Term 2 · Class 7 Maths · Chapter 1

Samacheer Class 7 Maths - Number System Intext Questions

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Chapter-wise textbook exercise answers for Number System Intext Questions with validation-aware solutions.

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Q.2Represent the following fractions in decimal form by converting denominator into ten or powers of 10. 7th Standard Maths Number System Exercise 1.1 Term 2 Chapter 1 Samacheer Kalviv
Solution

7th Maths Exercise 1.1 Samacheer Kalvi Term 2 Chapter 1 Number System Intext Questions

Answer:

7th Maths Exercise 1.1 Samacheer Kalvi Term 2 Chapter 1 Number System Intext Questions

Q.3Give any two life situations where we use decimal numbers.v
Solution

(i) Measuring weight of gold.
(ii) Weighing our height
(Try These Text book Page No. 3)

Answer:

(i) Measuring weight of gold.
(ii) Weighing our height
(Try These Text book Page No. 3)

Q.1Represent the following decimal numbers pictorially. (i) 5 ones and 3 tenths (ii) 6 tenths (iii) 7 ones and 9 tenths (iv) 6 ones and 4 tenths (v) Seven tenthsv
Solution

(i) 5 ones and 3 tenths
Samacheer Kalvi 7th Maths Term 2 Chapter 1 Number System Intext Questions
(ii) 6 tenths
7th Maths Guide Try These Solutions Term 2 Chapter 1 Number System Intext Questions Samacheer Kalvi
(iii) 7 ones and 9 tenths
Samacheer Kalvi 7th Maths Book Answers Solutions Term 2 Chapter 1 Number System Intext Questions
(iv) 6 ones and 4 tenths
7th Std Maths Guide Solutions Term 2 Chapter 1 Number System Intext Questions Samacheer Kalvi
(v) Seven tenths
Samacheer Kalvi 7th Term 2 Maths Solutions Chapter 1 Number System Intext Questions
(Try These Text book Page No. 5 & 6)

Answer:

(i) 5 ones and 3 tenths
Samacheer Kalvi 7th Maths Term 2 Chapter 1 Number System Intext Questions
(ii) 6 tenths
7th Maths Guide Try These Solutions Term 2 Chapter 1 Number System Intext Questions Samacheer Kalvi
(iii) 7 ones and 9 tenths
Samacheer Kalvi 7th Maths Book Answers Solutions Term 2 Chapter 1 Number System Intext Questions
(iv) 6 ones and 4 tenths
7th Std Maths Guide Solutions Term 2 Chapter 1 Number System Intext Questions Samacheer Kalvi
(v) Seven tenths
Samacheer Kalvi 7th Term 2 Maths Solutions Chapter 1 Number System Intext Questions
(Try These Text book Page No. 5 & 6)

Q.1Express the following decimal numbers in an expanded form and place value grid form. (i) 56.78 (ii) 123.32 (iii) 354.56v
Solution

(i) 56.78
(a) Expanded form
56.78 = 5 × 10 1 + 6 × 10 0 + 7 × 10 -1 + 8 × 10 -2
(b) Place value grid
Samacheer Kalvi 7 Maths Solutions Term 2 Chapter 1 Number System Intext Questions
(ii) 123.32
(a) Expanded form
123.32 = 1 × 10 2 + 2 × 10 1 + 3 × 10 0 + 3 × 10 -1 +2 × 10 -2
(b) Place value grid
Samacheer Kalvi 7th Standard Maths Solutions Term 2 Chapter 1 Number System Intext Questions
(iii) 354.56
(a) Expande form
354.56 = 3 × 10 2 + 5 × 10 1 + 4 × 10 0 + 5 × 10 -1 + 6 × 10 -2
(b) Place value grid
7th Maths 2nd Term Chapter 1 Number System Intext Questions Samacheer Kalvi

Answer:

(i) 56.78
(a) Expanded form
56.78 = 5 × 10 1 + 6 × 10 0 + 7 × 10 -1 + 8 × 10 -2
(b) Place value grid
Samacheer Kalvi 7 Maths Solutions Term 2 Chapter 1 Number System Intext Questions
(ii) 123.32
(a) Expanded form
123.32 = 1 × 10 2 + 2 × 10 1 + 3 × 10 0 + 3 × 10 -1 +2 × 10 -2
(b) Place value grid
Samacheer Kalvi 7th Standard Maths Solutions Term 2 Chapter 1 Number System Intext Questions
(iii) 354.56
(a) Expande form
354.56 = 3 × 10 2 + 5 × 10 1 + 4 × 10 0 + 5 × 10 -1 + 6 × 10 -2
(b) Place value grid
7th Maths 2nd Term Chapter 1 Number System Intext Questions Samacheer Kalvi

Q.3Write the following numbers in the place value grid and find the place value of the underlined digits. (i) 36. 3 7 (ii) 267.0 6 (iii) 0. 2 3 (iv) 27.6 9 (v) 53. 2 7v
Solution

7th Standard Maths Samacheer Kalvi Term 2 Chapter 1 Number System Intext Questions
(i) Place value of 3 in 36.37 is Tenths.
(ii) Place value of 6 in 267.06 is Hundredths.
(iii) Place value of 2 in 0.23 is Tenths.
(iv) Place value of 9 in 27.69 is Hundredths.
(v) Place value of 2 in 53.27 is Tenths.
Exercise 1.2
(Try These Text book Page No. 10)

Answer:

7th Standard Maths Samacheer Kalvi Term 2 Chapter 1 Number System Intext Questions
(i) Place value of 3 in 36.37 is Tenths.
(ii) Place value of 6 in 267.06 is Hundredths.
(iii) Place value of 2 in 0.23 is Tenths.
(iv) Place value of 9 in 27.69 is Hundredths.
(v) Place value of 2 in 53.27 is Tenths.
Exercise 1.2
(Try These Text book Page No. 10)

Q.1Convert the following fractions into the decimal numbers. (i) \(\frac { 16 }{ 1000 } \) (ii) \(\frac { 638 }{ 10 } \) (iii) \(\frac { 1 }{ 20 } \) (iv) \(\frac { 3 }{ 50 } \)v
Solution

(i) \(\frac { 16 }{ 1000 } \) = 0.016
(ii) \(\frac { 638 }{ 10 } \) = 63.8
(iii) \(\frac { 1 }{ 20 } \) = \(\frac{1 \times 5}{20 \times 5}\) = \(\frac { 5 }{ 100 } \) = 0.05
(iv) \(\frac { 3 }{ 50 } \) = \(\frac{3 \times 2}{50 \times 2}\) = \(\frac { 6 }{ 100 } \) = 0.06

Answer:

(i) \(\frac { 16 }{ 1000 } \) = 0.016
(ii) \(\frac { 638 }{ 10 } \) = 63.8
(iii) \(\frac { 1 }{ 20 } \) = \(\frac{1 \times 5}{20 \times 5}\) = \(\frac { 5 }{ 100 } \) = 0.05
(iv) \(\frac { 3 }{ 50 } \) = \(\frac{3 \times 2}{50 \times 2}\) = \(\frac { 6 }{ 100 } \) = 0.06

