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Samacheer Kalvi Class 7 Maths Practice Question Papers

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Brain Grain · braingrain.in
Maths — Practice Paper · Set 1
Class: 7Samacheer KalviMax Marks: 59
Name: ____________________Reg No: ____________
Part I — Multiple Choice Questions 10 × 1 = 10

Choose the correct answer. (Answer all questions.)

1.Which of the following expressions is equal to -30. (i) -20 – (-5 × 2) (ii) (6 × 10) – (6× 5) (iii) (2 × 5)+ (4 × 5) (iv) (-6) × (+5)[1]
2.Which of the following rule is not sufficient to verify the congruency of two triangles. (i) SSS rule (ii) SAS rule (iii) SSA rule (iv) ASA rule[1]
3.A straight angle measuresA. 45°B. 90°C. 180°D. 100°[1]
4.Find the missing values in the following table for the circles with radius (r), diameter (d) and Circumference (C).[1]
5.Which of the following does not represent an integer? (i) 0 ÷ (-7) (ii) 20 ÷ (-4) (iii) (-9) ÷ 3 (iv) 12 ÷ 5[1]
6.Which of the following methods are used to check the congruence of plane figures? (i) translation method (ii) superposition method (iii) substitution method (iv) transposition method[1]
7.Round the following decimal numbers upto 3 place of decimalA. 24.4003B. 1251.2345C. 61.00203[1]
8.Which of the following statement is ALWAYS TRUE when parallel lines are cut by a transversal (i) corresponding angles supplementary (ii) alternate interior angles supplementary (iii) alternate exterior angles supplementary (iv) interior angles on the same side of the transversal are supplementary[1]
9.An angle with measure 128° is called ___ angle.A. a straightB. an obtuseC. an acuteD. Right[1]
10.Construct the following angles using protractor and draw a bisector to each of the angle using ruler and compass. (e) 110°.A. 60°B. 100°C. 90°D. 48°[1]
Part II — Fill in the Blanks 5 × 1 = 5

Fill in the blanks. (Answer all questions.)

11.(-40) ÷ ___ =40[1]
12.The subtraction of 5m from -3m is ______[1]
13.________ is a representative value of the entire data. (i) Mean (ii) range (iii) minimum value (iv) maximum value[1]
14.x 2 [ ] xy __________[1]
15.20 + (-9) + 9 = ____ (i) 20 (ii) 29 (iii) 11 (iv) 38[1]
Part III — True or False 5 × 1 = 5

Write True or False. (Answer all questions.)

16.8 × (-4) = 32[1]
17.The co-efficient of ab in the term 15 abc is 15. Hint: Coefficient of ab is 15c[1]
18.x < -y can be rewritten as – y < x[1]
19.The sum of two integers can never be zero[1]
20.(-100) × 0 × 20 = 0[1]
Part IV — Short Answer Questions 12 × 2 = 24

Answer briefly. (Answer all questions.)

21.Find: 9.13 × 10 9.13 × 100 9.13 × 1000[2]
22.How many transversals can you draw for the following two lines[2]
23.0.07% is (i) \(\frac { 7 }{ 10 } \) (ii) \(\frac { 7 }{ 100 } \) (iii) \(\frac { 7 }{ 1000 } \) (iv) \(\frac { 7 }{ 10,000 } \) Hint: 0.07 % = 0.07% = \(\frac { 0.07 }{ 100 } \) = \(\frac{7}{\frac{100}{100}}\) = \(\frac{7}{100 \times 100}\) = \(\frac { 7 }{ 10,000 } \)[2]
24.The ratio of the area of a circle to the area of its semicircle is (i) 2 : 1 (ii) 1 : 2 (iii) 4 : 1 (iv) 1 : 4[2]
25.Cost of levelling a land at the rate of ₹ 15.50 sq. ft is ₹ 10,075. Find the area of the land.[2]
26.The area of parallelogram whose base 10 m and height 7 m is (i) 70 sq.m (ii) 35 sq.m (iii) 7 sq.m (iv) 10 sq.m[2]
27.(-200) ÷ 10 is (i) 20 (ii) -20 (iii) -190 (iv) 210[2]
28.78.56 [ ] 78.57 (i) < (ii) > (iii) = (iv) ≠[2]
29.What should be added to -1 to get 10?[2]
30.A toy factory making variety of toys for kids, wants to know the most popular toy liked by all the kids. Which average will be the most appropriate for it?[2]
31.If an exterior angle of a triangle is 115° and one of the interior opposite angles is 35°, then the other two angles of the triangle are (i) 45°, 60° (ii) 65°, 80° (iii) 65°, 70° (iv) 115°, 60°[2]
32.Given 168 × 32 = 5376 then fined (-5376) ÷ (-32).[2]
Part V — Long Answer Questions 3 × 5 = 15

Answer in detail. (Answer all questions.)

