Term 1 · Class 7 Maths · Chapter 4

Samacheer Class 7 Maths - Direct and Inverse Proportion Intext Questions

45 textbook Q&AFree Content

Chapter-wise textbook exercise answers for Direct and Inverse Proportion Intext Questions with step-by-step solutions.

📝 Don't just read — test yourselfFree flashcards + scored self-test · no sign-in
Your Progress - Chapter 40% complete
1Book Back Questions45 questions
Q.2Find the ratio (i) 555 g to 5 kg (ii) 21 km to 175 m.v
Answer:

(i) 1 kg = 1000 g
∴ 5 kg = 5000 g
∴ 555 g : 5 kg = 555 g : 5000 g = 111 : 1000
(ii) 21 km to 175m
1 km = 1000 m
21 km = 21 × 1000 = 21,000m
∴ 21 km : 175 m = 21000 : 175 = 120 : 1

Q.3Find the value of x in the following proportions : (i) 110 8: 88 (ii) x : 26 :: 5: 65v
Answer:

(i) Given 110 : x :: 8 : 88
Product of the means = Product of the extremes
x × 8 = 110 × 88(ii) x : 26 :: 5 : 65
Product of the means = Product of the extremesTry this (Text Book Page No. 74)

Q.1The number of chocolates to be distributed to the number of children. Is this statement in direct proportion?v
Answer:

Let the number of students be x and the number of chocolates be y. As the valve of x increases also correspondingly increases.
ie \(\frac{x}{y}=k\)
∴ x and y are in direct proportion.
Try This (Text book Page No. 74)

Q.2Observe the following 5 squares of different sides given in the graph sheet. The measures of the sides are recorded in the table given below. Find the corresponding perimeter and the ratios of each of these with the sides given and complete the table. From the information so obtained state whether the side of a square is in direct proportion to the perimeter of the square.v
Answer:

Perimeter of the square y = 4x, units where x is the side of a squareCompleting the tableFrom the above table we find that as x increases y also increased in such a way that \(\frac{x}{y}=\frac{1}{4}\), constant.
∴ Side of a square is in direct proportion to the perimeter of the square.
Try this (Text book Page No. 75)

Q.3When a fixed amount is deposited for a fixed rate of interest, the simple interest changes proportionally with the number of years it is being deposited. Can you find any other examples of such kind.v
Answer:

Some other examples of such kind are
(i) Cost of book and number of books
(ii) Distance and time to travel
(iii) Men workers and wages.
Exercise 4.2
Try this (Text book Page No. 78)

Q.1Think of an example in real life where two variable are inversely proportional.v
Answer:

Example of inverse proportion are
(i) Men working and the amount of work.
(ii) Speed and time to travel
Try These (Text book Page No. 78)

Q.2Read the following examples and group them in two categories. v
Answer:

About Us
Privacy Policy
Disclaimer
Contact Us

Q.3A dozen bananas costs ₹ 20. What is the price of 48 bananas ?v
Answer:

Let the required price be ₹ x. As the number of bananas increases price also increases
∴ Number of bananas and cost are in direct proportion.

Q.4A group of 21 students paid ₹ 840 as the entry fee for a magic show. How many students entered the magic show if the total amount paid was ₹ 1680?v
Answer:

Let the required number of students be x.As the number of students increases the entry fees also increases.
∴ They are in direct proportion .∴ The number of students entered magic show = 42

Q.5A birthday party is arranged in third floor of a hotel. 120 people take 8 trips in a lift to go to the party hall. If 12 trips were made how many people would have attended the party?v
Answer:

Let the number of people attended the party be x.As the number of trips increases, number of people also increases.
∴ They are in direct proportion.180 people attend the party in 12 trips

Q.6The shadow of a pole with height of 8m is 6m. If the shadow of another pole measured at the same time is 30m, find the height of the pole?v
Answer:

Let the required height of the pole be ‘x’ m.Height of the pole and its shadow are in direct proportion∴ Height of the pole x = 40m.

Q.7A postman can sort out 738 letters in 6 hours. How many letters can be sorted in 9 hours?v
Answer:

Let the required number of letters be x.They are in direct proportion.In 9 hours 1107 letters can be sorted.

Q.8If half a meter of cloth costs ₹ 15. Find the cost of \(8 \frac{1}{3}\) meters of the same cloth.v
Answer:

Let the cost of cloth required be x.Cost and length are in direct proportion.