Q.2Write the fraction for each of the following: (i) 6 hundreds + 3 tens + 3 ones + 6 hundredths + 3 thousandths. (ii) 3 thousands + 3 hundreds + 4 tens + 9 ones + 6 tenths.v
Solution

(i) 6 hundreds + 3 tens + 3 ones + 6 hundreds + 3 thousandths.
= 6 × 100 + 3 × 10 + 3 × 1 + 0 × \(\frac { 1 }{ 10 } \) + 6 × \(\frac { 1 }{ 100 } \) + 3 × \(\frac { 1 }{ 1000 } \)
= 600 + 30 + 3 + 0 + \(\frac { 6 }{ 100 } \) + \(\frac { 3 }{ 1000 } \)
= 633 + 0.06 + 0.003
= 633.063
(ii) 3 thousands + 3 hundreds + 4 tens + 9 ones + 6 tenths.
= 3 × 1000 + 3 × 100 + 4 × 10 + 9 × 1 + 6 × \(\frac { 1 }{ 10 } \)
= 3000 + 300 + 40 + 9 + \(\frac { 6 }{ 10 } \)
= 3349 + 0.6
= 3349.6

Answer:

(i) 6 hundreds + 3 tens + 3 ones + 6 hundreds + 3 thousandths.
= 6 × 100 + 3 × 10 + 3 × 1 + 0 × \(\frac { 1 }{ 10 } \) + 6 × \(\frac { 1 }{ 100 } \) + 3 × \(\frac { 1 }{ 1000 } \)
= 600 + 30 + 3 + 0 + \(\frac { 6 }{ 100 } \) + \(\frac { 3 }{ 1000 } \)
= 633 + 0.06 + 0.003
= 633.063
(ii) 3 thousands + 3 hundreds + 4 tens + 9 ones + 6 tenths.
= 3 × 1000 + 3 × 100 + 4 × 10 + 9 × 1 + 6 × \(\frac { 1 }{ 10 } \)
= 3000 + 300 + 40 + 9 + \(\frac { 6 }{ 10 } \)
= 3349 + 0.6
= 3349.6

Q.3Convert the following decimals into fractions. (i) 0.0005 (ii) 6.24v
Solution

(i) 0.0005 = \(\frac { 5 }{ 10000 } \) = \(\frac{5 \div 5}{10000 \div 5}\) = \(\frac { 1 }{ 2000 } \)
(ii) 6.24 = \(\frac { 624 }{ 100 } \) = \(\frac{624 \div 4}{100 \div 4}\) = \(\frac { 156 }{ 25 } \)
Exercise 1.4
(Try These Text book Page No. 22)

Answer:

(i) 0.0005 = \(\frac { 5 }{ 10000 } \) = \(\frac{5 \div 5}{10000 \div 5}\) = \(\frac { 1 }{ 2000 } \)
(ii) 6.24 = \(\frac { 624 }{ 100 } \) = \(\frac{624 \div 4}{100 \div 4}\) = \(\frac { 156 }{ 25 } \)
Exercise 1.4
(Try These Text book Page No. 22)

Q.1Mark the following decimal numbers on the number line. (i) 0.3 (ii) 1.7 (iii) 2.3v
Solution

(i) 0.3
We know that 0.3 is more than 0, but less than 1.
There are 3 tenths in it. Divide the unit lenght between O and 1 on the number line
into 10 equal parts and take 3 parts, which represent 0.3.
Samacheer Kalvi 7th Guide Maths Term 2 Chapter 1 Number System Intext Questions
(ii) 1.7
We know that 1.7 is more than 1, but less than 2.
There are one ones and 7 tenths in it. Divide the unit length between 1 and 2 on the number line into 10 equal parts and take 7 parts which represents 1.7 = 1 + 0.7
Samacheer Kalvi Maths 7th Standard Term 2 Chapter 1 Number System Intext Questions
(iii) We know that 2.3 is more than 2 and less than 3.
There are 2 ones and 3 tenths in it. Divide the unit length between 2 and 3 into 10 equal parts and take 3 parts, which represents 2.3 = 2 + 0.3
7th Maths Guide Term 2 Chapter 1 Number System Intext Questions Samacheer Kalvi

Answer:

(i) 0.3
We know that 0.3 is more than 0, but less than 1.
There are 3 tenths in it. Divide the unit lenght between O and 1 on the number line
into 10 equal parts and take 3 parts, which represent 0.3.
Samacheer Kalvi 7th Guide Maths Term 2 Chapter 1 Number System Intext Questions
(ii) 1.7
We know that 1.7 is more than 1, but less than 2.
There are one ones and 7 tenths in it. Divide the unit length between 1 and 2 on the number line into 10 equal parts and take 7 parts which represents 1.7 = 1 + 0.7
Samacheer Kalvi Maths 7th Standard Term 2 Chapter 1 Number System Intext Questions
(iii) We know that 2.3 is more than 2 and less than 3.
There are 2 ones and 3 tenths in it. Divide the unit length between 2 and 3 into 10 equal parts and take 3 parts, which represents 2.3 = 2 + 0.3
7th Maths Guide Term 2 Chapter 1 Number System Intext Questions Samacheer Kalvi

Q.2Identify any two decimal numbers between 2 and 3.v
Solution

2.5 and 2.9

Answer:

2.5 and 2.9

Q.3Write any decimal number which is greater than 1 and less than 2.v
Solution

1.7, 1.9, 1.6, ………………..
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Answer:

1.7, 1.9, 1.6, ………………..
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Contact Us
Facebook
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Copyright © 2026 Samacheer Kalvi Guru

Q.1Write the decimal numbers for the following pictorial representation of numbers. Samacheer Kalvi 7th Maths Solutions Term 2 Chapter 1 Number System 1.1 1v
Solution

(i) Tens 2 ones 2 tenths = 12.2
(ii) Tens 1 ones 3 tenths = 21.3

Answer:

(i) Tens 2 ones 2 tenths = 12.2
(ii) Tens 1 ones 3 tenths = 21.3

Q.2Express the following in cm using decimals. (i) 5 mm (ii) 9 mm (iii) 42 mm (iv) 8 cm 9 mm (v) 375 mmv
Solution

(i) 5 mm
1 mm = \(\frac { 1 }{ 10 } \) cm = 0.1 cm
5 mm = \(\frac { 5 }{ 10 } \) = 0.5 cm
(ii) 9 mm
1 mm = \(\frac { 1 }{ 10 } \) cm = 0.1 cm
9 mm = \(\frac { 9 }{ 10 } \) cm = 0.9 cm
(iii) 42 mm
1 mm = \(\frac { 1 }{ 10 } \) cm = 0.1 cm
42 mm = \(\frac { 42 }{ 10 } \) cm = 4.2 cm
(iv) 8 cm 9 mm
1 mm = \(\frac { 1 }{ 10 } \) cm = 0.1 cm
8 cm 9 mm = 8 cm + \(\frac { 9 }{ 10 } \) cm = 8.9 cm
(v) 375 mm
1 mm = \(\frac { 1 }{ 10 } \) cm = 0.1 cm
375 mm = \(\frac { 375 }{ 10 } \) cm = 37.5 cm
Samacheer Kalvi 7th Maths Solutions Term 2 Chapter 1 Number System Ex 1.1