33.Write each of the following as decimal numbers. (i) 20 + 1 + \(\frac { 2 }{ 10 } \) + \(\frac { 3 }{ 100 } \) + \(\frac { 7 }{ 1000 } \) (ii) 3 + \(\frac { 8 }{ 10 } \) + \(\frac { 4 }{ 100 } \) + \(\frac { 5 }{ 1000 } \) (iii) 6 + \(\frac { 0 }{ 10 } \) + \(\frac { 0 }{ 100 } \) + \(\frac { 9 }{ 1000 } \) (iv) 900 + 50 + 6 + \(\frac { 3 }{ 100 } \) (v) \(\frac { 6 }{ 10 } \) + \(\frac { 3 }{ 100 } \) + \(\frac { 1 }{ 1000 } \)[5]
34.Stephen invested ₹ 10,000 in a savings bank account that earned 2% simple interest. Find the interest earned if the amount was kept in the bank for 4 years.[5]
35.Find the shortest route to Vivekanandar Memorial Hall from the Mandapam using the given map.[5]
🔑 Show Answer Key — Set 1
  1. 1. (iv) (-6) × (+5) Hint: (i) -20 + (10) = -10 (ii) 60 – 30 = 30 (iii) 10 + 20 = 30 (iv) (-6) × (+5) = – 30
  2. 2. (iii) SSA rule
  3. 3. (c) 180° No, they are not adjacent pairs.
  4. 4. (i) Given radius r = 15cm ∴ diameter d = 2 × 15 = 30 cm Circumference C = π d units = \(\frac { 22 }{ 7 } \) × 30 = \(\frac { 660 }{ 7 } \) = 94.28 cm (ii) Given circumference C = 1760 cm 2πr = 1760 2 × \(\frac { 22 }{ 7 } \) × r = 1760 r = \(\frac{1760 \times 7}{2 \times 22}\) = \(\frac{160 \times 7}{2 \times 2}\) = 40 × 7 = 280 cm diameter = 2 × r = 2 × 280 = 560 cm (iii) diameter d = 24m radius r = \(\frac { d }{ 2 } \) = \(\frac { 24 }{ 2 } \) = 12 m Circumference C = 2 π r units = 2 × \(\frac { 22 }{ 7 } \) × 12 = \(\frac { 528 }{ 7 } \) = 75.4 m Tabulating the results
  5. 5. (iv) 12 ÷ 5
  6. 6. (ii) superposition method
  7. 7. (a) 24.4003 Rounding 24.4003 upto 3 places of decimal means rounding to the nearest thousandths place. Underlining the digit in the thousandths place of 24.4003 gives 24.40 0 3. In 24.40 0 3 the digit next to the thousandths value is 3 which is less than 5. ∴ The underlined digit remains the same. So the rounded value of24.4003 upto 3 places of decimal is 24.400. (b) 1251.2345 Rounding 1251.2345 upto 3 places of decimal means rounding to the nearest thousandths place. Underlining the digit in the thousandths place of 1251.2345 gives 1251.23 4 5, the digit next to the thousandths place value is 5 and so we add 1 to the underlined digit. So the rounded value of 1251.2345 upto 3 places of de…
  8. 8. (iv) Interior angles on the same side of the transversal are supplementary.
  9. 9. (b) an obtuse
  10. 10. (a) 60° Construction:Step 1: Drawn the given angle ∠ABC with the measure 60° using protractor. Step 2: With B as centre and convenient radius, drawn an arc to cut BA and BC. Marked the points of intersection as E on BA and F on BC. Step 3: With the same radius and E as centre drawn an arc in the interior of ∠ABC and another arc of same measure with centre at F to cut the previous arc. Step 4: Marked the point of intersection as G. Drawn a ray BX through G. BG is the required bisector of the given ∠ABC(b) 100°Construction : Step 1: Drawn the given angle ∠ABC with the measure 100° c using protractor. Step 2: With B as centre and convenient radius, drawn an arc to cut BA and BC. Marked the p…
