35
3
35 – 40
7
40 – 45
3
45 – 50
5
Total
53
Converting into continuous distribution we have
Class interval
No. of persons
0 – 5
1
5 – 10
11
10 – 15
7
15 – 20
7
20 – 25
1
25 – 30
8
30 – 35
3
35 – 40
7
40 – 45
3
45 – 50
5
Total
53
1 Rupee = 100 paise.
Expenditure of a cloth manufacturing company.
1 Rupee = 100 paise.
Expenditure of a cloth manufacturing company.
Ascending order: 4, 4, 7, 9, 10, 13, 25, 31, 34, 40, 42.
Descending order: 42, 40, 34, 31, 25, 13, 10, 9, 7, 4, 4
Ascending order: 4, 4, 7, 9, 10, 13, 25, 31, 34, 40, 42.
Descending order: 42, 40, 34, 31, 25, 13, 10, 9, 7, 4, 4
Ascending order of the given data:
4, 6, 9, 14, 20, 26, 31, 39, 42, 53, 57, 61, 63
Here largest value = 63
Smallest value = 4
∴ Range = Largest value – smallest value
= 63 – 4 = 59
Try These (Text Book page No. 217)
Ascending order of the given data:
4, 6, 9, 14, 20, 26, 31, 39, 42, 53, 57, 61, 63
Here largest value = 63
Smallest value = 4
∴ Range = Largest value – smallest value
= 63 – 4 = 59
Try These (Text Book page No. 217)
Ascending order of the given data.
1, 1, 1, 2, 2, 2, 2, 3, 3, 3, 3, 4, 4, 4, 5, 5, 6, 6
The distribution table:
Data
Tally marks
Frequency
1
|||
3
2
||||
4
3
||||
4
4
|||
3
5
||
2
6
||
2
∴ Frequency Table:
Ascending order of the given data.
1, 1, 1, 2, 2, 2, 2, 3, 3, 3, 3, 4, 4, 4, 5, 5, 6, 6
The distribution table:
Data
Tally marks
Frequency
1
|||
3
2
||||
4
3
||||
4
4
|||
3
5
||
2
6
||
2
∴ Frequency Table:
Largest value = 47
Smallest value = 3
Range = Largest value – Smallest value
= 47 – 3 = 44
Suppose we take class size as 10, then Number of class intervals possible
Apppbcnmxdfsmadnksa 5
Posted in Class 8 on September 20, 2024 September 21, 2024
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Largest value = 47
Smallest value = 3
Range = Largest value – Smallest value
= 47 – 3 = 44
Suppose we take class size as 10, then Number of class intervals possible
Apppbcnmxdfsmadnksa 5
Posted in Class 8 on September 20, 2024 September 21, 2024
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