Answer:

(i) 5 mm
1 mm = \(\frac { 1 }{ 10 } \) cm = 0.1 cm
5 mm = \(\frac { 5 }{ 10 } \) = 0.5 cm
(ii) 9 mm
1 mm = \(\frac { 1 }{ 10 } \) cm = 0.1 cm
9 mm = \(\frac { 9 }{ 10 } \) cm = 0.9 cm
(iii) 42 mm
1 mm = \(\frac { 1 }{ 10 } \) cm = 0.1 cm
42 mm = \(\frac { 42 }{ 10 } \) cm = 4.2 cm
(iv) 8 cm 9 mm
1 mm = \(\frac { 1 }{ 10 } \) cm = 0.1 cm
8 cm 9 mm = 8 cm + \(\frac { 9 }{ 10 } \) cm = 8.9 cm
(v) 375 mm
1 mm = \(\frac { 1 }{ 10 } \) cm = 0.1 cm
375 mm = \(\frac { 375 }{ 10 } \) cm = 37.5 cm
Samacheer Kalvi 7th Maths Solutions Term 2 Chapter 1 Number System Ex 1.1

Q.3Express the following in metres using decimals. (i) 16 cm (ii) 7 cm (iii) 43 cm (iv) 6 m 6 cm (v) 2 m 54 cmv
Solution

(i) 16 cm
1 cm = \(\frac { 1 }{ 100 } \) cm = 0.01 m
16 cm = \(\frac { 16 }{ 100 } \) m = 0.16 m
(ii) 7 cm
1 cm = \(\frac { 1 }{ 100 } \) cm = 0.01 m
1 cm = \(\frac { 7 }{ 100 } \) m = 0.07 m
(iii) 43 cm
1 cm = \(\frac { 1 }{ 100 } \) cm = 0.01 m
43 cm = \(\frac { 43 }{ 100 } \) m = 0.43 m
(iv) 6 m 6 cm
1 cm = \(\frac { 1 }{ 10 } \) m = 0.01 m
6 m 6 cm = 6 m + \(\frac { 6 }{ 100 } \) m = 6 m + 0.06 m = 6.06 m
(v) 2 mm 54 cm
1 cm = \(\frac { 1 }{ 100 } \) cm = 0.01 m
2 m 54 cm = 2 m + \(\frac { 54 }{ 100 } \) m = 2 m + 0.54 m = 2.54 m

Answer:

(i) 16 cm
1 cm = \(\frac { 1 }{ 100 } \) cm = 0.01 m
16 cm = \(\frac { 16 }{ 100 } \) m = 0.16 m
(ii) 7 cm
1 cm = \(\frac { 1 }{ 100 } \) cm = 0.01 m
1 cm = \(\frac { 7 }{ 100 } \) m = 0.07 m
(iii) 43 cm
1 cm = \(\frac { 1 }{ 100 } \) cm = 0.01 m
43 cm = \(\frac { 43 }{ 100 } \) m = 0.43 m
(iv) 6 m 6 cm
1 cm = \(\frac { 1 }{ 10 } \) m = 0.01 m
6 m 6 cm = 6 m + \(\frac { 6 }{ 100 } \) m = 6 m + 0.06 m = 6.06 m
(v) 2 mm 54 cm
1 cm = \(\frac { 1 }{ 100 } \) cm = 0.01 m
2 m 54 cm = 2 m + \(\frac { 54 }{ 100 } \) m = 2 m + 0.54 m = 2.54 m

Q.4Expand the following decimal numbers. (i) 37.3 (ii) 658.37 (iii) 237.6 (iv) 5678.358v
Solution

(i) 37.3 = 30 + 7 + \(\frac { 3 }{ 10 } \) = 3 × 10 1 + 7 × 10 0 + 3 × 10 -1
(ii) 658.37 = 600 + 50 + 8 + \(\frac { 3 }{ 10 } \) + \(\frac { 7 }{ 100 } \)
= 6 × 10 2 + 5 × 10 1 + 8 × 100 + 3 × 10 -1 + 7 × 10 -2
(iii) 237.6 = 200 + 30 + 7 + \(\frac { 6 }{ 10 } \)
= 2 × 10 2 + 3 × 10 1 + 7 × 10 0 + 6 × 10 -1
(iv) 5678.358 = 5000 + 600 + 70 + 8 + \(\frac { 3 }{ 10 } \) + \(\frac { 5 }{ 100 } \) + \(\frac { 8 }{ 1000 } \)
= 5 × 10 3 + 6 × 10 2 + 7 × 10 1 + 8 × 10 0 + 3 × 10 -1 + 5 × 10 -2 + 8 × 10 -3
Samacheer Kalvi 7th Maths Solutions Term 2 Chapter 1 Number System Ex 1.1

Answer:

(i) 37.3 = 30 + 7 + \(\frac { 3 }{ 10 } \) = 3 × 10 1 + 7 × 10 0 + 3 × 10 -1
(ii) 658.37 = 600 + 50 + 8 + \(\frac { 3 }{ 10 } \) + \(\frac { 7 }{ 100 } \)
= 6 × 10 2 + 5 × 10 1 + 8 × 100 + 3 × 10 -1 + 7 × 10 -2
(iii) 237.6 = 200 + 30 + 7 + \(\frac { 6 }{ 10 } \)
= 2 × 10 2 + 3 × 10 1 + 7 × 10 0 + 6 × 10 -1
(iv) 5678.358 = 5000 + 600 + 70 + 8 + \(\frac { 3 }{ 10 } \) + \(\frac { 5 }{ 100 } \) + \(\frac { 8 }{ 1000 } \)
= 5 × 10 3 + 6 × 10 2 + 7 × 10 1 + 8 × 10 0 + 3 × 10 -1 + 5 × 10 -2 + 8 × 10 -3
Samacheer Kalvi 7th Maths Solutions Term 2 Chapter 1 Number System Ex 1.1

Q.5Express the following decimal numbers in place value grid and write the place value of the underlined digit. (i) 53.61 (ii) 263.271 (iii) 17.39 (iv) 9.657 (v) 4972.068v
Solution

(i) 53.61
Samacheer Kalvi 7th Maths Solutions Term 2 Chapter 1 Number System 1.1 2
(ii) 263.271
Samacheer Kalvi 7th Maths Solutions Term 2 Chapter 1 Number System 1.1 3
(iii) 17.39
Samacheer Kalvi 7th Maths Solutions Term 2 Chapter 1 Number System 1.1 7
(iv) 9.657
Samacheer Kalvi 7th Maths Solutions Term 2 Chapter 1 Number System 1.1 5
(v) 4972.068
Samacheer Kalvi 7th Maths Solutions Term 2 Chapter 1 Number System 1.1 6
Samacheer Kalvi 7th Maths Solutions Term 2 Chapter 1 Number System Ex 1.1
Objective Type Questions