  11. 11. -1
  12. 12. -8m
  13. 13. (i) Mean
  14. 14. x 2 [ > ] xy
  15. 15. (i) 20 About Us Privacy Policy Disclaimer Contact Us
  16. 16. False
  17. 17. False
  18. 18. False
  19. 19. False
  20. 20. True
  21. 21. 9.13 × 10 = 91.3 9.13 × 100 = 913 9.13 × 1000 = 9130Try These (Text book Page No. 16)
  22. 22. Infinite number of transversals can be drawn.a, b, c, d, e, f, g are transversal to m and n. Try these (Text book Page No. 96)
  23. 23. (iv) \(\frac { 7 }{ 10,000 } \) About Us Privacy Policy Disclaimer Contact Us
  24. 24. (i) 2 : 1
  25. 25. Cost of levelling the entire land = ₹ 10,075 Cost of levelling 1 sq. ft = ₹ 15.50∴ Area of the land = 650 sq.ft.
  26. 26. (i) 70 sq. m Hint: = base × height = 10m × 7m = 70 sq.m
  27. 27. (ii) 20
  28. 28. (i) < About Us Privacy Policy Disclaimer Contact Us
  29. 29. (-1) + a number = 10 ∴ The number = 10 + 1 = 11
  30. 30. Mode.
  31. 31. (ii) 65°, 80° About Us Privacy Policy Disclaimer Contact Us
  32. 32. Given 168 × 32 = 5376 ∴ \(\frac{5376}{32}\) = 168 Also, \(\frac{-5376}{-32}\) = 168
  33. 33. (i) 20 + 1 + \(\frac { 2 }{ 10 } \) + \(\frac { 3 }{ 100 } \) + \(\frac { 7 }{ 1000 } \) = 21 + 2 × \(\frac { 1 }{ 10 } \) + 3 × \(\frac { 1 }{ 100 } \) + 7 × \(\frac { 1 }{ 1000 } \) = 21.237 (ii) 3 + \(\frac { 8 }{ 10 } \) + \(\frac { 4 }{ 100 } \) + \(\frac { 5 }{ 1000 } \) = 3 + 8 × \(\frac { 1 }{ 10 } \) + 4 × \(\frac { 1 }{ 100 } \) + 5 × \(\frac { 1 }{ 1000 } \) = 3.845 (iii) 6 + \(\frac { 0 }{ 10 } \) + \(\frac { 0 }{ 100 } \) + \(\frac { 9 }{ 1000 } \) = 6 + 0 × \(\frac { 1 }{ 10 } \) + 0 × \(\frac { 1 }{ 100 } \) + 9 × \(\frac { 1 }{ 1000 } \) = 6.009 (iv) 900 + 50 + 6 + \(\frac { 3 }{ 100 } \) = 956 + 0 × \(\frac { 1 }{ 10 } \) + 3 × \(\frac { 1 }{ 100 } \) = 956.03 (v) \(\frac…
  34. 34. Principal (P) = ₹ 10,000 Rate of interest (r) = 2% Time (n) = 4 years ∴ Simple Interest I = \(\frac { pnr }{ 100 } \) = \(\frac{10000 \times 4 \times 2}{100}\) = ₹ 800 Stephen will earn ₹ 800
  35. 35. Possible routes from Mandapam to Vivekandar Memorial are route 1: (a) Mandapam ➝ Pullivasal Island ➝ Krusadai Island ➝ Vivekanandar Memorial Hall. Distance = 6 Km + 2 Km + 1.5 Km = 9.5 Km route 2: (b) Mandapam ➝ Krusadai Island ➝ Vivekanandar Memorial Hall. Distance = 7 Km + 1.5 Km = 8.5 Km 8.5 km < 9.5 km ∴ Shortest route : Mandapam ➝ Krusadai Island ➝ Vivekanandar Memorial Hall. Challenge Problems
Brain Grain · braingrain.in
Maths — Practice Paper · Set 2
Class: 7Samacheer KalviMax Marks: 59
Name: ____________________Reg No: ____________
Part I — Multiple Choice Questions 10 × 1 = 10