Q.9The weight of 72 books is 9 kg. What is the weight of 40 such books (using unitary method)v
Answer:

Weight of 72 books = 9 kg = 9000 g
∴ Weight of 1 book = \(\frac{9000}{72}\) = 125 g
∴ Weight of 40 books = 125 × 40 g = 5000 g = 5 kg.
Weight of 40 books = 5 kg

Q.10Thamarai pages ₹ 7500 as rent for 3 months. With the same rate how much does she have to pay for 1 year (using unitary method).v
Answer:

Rent paid by Thamarai for 3 months = ₹ 7500
∴ Rent paid for 1 month = \(\frac{7500}{3}\) = 2500
Rent paid for 1 year or 12 moths = 2500 × 12 = ₹ 30,000
For 1 year rent to be paid = ₹ 30,000

Q.11If 30 men can reap a field in 15 days, then in how many days can 20 men reap the same field? (using unitary method).v
Answer:

∴ 20 men can reap the field in 10 days.

Q.12Valli purchase 10 pens for ₹ 180 and Kamala boys 8 pens for ₹ 96. Can you say who bought the pen cheaper (using unitary method).v
Answer:

∴ Kamala bought the pen cheaper.

Q.13A motorbike requires 2 liters of petrol to cover 100 kilometres. How many liters of petrol will be required to cover 250 kilometers? (using unitary method).v
Answer:

To cover 100 km quantity of petrol required = 2 litres5 litres of petrol required to cover 250 km
Objective Type Questions

Q.14If the cost of 3 books is ₹ 90, then find the cost of 12 books. (i) ₹ 300 (ii) ₹ 320 (iii) ₹ 360 (iv) ₹ 400 v
Answer:

(iii) ₹ 360

Q.15If Mani buys 5 kg of potatoes for ₹ 75 then he can buy ₹ 105. (i) 6 (ii) 7 (iii) 8 (iv) 5 v
Answer:

(ii) 7

Q.1635 cycles were produced in 5 days by a company then ___ cycles will be produced in 21 days. (i) 150 (ii) 70 (iii) 100 (iv) 147 v
Answer:

(iv) 147

Q.17An aircraft can accommodate 280 people in 2 trips. It can take ______ trips to take 1400 people. (i) 8 (ii) 10 (iii) 9 (iv) 12v
Answer:

(ii) 10

Q.26 pumps are required to fill a water sump in 1 hr 30 minutes. What will be the time taken to fill the sump if one pump is switched off?v
Answer:

Let x be the required time takenTime taken in minutes 1 hr. 48m

Q.3A farmer has enough food for 144 ducks for 28 days. If he sells 32 ducks how long will the food last?v
Answer:

Let the required number of days be x.As the number of ducks decreases the food will last for more days.
∴ They are in inverse proportion. x 1 y 1 = x 2 y 2The food lasts for 36 days

Q.4It takes 60 days for 10 machines to dig a hole. Assuming that all machines work at the same speed, how long will it take 30 machines to dig the same hole?v
Answer:

Let the number of days required be x.As the number of machines increases it takes less days to complete the work
∴ They are in inverse proportion, x 1 y 1 = x 2 y 2It takes 20 days to dig the hole

Q.5Forty students stay in a hostel. They had food stock for 30 days. If the students are doubled then for how many days the stock will last?v
Answer:

Let the required number of days be x.As the number of students increases the food last for less number of days
∴ They are in inverse proportion.The food stock lasts for 15 days

Q.6Meena had enough money to send 8 parcels each weighing 500 grams through a courier service. What would be the weight of each parcel, if she has to send 40 parcel for the same money?v
Answer:

Let the required weight of the parcel be x grams.As the number of parcels increases weight of a parcel decreases.
∴ They are in inverse proportion.Weight of each parcel = 100 grams

Q.7It takes 120 minutes to weed a garden with 6 gardeners. If the same work is to be done in 30minutes, how many more gardeners are needed?v
Answer:

Let the, number of gardeners needed be x.As the number of gardeners increases the time decreases. They are in inverse proportion,
x 1 y 1 = x 2 y 2∴ To complete the work in 30 min gardeners needed = 24
Already existing gardeners = 6
∴ More gardeners needed = 24 – 6 = 18
18 more gardeners are needed

Q.8Neelaveni goes by bicycle to her school every day. Her average speed is 12km/hr and she reaches school in 20 minutes. What is the increase in speed, If she reaches the school in 15 minutes?v
Answer:

Let the speed to reach school in 15 min be x∴ They are in inverse proportion x 1 y 1 = x 2 y 2If she reaches in 15 min the speed = 16 km/hr
Already running with 12 km / hr
∴ Increased speed = 16 – 12 = 4km / hr
Increase in speed = 4 km / hr