Answer:

(i) 53.61
Samacheer Kalvi 7th Maths Solutions Term 2 Chapter 1 Number System 1.1 2
(ii) 263.271
Samacheer Kalvi 7th Maths Solutions Term 2 Chapter 1 Number System 1.1 3
(iii) 17.39
Samacheer Kalvi 7th Maths Solutions Term 2 Chapter 1 Number System 1.1 7
(iv) 9.657
Samacheer Kalvi 7th Maths Solutions Term 2 Chapter 1 Number System 1.1 5
(v) 4972.068
Samacheer Kalvi 7th Maths Solutions Term 2 Chapter 1 Number System 1.1 6
Samacheer Kalvi 7th Maths Solutions Term 2 Chapter 1 Number System Ex 1.1
Objective Type Questions

Q.6The place value of 3 in 85.073 is _____ (i) tenths (ii) hundredths (iii) thousands (iv) thousandthsv
Solution

(iv) thousandths
Hint: 1000 g = 1 kg; 1 g = \(\frac { 1 }{ 1000 } \) kg

Answer:

(iv) thousandths
Hint: 1000 g = 1 kg; 1 g = \(\frac { 1 }{ 1000 } \) kg

Q.7To convert grams into kilograms, we have to divide it by (i) 10000 (ii) 1000 (iii) 100 (iv) 10v
Solution

(ii) 1000
Hint: 85.073 = 8 × 10 + 5 × 1 + 0 × \(\frac { 1 }{ 10 } \) + 7 × \(\frac { 1 }{ 100 } \) + 3 × \(\frac { 1 }{ 1000 } \)
Samacheer Kalvi 7th Maths Solutions Term 2 Chapter 1 Number System Ex 1.1

Answer:

(ii) 1000
Hint: 85.073 = 8 × 10 + 5 × 1 + 0 × \(\frac { 1 }{ 10 } \) + 7 × \(\frac { 1 }{ 100 } \) + 3 × \(\frac { 1 }{ 1000 } \)
Samacheer Kalvi 7th Maths Solutions Term 2 Chapter 1 Number System Ex 1.1

Q.8The decimal representation of 30 kg and 43 g is ____ kg. (i) 30.43 (ii) 30.430 (iii) 30.043 (iv) 30.0043v
Solution

(iii) 30.043
Hint: 30 kg and 43 g = 30 kg + \(\frac { 43 }{ 1000 } \) kg = 30 + 0.043 = 30.043

Answer:

(iii) 30.043
Hint: 30 kg and 43 g = 30 kg + \(\frac { 43 }{ 1000 } \) kg = 30 + 0.043 = 30.043

Q.9A cricket pitch is about 264 cm wide. It is equal to _____ m. (i) 26.4 (ii) 2.64 (iii) 0.264 (iv) 0.0264v
Solution

(ii) 2.64
Hint: 264 cm = \(\frac { 264 }{ 100 } \) m = 2.64 m
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Answer:

(ii) 2.64
Hint: 264 cm = \(\frac { 264 }{ 100 } \) m = 2.64 m
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Q.3Write the following decimal numbers in the place value table. (i) 25.178 (ii) 0.025 (iii) 428.001 (iv) 173.178 (v) 19.54v
Solution

(i) 25.178
Samacheer Kalvi 7th Maths Solutions Term 2 Chapter 1 Number System Ex 1.2 5
(ii) 0.025
Samacheer Kalvi 7th Maths Solutions Term 2 Chapter 1 Number System Ex 1.2 6
(iii) 428.001
Samacheer Kalvi 7th Maths Solutions Term 2 Chapter 1 Number System Ex 1.2 7
(iv) 173.178
Samacheer Kalvi 7th Maths Solutions Term 2 Chapter 1 Number System Ex 1.2 8
(v) 19.54
Samacheer Kalvi 7th Maths Solutions Term 2 Chapter 1 Number System Ex 1.2 9
Samacheer Kalvi 7th Maths Solutions Term 2 Chapter 1 Number System Ex 1.2

Answer:

(i) 25.178
Samacheer Kalvi 7th Maths Solutions Term 2 Chapter 1 Number System Ex 1.2 5
(ii) 0.025
Samacheer Kalvi 7th Maths Solutions Term 2 Chapter 1 Number System Ex 1.2 6
(iii) 428.001
Samacheer Kalvi 7th Maths Solutions Term 2 Chapter 1 Number System Ex 1.2 7
(iv) 173.178
Samacheer Kalvi 7th Maths Solutions Term 2 Chapter 1 Number System Ex 1.2 8
(v) 19.54
Samacheer Kalvi 7th Maths Solutions Term 2 Chapter 1 Number System Ex 1.2 9
Samacheer Kalvi 7th Maths Solutions Term 2 Chapter 1 Number System Ex 1.2

Q.4Write each of the following as decimal numbers. (i) 20 + 1 + \(\frac { 2 }{ 10 } \) + \(\frac { 3 }{ 100 } \) + \(\frac { 7 }{ 1000 } \) (ii) 3 + \(\frac { 8 }{ 10 } \) + \(\frac { 4 }{ 100 } \) + \(\frac { 5 }{ 1000 } \) (iii) 6 + \(\frac { 0 }{ 10 } \) + \(\frac { 0 }{ 100 } \) + \(\frac { 9 }{ 1000 } \) (iv) 900 + 50 + 6 + \(\frac { 3 }{ 100 } \) (v) \(\frac { 6 }{ 10 } \) + \(\frac { 3 }{ 100 } \) + \(\frac { 1 }{ 1000 } \)v
Solution

(i) 20 + 1 + \(\frac { 2 }{ 10 } \) + \(\frac { 3 }{ 100 } \) + \(\frac { 7 }{ 1000 } \) = 21 + 2 × \(\frac { 1 }{ 10 } \) + 3 × \(\frac { 1 }{ 100 } \) + 7 × \(\frac { 1 }{ 1000 } \) = 21.237
(ii) 3 + \(\frac { 8 }{ 10 } \) + \(\frac { 4 }{ 100 } \) + \(\frac { 5 }{ 1000 } \) = 3 + 8 × \(\frac { 1 }{ 10 } \) + 4 × \(\frac { 1 }{ 100 } \) + 5 × \(\frac { 1 }{ 1000 } \) = 3.845
(iii) 6 + \(\frac { 0 }{ 10 } \) + \(\frac { 0 }{ 100 } \) + \(\frac { 9 }{ 1000 } \) = 6 + 0 × \(\frac { 1 }{ 10 } \) + 0 × \(\frac { 1 }{ 100 } \) + 9 × \(\frac { 1 }{ 1000 } \) = 6.009
(iv) 900 + 50 + 6 + \(\frac { 3 }{ 100 } \) = 956 + 0 × \(\frac { 1 }{ 10 } \) + 3 × \(\frac { 1 }{ 100 } \) = 956.03
(v) \(\frac { 6 }{ 10 } \) + \(\frac { 3 }{ 100 } \) + \(\frac { 1 }{ 1000 } \) = 6 × \(\frac { 1 }{ 10 } \) + 3 × \(\frac { 1 }{ 100 } \) = 0.631