Choose the correct answer. (Answer all questions.)

1.The corner of the A4 paper hasA. An acute angleB. A right angleC. StraightD. An obtuse angle[1]
2.Find the area o the following parallelograms by measuring their base and height, using formula. (e) _____ sq. unitsA. _____ sq. unitsB. _____ sq. unitsC. _____ sq. unitsD. _____ sq. units[1]
3.If a perpendicular line is bisecting the given line, you would have twoA. right anglesB. obtuse anglesC. acute anglesD. reflex angles[1]
4.An angle that measure 0° is calledA. right angleB. obtuse angleC. acute angleD. Zero angle.[1]
5.Draw a line segment of given length and construct a perpendicular bisector to each line segment using scale and compass (e) 58 cmA. 8 cmB. 7 cmC. 5.6 cmD. 10.4 cm[1]
6.Count the squares and find the area of the following parallelograms by converting those into rectangles of the same area. (Without changing the base and height).A. ______ sq. unitsB. ______ sq. unitsC. ______ sq. unitsD. ______ sq. units[1]
7.A pool of fish translates from point F to point D.A. Describe the translation of the pool of fish.B. Can the fishing boat make the same translation? Explain.C. Describe a translation the fishing boat could make to get to point D.[1]
8.Which of the following can be the sides of a triangle? (i) 5.9.14 (ii) 7,7,15 (iii) 1,2,4 (iv) 3, 6, 8[1]
9.Which of the following expressions is equal to -30. (i) -20 – (-5 × 2) (ii) (6 × 10) – (6× 5) (iii) (2 × 5)+ (4 × 5) (iv) (-6) × (+5)[1]
10.Which of the following rule is not sufficient to verify the congruency of two triangles. (i) SSS rule (ii) SAS rule (iii) SSA rule (iv) ASA rule[1]
Part II — Fill in the Blanks 5 × 1 = 5

Fill in the blanks. (Answer all questions.)

11.The additive inverse of -37xyz is _____[1]
12.____ × (-9) = -45[1]
13.The addition of – 7b and 2b is _______[1]
14.A triangle has angle measurements of 29°, 65° and 86°. Then it is ______ triangle. (i) an acute angled (ii) a right angled (iii) an obtuse angled (iv) a scalene[1]
15.In the expression 25m + 14M, the type of the terms are ______ terms[1]
Part III — True or False 5 × 1 = 5

Write True or False. (Answer all questions.)

16.If x is a natural number, then x + 1 is its predecessor. Hint: x – 1 is its predecessor.[1]
17.The expressions 8x + 3y and 7x + 2y cannot be added[1]
18.-7 + 2 = 2 + (-7)[1]
19.(-90) + (-30) = 60[1]
20.(-33) + 8 = 8 + (-33)[1]
Part IV — Short Answer Questions 12 × 2 = 24

Answer briefly. (Answer all questions.)

21.Ages of 15 students in 8th standard is 13, 12, 13, 14, 12, 13, 13, 14, 12, 13, 13, 14, 13, 12, 14. Find the mean age of the students.[2]
22.Cost of 105 note books is ₹ 2415. How many notebooks can be bought for ₹ 1863?[2]
23.Observe the sequence of numbers obtained in the 3rd and 4th slanting rows of Pascal’s Triangle and find the difference between the consecutive numbers and complete the table given below.[2]
24.What is the difference between 0.01 and 1%.[2]
25.A motorbike requires 2 liters of petrol to cover 100 kilometres. How many liters of petrol will be required to cover 250 kilometers? (using unitary method).[2]
26.Between which two whole numbers, the following decimal numbers lie? (i) 3.3 (ii) 2.5 (iii) 0.9[2]
27.The unit digit of (32 × 65) 0 is (i) 2 (ii) 5 (iii) 0 (iv) 1[2]
28.If 30 men can reap a field in 15 days, then in how many days can 20 men reap the same field? (using unitary method).[2]
29.How is the pre-image translated to the image?[2]
30.(-100) – 0 + 100 = (i) 200 (ii) 0 (iii) 100 (iv)-200[2]
31.2.01 ÷ 0.03 = ? (i) 6.7 (ii) 67.0 (iii) 0.67 (iv) 0.067[2]
32.Simplify: 23.5 – 27.89 + 35.4 – 17.[2]
Part V — Long Answer Questions 3 × 5 = 15

Answer in detail. (Answer all questions.)