Q.9A toy company requires 36 machines to produce car toys in 54 days. How many machines would be required to produce the same number of car toys in 81 days?v
Answer:

Let the required number of machines be xAs the number of machines increases number of days required decreases.∴ 24 machines would be required
Objective Type Questions

Q.1012 cows can graze a field for 10 days. 20 cows can graze the same field for ____ days (i) 15 (ii) 18 (iii) 6 (iv) 8v
Answer:

(iii) 6
Hint:

Q.114 typists are employed to complete a work in 12 days. If two more typists are added, they will finish the same work in days (i) 7 (ii) 8 (iii) 9 (iv) 10v
Answer:

(ii) 8About Us
Privacy Policy
Disclaimer
Contact Us

Q.1If the cost of 7 kg of onions is ₹ 84 find the following : (i) Weight of the onions bought for ₹ 180 (ii) The cost of 3 kg of onionsv
Answer:

(i) For ₹ 84 weight of onion bought
for ₹ 1 weight of onion bought
∴ For ₹ 180 weight of onion bought w
∴ For ₹ 180 weight of onion bought
(ii) Cost of 7 kg of onions = 15 kg

Q.2If C = kd (i) what is the relation between C and d ? (ii) Find k when C = 30 and d = 6 (iii) Find C, when d = 10v
Answer:

As C increases d also increases
∴ It is direct proportion

Q.3Every 3 months Tamilselvan deposits ₹ 5000 as savings in his bank account. In how many years he can save ₹ 1,50,000.v
Answer:

Let the number of years required be x.No. of years and deposit are direct proportion as they both increases simultaneously.He can save ₹ 1,50,000 in \(7 \frac{1}{2}\) years.

Q.4A printer, prints a book of 300 pages at the rate of 30 pages per minute. Then, how long will it take to print the same book if the speed of the printer is 25 pages per minute?v
Answer:

Let the required time taken to print be x
As the speed increases time taken to print decreases
∴ They are in inverse proportion
Time taken to print 30 pages = 1 min

Q.5If the cost of 6 cans of juice in ₹ 210, then what will be the cost of 4 cans of juice?v
Answer:

Let the cost required be xAs number of cans increases cost also increases.
∴ They are in direct proportionx = 140
Cost of 4 cans of juice = 140

Q.6x varies inversely as twice of y. Given that when y = 6, the value of x is 4. Find the value of x when y = 8.v
Answer:

Given x varies inversely as twice of y.

Q.7A truck requires 108 litres of diesel for covering a distance of 594 km. How much diesel will be required to cover a distance of 1650 km?v
Answer:

Let the required distance be xAs the distance increases fuel quantity also increases.
∴ They are direct proportion.∴ The diesel required = 300 liters
Challenge Problems

Q.8If the cost of a dozen soaps is ₹ 396, what will be the cost of 35 such soaps?v
Answer:

1 dozen = 12
Cost of 12 soaps = ₹ 396

Q.9In a school there is 7 periods a day each of 45 minutes duration. How long each period is if the school has 9 periods a day assuming the number of hours to be the same?v
Answer:

Number of periods increases as duration decreases, since the number of hours is same.
Let the duration of each period be x.

Q.10Cost of 105 note books is ₹ 2415. How many notebooks can be bought for ₹ 1863?v
Answer:

For 2415 number of notebooks bought = 105

Q.1110 farmers can plough a field in 21 days. Find the number of days reduced if 14 farmers ploughed the same field?v
Answer:

Let the required number of days if 14 farmers ploughed = xAs number of farmers increases, number of days decreases.
∴ They are in inverse proportionInitially the farmers worked for 21 days. Now they worked for 15 days.
∴ The number of days reduced = 21 – 15 = 6 days

Q.12A flood relief camp has food stock by which 80 people can be benefited for 60 days. After 10 days 20 more people have joined the camp. Calculate the number of days of food shortage due to the addition of 20 more people?v
Answer:

As number of people increases food last for less number of days.Remaining food is to be used for 50 days.
But it only last for 40 days.
No. of days shortage = 50 – 40 = 10 days.
∴ 10 days of food shortage due to the addition of 20 more people.

Q.13Six men can complete a work in 12 days. Two days later, 6 more men joined them. How many days will they take to complete the remaining work?v
Answer:

As the number of men increases number of days increases.
∴ They are inversely proportionalx = 5 days
∴ Remaining work will be complete in 5 days
About Us
Privacy Policy
Disclaimer
Contact Us