Answer:

(i) 20 + 1 + \(\frac { 2 }{ 10 } \) + \(\frac { 3 }{ 100 } \) + \(\frac { 7 }{ 1000 } \) = 21 + 2 × \(\frac { 1 }{ 10 } \) + 3 × \(\frac { 1 }{ 100 } \) + 7 × \(\frac { 1 }{ 1000 } \) = 21.237
(ii) 3 + \(\frac { 8 }{ 10 } \) + \(\frac { 4 }{ 100 } \) + \(\frac { 5 }{ 1000 } \) = 3 + 8 × \(\frac { 1 }{ 10 } \) + 4 × \(\frac { 1 }{ 100 } \) + 5 × \(\frac { 1 }{ 1000 } \) = 3.845
(iii) 6 + \(\frac { 0 }{ 10 } \) + \(\frac { 0 }{ 100 } \) + \(\frac { 9 }{ 1000 } \) = 6 + 0 × \(\frac { 1 }{ 10 } \) + 0 × \(\frac { 1 }{ 100 } \) + 9 × \(\frac { 1 }{ 1000 } \) = 6.009
(iv) 900 + 50 + 6 + \(\frac { 3 }{ 100 } \) = 956 + 0 × \(\frac { 1 }{ 10 } \) + 3 × \(\frac { 1 }{ 100 } \) = 956.03
(v) \(\frac { 6 }{ 10 } \) + \(\frac { 3 }{ 100 } \) + \(\frac { 1 }{ 1000 } \) = 6 × \(\frac { 1 }{ 10 } \) + 3 × \(\frac { 1 }{ 100 } \) = 0.631

Q.5Convert the following fractions into decimal numbers. (i) \(\frac { 3 }{ 10 } \) (ii) 3 \(\frac { 1 }{ 2 } \) (iii) 3 \(\frac { 3 }{ 5 } \) (iv) \(\frac { 3 }{ 2 } \) (v) \(\frac { 4 }{ 5 } \) (vi) \(\frac { 99 }{ 100 } \) (vii) 3 \(\frac { 19 }{ 25 } \)v
Solution

(i) \(\frac { 3 }{ 10 } \) = 0.3
(ii) 3 \(\frac { 1 }{ 2 } \) = \(\frac { 7 }{ 2 } \) = \(\frac{7 \times 5}{2 \times 5}\) = \(\frac { 35 }{ 10 } \) = 3.5
(iii) 3 \(\frac { 3 }{ 5 } \) = \(\frac { 18 }{ 5 } \) = \(\frac{18 \times 2}{5 \times 2}\) = \(\frac { 36 }{ 10 } \) = 3.6
(iv) \(\frac { 3 }{ 2 } \) = \(\frac{3 \times 5}{2 \times 5}\) = \(\frac { 15 }{ 10 } \) = 1.5
(v) \(\frac { 4 }{ 5 } \) = \(\frac{4 \times 2}{5 \times 2}\) = \(\frac { 8 }{ 10 } \) = 0.8
(vi) \(\frac { 99 }{ 100 } \) = 0.99
(vii) 3 \(\frac { 19 }{ 25 } \) = \(\frac { 94 }{ 25 } \) = \(\frac{94 \times 4}{25 \times 4}\) = \(\frac { 376 }{ 100 } \) = 3.76

Answer:

(i) \(\frac { 3 }{ 10 } \) = 0.3
(ii) 3 \(\frac { 1 }{ 2 } \) = \(\frac { 7 }{ 2 } \) = \(\frac{7 \times 5}{2 \times 5}\) = \(\frac { 35 }{ 10 } \) = 3.5
(iii) 3 \(\frac { 3 }{ 5 } \) = \(\frac { 18 }{ 5 } \) = \(\frac{18 \times 2}{5 \times 2}\) = \(\frac { 36 }{ 10 } \) = 3.6
(iv) \(\frac { 3 }{ 2 } \) = \(\frac{3 \times 5}{2 \times 5}\) = \(\frac { 15 }{ 10 } \) = 1.5
(v) \(\frac { 4 }{ 5 } \) = \(\frac{4 \times 2}{5 \times 2}\) = \(\frac { 8 }{ 10 } \) = 0.8
(vi) \(\frac { 99 }{ 100 } \) = 0.99
(vii) 3 \(\frac { 19 }{ 25 } \) = \(\frac { 94 }{ 25 } \) = \(\frac{94 \times 4}{25 \times 4}\) = \(\frac { 376 }{ 100 } \) = 3.76

Q.6Write the following decimals as fractions. (i) 2.5 (ii) 6.4 (iii) 0.75v
Solution

(i) 2.5 = 2 + \(\frac { 5 }{ 10 } \) = \(\frac { 25 }{ 10 } \)
(ii) 6.4 = 6 + \(\frac { 4 }{ 10 } \) = \(\frac { 64 }{ 10 } \)
(iii) 0.75 = 0 + \(\frac { 7 }{ 10 } \) + \(\frac { 5 }{ 100 } \) = \(\frac { 70+5 }{ 100 } \) = \(\frac { 75 }{ 100 } \)

Answer:

(i) 2.5 = 2 + \(\frac { 5 }{ 10 } \) = \(\frac { 25 }{ 10 } \)
(ii) 6.4 = 6 + \(\frac { 4 }{ 10 } \) = \(\frac { 64 }{ 10 } \)
(iii) 0.75 = 0 + \(\frac { 7 }{ 10 } \) + \(\frac { 5 }{ 100 } \) = \(\frac { 70+5 }{ 100 } \) = \(\frac { 75 }{ 100 } \)

Q.7Express the following decimals as fractions in lowest form. (i) 2.34 (ii) 0.18 (iii) 3.56v
Solution

(i) 2.34 = 2 + \(\frac { 34 }{ 100 } \) = 2 + \(\frac{34 \div 2}{100 \div 2}\) = 2 + \(\frac { 17 }{ 50 } \) = 2\(\frac { 17 }{ 50 } \) = \(\frac { 117 }{ 50 } \)
(ii) 0.18 = 0 + \(\frac { 18 }{ 100 } \) = \(\frac{18 \div 2}{100 \div 2}\) = \(\frac { 9 }{ 50 } \)
(iii) 3.56 = 3 + \(\frac { 56 }{ 100 } \) = 3 + \(\frac{56 \div 4}{100 \div 4}\) = 3 + \(\frac { 14 }{ 25 } \) = 3 \(\frac { 14 }{ 25 } \) = \(\frac { 89 }{ 25 } \)
Samacheer Kalvi 7th Maths Solutions Term 2 Chapter 1 Number System Ex 1.2
Objective Questions