33.Add: (i) 8x, 3x (ii) 7mn, 5mn (iii) -9y, 11y, 2y[5]
34.A student earned a grade of 80% on a math test that had 20 problems. How many problems on this test did the student answer correctly?[5]
35.Draw circles for the following measurements of radius (r)/ diameters(d). (i) r = 4 cm (ii) d = 12 cm (iii) r = 3.5 cm (iv) r = 6.5 cm. (v) d = 6 cm[5]
🔑 Show Answer Key — Set 2
  1. 1. (b) a right angle
  2. 2. (a) Area of the rectangle = (base × height) sq. units base = 5 units height = 5 units ∴ Area = (5 × 5 ) = sq. units = 25 sq. units (b) Area of the rectangle = (base × height) sq. units base = 4 units height = 1 units ∴ Area = (4 × 1 ) = sq. units = 4 sq. units (c) Area of the rectangle = (base × height) sq. units base = 2 units height = 3 units ∴ Area = (2 × 3 ) = sq. units = 6 sq. units (d) Area of the rectangle = (base × height) sq. units base = 4 units height = 4 units ∴ Area = (4 × 4 ) = sq. units = 16 sq. units (e) Area of the parallelogram = (base × height) sq. units base = 7 units height = 5 units = 7 × 5 = 35 sq. units
  3. 3. (a) right angle
  4. 4. (d) Zero angle Try this (Text Book Page No. 86)
  5. 5. (a) 8 cm Construction :Step 1: Drawn a line. Marked two points A and B on it so that AB = 8 cm Step 2: Using compass with A as centre and radius more than half of the length of AB, drawn two arcs of the same length one above AB and one below AB Step 3: With the same radius and B as centre drawn two arcs to cut the arcs drawn in step 2. Marked the points of intersection of the arcs as C and D. step 4: Joined C and D, CD intersect AB. Marked the point of intersection as ‘O’. CD is the required perpendicular bisector of AB.(b) 7 cm Construction :step 1: Drawn a line and marked points A and B on it so that AB = 7 cm. step 2: Using compass with A as centre and radius more than half of the leng…
  6. 6. Converting the given parallelograms into rectangles we get.(a) 10 sq. units (b) 18 sq. units (c) 16 sq. units (d) 5 sq. units
  7. 7. (a) Translation of pool of fish is 7 →, 2↓ (b) No, the fishing boat will be landed on the island if translated. (c) To get point D, the translation will be 5 →, 3↓
  8. 8. (iv) 3, 6, 8 (i) Here 5 + 9 = 14 = the measure of the third side. In a triangle the sum of the measures of any two sides must be greater than the third side. ∴ 5, 9, 14 cannot be the sides of a triangle. (ii) 7.7.15 Here sum of two sides 7 + 7 = 14 < the measures of the thrid side. So 1,1, 15 cannot be the sides of a triangles. (iii) 1,2,4 Here sum of two sides 1 + 2 = 3 < the measure of the third side. ∴ 1, 2, 4 cannot be the sides of a triangle. (iv) 3, 6, 8 Sum of two sides 3 + 6 = 9 > the third side. ∴ 3, 6, 8 can be the sides of a triangle.
  9. 9. (iv) (-6) × (+5) Hint: (i) -20 + (10) = -10 (ii) 60 – 30 = 30 (iii) 10 + 20 = 30 (iv) (-6) × (+5) = – 30
  10. 10. (iii) SSA rule
  11. 11. 37xyz
  12. 12. 5
  13. 13. -5b
  14. 14. (i) an acute angled
  15. 15. unlike
  16. 16. False
  17. 17. False
  18. 18. True, by commutative property on intergers
  19. 19. False
  20. 20. True, by commutative property on intergers
  21. 21. = \(\frac { 195 }{ 15 } \) = 13 Mean age of the students = 13
  22. 22. For 2415 number of notebooks bought = 105
  23. 23. Try These (Text book Page No. 96)
  24. 24. 0.01 = \(\frac { 1 }{ 100 } \) = 1% 0.01 and 1% are the same.
  25. 25. To cover 100 km quantity of petrol required = 2 litres5 litres of petrol required to cover 250 km Objective Type Questions
  26. 26. (i) 3.3 – 3.3 lies between 3 and 4. (ii) 2.5 – 2.5 lies between 2 and 3. (iii) 0.9 – 0.9 lies between 0 and 1.
  27. 27. (iv) 1
  28. 28. ∴ 20 men can reap the field in 10 days.
  29. 29. (i) 3 →, 4↑ (ii) 3 ←, 3↑ (iii) 4 ←, 4↓ (iv) 2 ←, 2↓
  30. 30. (ii) 0 About Us Privacy Policy Disclaimer Contact Us
  31. 31. (ii) 67.0 Hint: \(\frac { 2.01 }{ 0.03 } \) = \(\frac { 201 }{ 3 } \) = 67
  32. 32. 23.5 – 27.89 + 35.4 – 17 = 14.01
  33. 33. (i) 8x + 3x = (8 + 3) x = 11x (ii) 7mn + 5mn = (7 + 5)mn = 12mn (iii) -9y + 11y + 2y =(-9 + 11 + 2 )y = (2 + 2)y = 4y
  34. 34. Total number of problems in the test = 20 Students score = 80 % Number of problem answered = \(\frac { 80 }{ 100 } \) × 20 = 16
  35. 35. (i) r = 4 cmStep 1 : Market a point ‘O’ on the paper. Step 2 : Extended the compass distance equal to radius 4 cm. Step 3 : At center ‘O’, helded the compass firmly and placed the pointed end of the compass. Step 4 : Slowly rotated the compass around to get the circle.(ii) d = 12 cm given d= 12 cm ∴ radius r = \(\frac { d }{ 2 } \) = \(\frac { 12 }{ 2 } \) = 6 cmStep 1: Marked a point ‘O’ on the paper. Step 2: Extended the compass distance equal to radius 6 cm. Step 3: At center ‘O’, held the compass firmly and placed the pointed end of the compass. Step 4: Slowly rotated the compass around to get the circle. (iii) r = 3.5 cmStep 1: Market a point ‘O’ on the paper. Step 2: Extended the co…
Brain Grain · braingrain.in
Maths — Practice Paper · Set 3
Class: 7Samacheer KalviMax Marks: 59
Name: ____________________Reg No: ____________
Part I — Multiple Choice Questions 10 × 1 = 10

Choose the correct answer. (Answer all questions.)

1.A straight angle measuresA. 45°B. 90°C. 180°D. 100°[1]
2.Find the missing values in the following table for the circles with radius (r), diameter (d) and Circumference (C).[1]
3.Which of the following does not represent an integer? (i) 0 ÷ (-7) (ii) 20 ÷ (-4) (iii) (-9) ÷ 3 (iv) 12 ÷ 5[1]
4.Which of the following methods are used to check the congruence of plane figures? (i) translation method (ii) superposition method (iii) substitution method (iv) transposition method[1]
5.Round the following decimal numbers upto 3 place of decimalA. 24.4003B. 1251.2345C. 61.00203[1]
6.Which of the following statement is ALWAYS TRUE when parallel lines are cut by a transversal (i) corresponding angles supplementary (ii) alternate interior angles supplementary (iii) alternate exterior angles supplementary (iv) interior angles on the same side of the transversal are supplementary[1]
7.An angle with measure 128° is called ___ angle.A. a straightB. an obtuseC. an acuteD. Right[1]
8.Construct the following angles using protractor and draw a bisector to each of the angle using ruler and compass. (e) 110°.A. 60°B. 100°C. 90°D. 48°[1]
9.The corner of the A4 paper hasA. An acute angleB. A right angleC. StraightD. An obtuse angle[1]
10.Find the area o the following parallelograms by measuring their base and height, using formula. (e) _____ sq. unitsA. _____ sq. unitsB. _____ sq. unitsC. _____ sq. unitsD. _____ sq. units[1]
Part II — Fill in the Blanks 5 × 1 = 5

Fill in the blanks. (Answer all questions.)

11.The place value of 3 in 85.073 is _____ (i) tenths (ii) hundredths (iii) thousands (iv) thousandths[1]
12.(-10) + (+7) = ____ (i) +3 (ii) -3 (iii) -17 (iv) +17[1]
13.A _______ is a turn about a point. (i) Translation (ii) Rotation (iii) Reflection (iv) Glide Reflection[1]
14.In an expression, we can add or subtract only _____ (i) like terms (ii) unlike terms (iii) all terms (iv) None of the above[1]
15.___ – (+50) = -80[1]
Part III — True or False 5 × 1 = 5

Write True or False. (Answer all questions.)