Answer:

(i) 2.34 = 2 + \(\frac { 34 }{ 100 } \) = 2 + \(\frac{34 \div 2}{100 \div 2}\) = 2 + \(\frac { 17 }{ 50 } \) = 2\(\frac { 17 }{ 50 } \) = \(\frac { 117 }{ 50 } \)
(ii) 0.18 = 0 + \(\frac { 18 }{ 100 } \) = \(\frac{18 \div 2}{100 \div 2}\) = \(\frac { 9 }{ 50 } \)
(iii) 3.56 = 3 + \(\frac { 56 }{ 100 } \) = 3 + \(\frac{56 \div 4}{100 \div 4}\) = 3 + \(\frac { 14 }{ 25 } \) = 3 \(\frac { 14 }{ 25 } \) = \(\frac { 89 }{ 25 } \)
Samacheer Kalvi 7th Maths Solutions Term 2 Chapter 1 Number System Ex 1.2
Objective Questions

Q.83 + \(\frac { 4 }{ 100 } \) + \(\frac { 9 }{ 1000 } \) = ? (i) 30.49 (ii) 3049 9 (iii) 3.0049 (iv) 3.049v
Solution

(iv) 3.049
Hint: = 3 × 1 + \(\frac { 0 }{ 10 } \) + \(\frac { 4 }{ 100 } \) + \(\frac { 9 }{ 1000 } \) = 3.049

Answer:

(iv) 3.049
Hint: = 3 × 1 + \(\frac { 0 }{ 10 } \) + \(\frac { 4 }{ 100 } \) + \(\frac { 9 }{ 1000 } \) = 3.049

Q.9\(\frac { 3 }{ 5 } \) = _______ (i) 0.06 (ii) 0.006 (iii) 6 (iv) 0.6v
Solution

(iv) 0.6
Hint: \(\frac { 3 }{ 5 } \) = \(\frac{3 \times 2}{5 \times 2}\) = \(\frac { 6 }{ 10 } \) = 0.06
Samacheer Kalvi 7th Maths Solutions Term 2 Chapter 1 Number System Ex 1.2

Answer:

(iv) 0.6
Hint: \(\frac { 3 }{ 5 } \) = \(\frac{3 \times 2}{5 \times 2}\) = \(\frac { 6 }{ 10 } \) = 0.06
Samacheer Kalvi 7th Maths Solutions Term 2 Chapter 1 Number System Ex 1.2

Q.10The simplest form of 0.35 is (i) \(\frac { 35 }{ 1000 } \) (ii) \(\frac { 35 }{ 10 } \) (iii) \(\frac { 7 }{ 20 } \) (iv) \(\frac { 7 }{ 100 } \)v
Solution

(iii) \(\frac { 7 }{ 20 } \)
Hint: 0.35 = \(\frac { 35 }{ 100 } \) = \(\frac{35 \div 5}{100 \div 5}\) = \(\frac { 7 }{ 20 } \)
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Answer:

(iii) \(\frac { 7 }{ 20 } \)
Hint: 0.35 = \(\frac { 35 }{ 100 } \) = \(\frac{35 \div 5}{100 \div 5}\) = \(\frac { 7 }{ 20 } \)
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Q.1Compare the following decimal numbers and find out the smaller number. (i) 2.08,2.086 (ii) 0.99,1.9 (iii) 3.53,3.35 (iv) 5.05,5.50 (v) 123.5,12.35v
Solution

(i) 2.08, 2.086
Let us take 2.080, 2.086.
Comparing 2.08 and 2.086 the whole number part, tenths place digit and the digit in the hundredths place are equal.
Comparing the digits at thousandths place we get 0 < 6.
Therefore 2.08 < 2.086.
Smallest number is 2.08
(ii) 0.99, 1.9
Comparing 0.99 and 1.9.
First when we compare the digit in the whole number parts we get 0 < 1.
∴ 0.99 < 1.9 Smallest number is 0.99
(iii) 3.53,3.35
Comparing 3.53 and 3.35
Here the whole number parts of the given two numbers are equal.
Comparing the digits at tenths place, we get 3 < 5
∴ 3.35 < 3.53
Smallest number is 3.35
(iv) 5.05, 5.50
Comparing 5.05 and 5.50
Here the whole number parts of the given two numbers are equal.
Comparing the digits at tenths place, we get 0 < 5.
∴ 5.5 < 5.50
Smallest number is 5.05
(v) 123.5, 12.35
Comparing 123.5 and 12.35.
Comparing the whole number parts, we get 12 < 123
∴ 12.35 < 123.5
Smallest number is 12.35
Samacheer Kalvi 7th Maths Solutions Term 2 Chapter 1 Number System Ex 1.3

Answer:

(i) 2.08, 2.086
Let us take 2.080, 2.086.
Comparing 2.08 and 2.086 the whole number part, tenths place digit and the digit in the hundredths place are equal.
Comparing the digits at thousandths place we get 0 < 6.
Therefore 2.08 < 2.086.
Smallest number is 2.08
(ii) 0.99, 1.9
Comparing 0.99 and 1.9.
First when we compare the digit in the whole number parts we get 0 < 1.
∴ 0.99 < 1.9 Smallest number is 0.99
(iii) 3.53,3.35
Comparing 3.53 and 3.35
Here the whole number parts of the given two numbers are equal.
Comparing the digits at tenths place, we get 3 < 5
∴ 3.35 < 3.53
Smallest number is 3.35
(iv) 5.05, 5.50
Comparing 5.05 and 5.50
Here the whole number parts of the given two numbers are equal.
Comparing the digits at tenths place, we get 0 < 5.
∴ 5.5 < 5.50
Smallest number is 5.05
(v) 123.5, 12.35
Comparing 123.5 and 12.35.
Comparing the whole number parts, we get 12 < 123
∴ 12.35 < 123.5
Smallest number is 12.35
Samacheer Kalvi 7th Maths Solutions Term 2 Chapter 1 Number System Ex 1.3

Q.2Arrange the following in ascending order. (i) 2.35, 2.53, 5.32, 3.52, 3.25 (ii) 123.45, 123.54,125.43, 125.34,125.3v
Solution