16.An inequation, -3 < x < -1, where x is an integer, cannot be represented in the number line.[1]
17.The product of two negative integers is a positive integer.[1]
18.The additive inverse of (-32) is -32[1]
19.(-11) + (-8) = (-8) + (-11)[1]
20.(-30) ÷ (-6) = -6[1]
Part IV — Short Answer Questions 12 × 2 = 24

Answer briefly. (Answer all questions.)

21.If P = -15 and Q = 5 find (P – Q) – (P + Q).[2]
22.Four real life examples for transversal of parallel lines are given below. Give four more examples for transversal of parallel lines seen in your surroundings.[2]
23.The formula to find the area of the circular path is (i) π(R 2 – r 2 ) sq. units (ii) πr 2 sq. units (iii) 2πr 2 sq. units (iv) πr 2 + 2r sq. units[2]
24.Which among the following rate of interest yields an interest of ₹ 200 for the principle of ₹ 2,000 for one year. (i) 10% (ii) 20% (iii) 5% (iv) 15% Hint: r = \(\frac{I \times 100}{P \times n}\) = \(\frac{200 \times 100}{2000 \times 1}\) = 10 %[2]
25.Match the given patterns of shapes with the appropriate number pattern and its generalization.[2]
26.Simply the following. 1. 23 5 ÷ 23 2 2. 11 6 ÷ 11 3 3. (-5) 3 ÷ (-5) 2 4. 7 3 ÷ 7 3 5. 15 4 ÷ 15[2]
27.Between which two whole numbers 1.7 lie? (i) 2 and 3 (ii) 3 and 4 (iii) 1 and 2[2]
28.Find the modes of the data 2, 1, 1, 3, 4, 5, 2. (1) 1 and 5 (2) 2 and 3 (3) 2 and 1 (4) 1 and 4[2]
29.Subtract the following by using place value grid, (i) 6.567 from 9.231 (ii) 3.235 from 7[2]
30.In an examination a student scored 75% of marks. Represent the given the percentage in decimal form?[2]
31.Represent the following fractions in decimal form by converting denominator into ten or powers of 10.[2]
32.Kavin scored 15 out of 25 in a test. The percentage of his marks is (i) 60% (ii) 15% (iii) 25% (iv) 15/25 Hint: \(\frac { 15 }{ 25 } \) × \(\frac { 100 }{ 100 } \) = \(\frac { 15 }{ 25 } \) × 100 % = 60 %[2]
Part V — Long Answer Questions 3 × 5 = 15

Answer in detail. (Answer all questions.)

33.If the three angles of a triangle are in the ratio 3 : 5 : 4, then find them.[5]
34.The area of a trapezium is 1586 sq. cm. The distance between its parallel sides is 26 cm. If one of the parallel sides is 84 cm then find the other side.[5]
35.An agricultural field is in the form of a parallelogram, whose area is 68.75 sq. hm. The distance between the parallel sides is 6.25 cm. Find the length of the base.[5]
🔑 Show Answer Key — Set 3
  1. 1. (c) 180° No, they are not adjacent pairs.
  2. 2. (i) Given radius r = 15cm ∴ diameter d = 2 × 15 = 30 cm Circumference C = π d units = \(\frac { 22 }{ 7 } \) × 30 = \(\frac { 660 }{ 7 } \) = 94.28 cm (ii) Given circumference C = 1760 cm 2πr = 1760 2 × \(\frac { 22 }{ 7 } \) × r = 1760 r = \(\frac{1760 \times 7}{2 \times 22}\) = \(\frac{160 \times 7}{2 \times 2}\) = 40 × 7 = 280 cm diameter = 2 × r = 2 × 280 = 560 cm (iii) diameter d = 24m radius r = \(\frac { d }{ 2 } \) = \(\frac { 24 }{ 2 } \) = 12 m Circumference C = 2 π r units = 2 × \(\frac { 22 }{ 7 } \) × 12 = \(\frac { 528 }{ 7 } \) = 75.4 m Tabulating the results
  3. 3. (iv) 12 ÷ 5
  4. 4. (ii) superposition method
  5. 5. (a) 24.4003 Rounding 24.4003 upto 3 places of decimal means rounding to the nearest thousandths place. Underlining the digit in the thousandths place of 24.4003 gives 24.40 0 3. In 24.40 0 3 the digit next to the thousandths value is 3 which is less than 5. ∴ The underlined digit remains the same. So the rounded value of24.4003 upto 3 places of decimal is 24.400. (b) 1251.2345 Rounding 1251.2345 upto 3 places of decimal means rounding to the nearest thousandths place. Underlining the digit in the thousandths place of 1251.2345 gives 1251.23 4 5, the digit next to the thousandths place value is 5 and so we add 1 to the underlined digit. So the rounded value of 1251.2345 upto 3 places of de…
  6. 6. (iv) Interior angles on the same side of the transversal are supplementary.
  7. 7. (b) an obtuse
  8. 8. (a) 60° Construction:Step 1: Drawn the given angle ∠ABC with the measure 60° using protractor. Step 2: With B as centre and convenient radius, drawn an arc to cut BA and BC. Marked the points of intersection as E on BA and F on BC. Step 3: With the same radius and E as centre drawn an arc in the interior of ∠ABC and another arc of same measure with centre at F to cut the previous arc. Step 4: Marked the point of intersection as G. Drawn a ray BX through G. BG is the required bisector of the given ∠ABC(b) 100°Construction : Step 1: Drawn the given angle ∠ABC with the measure 100° c using protractor. Step 2: With B as centre and convenient radius, drawn an arc to cut BA and BC. Marked the p…
  9. 9. (b) a right angle
  10. 10. (a) Area of the rectangle = (base × height) sq. units base = 5 units height = 5 units ∴ Area = (5 × 5 ) = sq. units = 25 sq. units (b) Area of the rectangle = (base × height) sq. units base = 4 units height = 1 units ∴ Area = (4 × 1 ) = sq. units = 4 sq. units (c) Area of the rectangle = (base × height) sq. units base = 2 units height = 3 units ∴ Area = (2 × 3 ) = sq. units = 6 sq. units (d) Area of the rectangle = (base × height) sq. units base = 4 units height = 4 units ∴ Area = (4 × 4 ) = sq. units = 16 sq. units (e) Area of the parallelogram = (base × height) sq. units base = 7 units height = 5 units = 7 × 5 = 35 sq. units
  11. 11. (iv) thousandths Hint: 1000 g = 1 kg; 1 g = \(\frac { 1 }{ 1000 } \) kg
  12. 12. (ii) -3
  13. 13. (ii) Rotation
  14. 14. (i) like terms About Us Privacy Policy Disclaimer Contact Us
  15. 15. -30
  16. 16. True
  17. 17. True
  18. 18. False
  19. 19. True, because addition is commutative for intergers
  20. 20. False
  21. 21. Given P = 15 ; Q = 5
  22. 22. Some examples of parallel lines in our surroundings (i) Zebra crossing on the road. (ii) Railway tracks with sleepers. (iii) Steps (iv) Parallel bars in men’s gymnastics
  23. 23. (i) π(R 2 – r2) sq. units
  24. 24. (i) 10% About Us Privacy Policy Disclaimer Contact Us
  25. 25. (i) (d) (ii) (a) (iii) (c) (iv) (c) (v) (b) Objective Type Questions
  26. 26. Try These (Text book Page No. 48)
  27. 27. (iii) 1 and 2
  28. 28. (3) 2 and 1 About Us Privacy Policy Disclaimer Contact Us
  29. 29. (i) Let as use place value gridTherefore 9.231 – 6.567 = 2.664 (ii) Let as use place value grid.Therefore 7 – 3.235 = 3.765
  30. 30. Student’s Score = 75% = \(\frac { 75 }{ 100 } \) = 0.75
  31. 31. (refer textbook)
  32. 32. (i) 60%
  33. 33. Given three angles of the triangles are in the ratio 3 : 5 : 4. Let the three angle be 3x, 5x and 4x. By angle sum property of a triangle, we have 3x + 5x + 4x = 180° 12x = 180° x = \(\frac{180^{\circ}}{12}\) x = 15° ∴ The angle are 3x = 3 × 15° = 45° 5x = 5 × 15° = 75° 4x = 4 × 15° = 60° Three angles of the triangle are 45°, 75°, 60°
  34. 34. Given one parallel side = 84 cm. Let the other parallel side be ‘b’ cm. Distance between a and b is h = 26 cm. Area of the trapezium = 1586 sq. cm∴ The other parallel side = 38 cm.
  35. 35. Height of the parallelogram = 6.25 hm Area of the parallelogram = 68.75 sq. hm b × h = 68.75 b × 6.25 = 68.75 b = \(\frac{68.75}{6.25}=\frac{6875}{625}\) = 11 km Length of the base = 11 km.

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