(i) 2.35, 2.53, 5.32, 3.52, 3.25
Comparing the whole number parts of all the numbers 5 is the greatest and 5 > 3 > 2.
∴ Greatest number is 5.32
Next 3.52 and 3.25 are equal in their whole number.
So comparing their digits in tenths place, we get 5 > 2
So 3.52 > 3.25
Now comparing 2.35 and 2.53 their whole number parts also equal.
∴ Comparing the digit in tenths place we get
2.53 > 2.35 ……(2)
Ascending order :
2.35 < 2.53 < 3.25 < 3.52 < 5.32
(ii) 123.45, 123.54, 125.43, 125.34, 125.3
Comparing the whole number parts we have 123 is the smallest number and two numbers 123.45 and 123.54 have same whole number part.
So in 123.45 and 123.54 comparing their digits in the tenths place we get 4 < 5
∴ 123.45 < 123.54 …(1)
Now comparing the remaining numbers
125.43, 125.34, 125.3 they all have the same whole number part.
Comparing the numbers in the tenths place we have 3 < 4
∴ 125.43 is the greatest …(2)
Also tenths place value 3 = 3 in 125.34 and 125.3
Again comparing the hundredths place value in 125.34 and 125.3, we get
125.3 < 125.34 …(3)
From (1), (2) and (3) we have,
123.45 < 123.54 < 125.3 < 125.34 < 125.43
Samacheer Kalvi 7th Maths Solutions Term 2 Chapter 1 Number System Ex 1.3

Answer:

(i) 2.35, 2.53, 5.32, 3.52, 3.25
Comparing the whole number parts of all the numbers 5 is the greatest and 5 > 3 > 2.
∴ Greatest number is 5.32
Next 3.52 and 3.25 are equal in their whole number.
So comparing their digits in tenths place, we get 5 > 2
So 3.52 > 3.25
Now comparing 2.35 and 2.53 their whole number parts also equal.
∴ Comparing the digit in tenths place we get
2.53 > 2.35 ……(2)
Ascending order :
2.35 < 2.53 < 3.25 < 3.52 < 5.32
(ii) 123.45, 123.54, 125.43, 125.34, 125.3
Comparing the whole number parts we have 123 is the smallest number and two numbers 123.45 and 123.54 have same whole number part.
So in 123.45 and 123.54 comparing their digits in the tenths place we get 4 < 5
∴ 123.45 < 123.54 …(1)
Now comparing the remaining numbers
125.43, 125.34, 125.3 they all have the same whole number part.
Comparing the numbers in the tenths place we have 3 < 4
∴ 125.43 is the greatest …(2)
Also tenths place value 3 = 3 in 125.34 and 125.3
Again comparing the hundredths place value in 125.34 and 125.3, we get
125.3 < 125.34 …(3)
From (1), (2) and (3) we have,
123.45 < 123.54 < 125.3 < 125.34 < 125.43
Samacheer Kalvi 7th Maths Solutions Term 2 Chapter 1 Number System Ex 1.3

Q.3Compare the following decimal numbers and find the greater number. (i) 24.5,20.32 (ii) 6.95,6.59 (iii) 17.3,17.8 (iv) 235.42,235.48 (v) 0.007,0.07 (vi) 4.571,4.578v
Solution

(i) 24.5, 20.32
Comparing the whole number part we get 24 > 20
∴ 24.5 > 20.32
greater number is 24.5
(ii) 6.95,6.59
Here the whole number part of given two numbers are equal.
Comparing the digits at tenths place we get 9 > 5.
∴ 6.95 > 6.59
Greater number is 6.95
(iii) 17.3,17.8
Here the whole number part of given two numbers are equal.
Comparing the digits at tenths place we get 8 > 3.
∴ 17.8 > 17.3
Greater number is 17.8
(iv) 235.42,235.48
Here the whole number part of given two numbers are equal.
Also the digits at tenths place also equal.
Comparing the digits at the hundredths place we get 8 > 4.
∴ 235.48 > 235.42
Greater number is 235.48
(v) 0.007,0.07
Here the whole number part of given two numbers are equal.
Also the digits at the tenths place also equal.
∴ Comparing the the digits at the hundredths place we get 7 > 0.
0. 07 > 0.007
greater number is 0.07.
(vi) 4.571,4.578
Here the whole number part of given two numbers are equal.
Also the digits at the tenths place and the hundredths place also equal.
Again comparing the digits in the thousandths place we get 8 > 1.
∴ 4.578 > 4.571
∴ Greater number is 4.578

Answer:

(i) 24.5, 20.32
Comparing the whole number part we get 24 > 20
∴ 24.5 > 20.32
greater number is 24.5
(ii) 6.95,6.59
Here the whole number part of given two numbers are equal.
Comparing the digits at tenths place we get 9 > 5.
∴ 6.95 > 6.59
Greater number is 6.95
(iii) 17.3,17.8
Here the whole number part of given two numbers are equal.
Comparing the digits at tenths place we get 8 > 3.
∴ 17.8 > 17.3
Greater number is 17.8
(iv) 235.42,235.48
Here the whole number part of given two numbers are equal.
Also the digits at tenths place also equal.
Comparing the digits at the hundredths place we get 8 > 4.
∴ 235.48 > 235.42
Greater number is 235.48
(v) 0.007,0.07
Here the whole number part of given two numbers are equal.
Also the digits at the tenths place also equal.
∴ Comparing the the digits at the hundredths place we get 7 > 0.
0. 07 > 0.007
greater number is 0.07.
(vi) 4.571,4.578
Here the whole number part of given two numbers are equal.
Also the digits at the tenths place and the hundredths place also equal.
Again comparing the digits in the thousandths place we get 8 > 1.
∴ 4.578 > 4.571
∴ Greater number is 4.578

Q.4Arrange the given decimal numbers in descending order. (i) 17.35, 71.53, 51.73, 73.51,37.51 (ii) 456.73, 546.37, 563.47, 745.63 457.71v
Solution

(i) 17.35,71.53,51.73,73.51,37.51
Comparing the whole number parts of the given numbers we get
73 > 71 > 51 > 37 > 17.
Descending order:
73.51,71.53,51.73,37.51, 17.35
(ii) 456.73, 546.37, 563.47, 745.63 457.71
Comparing the whole number parts of the given numbers from left to right we get
745 > 563 > 546 > 457 > 456
Descending Order: 745.63, 563.47, 546.37, 457.71, 456.73
Samacheer Kalvi 7th Maths Solutions Term 2 Chapter 1 Number System Ex 1.3
Objective Question

Answer:

(i) 17.35,71.53,51.73,73.51,37.51
Comparing the whole number parts of the given numbers we get
73 > 71 > 51 > 37 > 17.
Descending order:
73.51,71.53,51.73,37.51, 17.35
(ii) 456.73, 546.37, 563.47, 745.63 457.71
Comparing the whole number parts of the given numbers from left to right we get
745 > 563 > 546 > 457 > 456
Descending Order: 745.63, 563.47, 546.37, 457.71, 456.73
Samacheer Kalvi 7th Maths Solutions Term 2 Chapter 1 Number System Ex 1.3
Objective Question

Q.50.009 is equal to (i) 0.90 (ii) 0.090 (iii) 0.00900 (iv) 0.900v
Solution

(iii) 0.00900

Answer:

(iii) 0.00900

Q.637.70 [ ] 37.7 (i) = (ii) < (iii) > (iv) ≠v
Solution

(i) =

Answer:

(i) =

Q.778.56 [ ] 78.57 (i) < (ii) > (iii) = (iv) ≠v
Solution

(i) <
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Answer:

(i) <
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Q.2Represent the following decimal numbers on the number line. (i) 1.7 (ii) 0.3 (iii) 2.1v
Solution

(i) 1.7
We know that 1.7 is more than 1, but less than 2.
There are one ones and 7 tenths in it. Divide the unit length between 1 and 2 on the number line into 10 equal parts and take 7 parts which represents 1.7 = 1 + 0.7
Samacheer Kalvi 7th Maths Solutions Term 2 Chapter 1 Number System Ex 1.4 2
(ii) 0.3
We know that 0.3 is more than 0, but less than 1.
There are 3 tenths in it. Divide the unit lenght between 0 and 1 on the number line into 10 equal parts and take 3 parts, which represent 0.3.
Samacheer Kalvi 7th Maths Solutions Term 2 Chapter 1 Number System Ex 1.4 3
(iii) 2.1
We knowthat 2.1 is more than 2 and less than 3.
There are 2 ones and 1 tenths in it.
Divide the unit length between 2 and 3 into 10 equal parts and take 1 part, which represemt 2.1 = 2 + 0.1
Samacheer Kalvi 7th Maths Solutions Term 2 Chapter 1 Number System Ex 1.4 4

Answer:

(i) 1.7
We know that 1.7 is more than 1, but less than 2.
There are one ones and 7 tenths in it. Divide the unit length between 1 and 2 on the number line into 10 equal parts and take 7 parts which represents 1.7 = 1 + 0.7
Samacheer Kalvi 7th Maths Solutions Term 2 Chapter 1 Number System Ex 1.4 2
(ii) 0.3
We know that 0.3 is more than 0, but less than 1.
There are 3 tenths in it. Divide the unit lenght between 0 and 1 on the number line into 10 equal parts and take 3 parts, which represent 0.3.
Samacheer Kalvi 7th Maths Solutions Term 2 Chapter 1 Number System Ex 1.4 3
(iii) 2.1
We knowthat 2.1 is more than 2 and less than 3.
There are 2 ones and 1 tenths in it.
Divide the unit length between 2 and 3 into 10 equal parts and take 1 part, which represemt 2.1 = 2 + 0.1
Samacheer Kalvi 7th Maths Solutions Term 2 Chapter 1 Number System Ex 1.4 4

Q.3Between which two whole numbers, the following decimal numbers lie? (i) 3.3 (ii) 2.5 (iii) 0.9v
Solution

(i) 3.3 – 3.3 lies between 3 and 4.
(ii) 2.5 – 2.5 lies between 2 and 3.
(iii) 0.9 – 0.9 lies between 0 and 1.

Answer:

(i) 3.3 – 3.3 lies between 3 and 4.
(ii) 2.5 – 2.5 lies between 2 and 3.
(iii) 0.9 – 0.9 lies between 0 and 1.

Q.4Find the greater decimal number in the following. (i) 2.3,3.2 (ii) 5.6,6.5 (iii) 1.2,2.1v
Solution

(i) 2.3, 3.2
Comparing the whole number parts of 2.3 and 3.2 we get 3 > 2.
3.2 > 2.3 – Greater number is 3.2
(ii) 5.6, 6.5
Comparing the whole number parts of 5.6 and 6.5, we get 6 > 5.
6.5 > 5.6 – Greater number is 6.5
(iii) 1.2, 2.1
Comparing the whole number parts of 1.2 and 2.1, we get 2 > 1.
2.1 > 1.2 – Greater number is 2.1
Samacheer Kalvi 7th Maths Solutions Term 2 Chapter 1 Number System Ex 1.4

Answer:

(i) 2.3, 3.2
Comparing the whole number parts of 2.3 and 3.2 we get 3 > 2.
3.2 > 2.3 – Greater number is 3.2
(ii) 5.6, 6.5
Comparing the whole number parts of 5.6 and 6.5, we get 6 > 5.
6.5 > 5.6 – Greater number is 6.5
(iii) 1.2, 2.1
Comparing the whole number parts of 1.2 and 2.1, we get 2 > 1.
2.1 > 1.2 – Greater number is 2.1
Samacheer Kalvi 7th Maths Solutions Term 2 Chapter 1 Number System Ex 1.4

Q.5Find the smaller decimal number in the following. (i) 25.3,25.03 (ii) 7.01,7.3 (iii) 5.6,6.05v
Solution

(i) 25.3, 25.03
The whole number parts of both the numbers are equal.
∴ Comparing the digits at tenths place we get 0 < 3.
∴ 25.03 < 25.3 – Smaller number 25.03
(ii) 7.01,7.3
The whole number parts of both the numbers are equal.
Comparing the digits at tenths place we get 0 < 3.
∴ 7.01 < 7.3 – Smaller number is 7.01.
(iii) 5.6, 6.05
Comparing the whole number parts, we get 5 < 6.
∴ 5.6 < 6.05 – Smaller number is 5.6
Samacheer Kalvi 7th Maths Solutions Term 2 Chapter 1 Number System Ex 1.4
Objective Question

Answer:

(i) 25.3, 25.03
The whole number parts of both the numbers are equal.
∴ Comparing the digits at tenths place we get 0 < 3.
∴ 25.03 < 25.3 – Smaller number 25.03
(ii) 7.01,7.3
The whole number parts of both the numbers are equal.
Comparing the digits at tenths place we get 0 < 3.
∴ 7.01 < 7.3 – Smaller number is 7.01.
(iii) 5.6, 6.05
Comparing the whole number parts, we get 5 < 6.
∴ 5.6 < 6.05 – Smaller number is 5.6
Samacheer Kalvi 7th Maths Solutions Term 2 Chapter 1 Number System Ex 1.4
Objective Question

Q.6Between which two whole numbers 1.7 lie? (i) 2 and 3 (ii) 3 and 4 (iii) 1 and 2v
Solution

(iii) 1 and 2

Answer:

(iii) 1 and 2

Q.7The decimal number which lies between 4 and 5 is _______ (i) 4.5 (ii) 2.9 (iii) 1.9v
Solution

(i) 4.5
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Answer:

(i) 4.5
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Q.1Write the following decimal numbers in the place value table. (i) 247.36 (ii) 132.105v
Solution

(i) 247.36
Samacheer Kalvi 7th Maths Solutions Term 2 Chapter 1 Number System Ex 1.5 1
(ii) 132.105
Samacheer Kalvi 7th Maths Solutions Term 2 Chapter 1 Number System Ex 1.5 2

Answer:

(i) 247.36
Samacheer Kalvi 7th Maths Solutions Term 2 Chapter 1 Number System Ex 1.5 1
(ii) 132.105
Samacheer Kalvi 7th Maths Solutions Term 2 Chapter 1 Number System Ex 1.5 2

Q.2Write each of the following as decimal number. (i) 300 + 5 + \(\frac { 7 }{ 10 } \) + \(\frac { 9 }{ 100 } \) + \(\frac { 2 }{ 100 } \) (ii) 1000 + 400 + 30 + 2 + \(\frac { 6 }{ 10 } \) + \(\frac { 7 }{ 100 } \)v
Solution

(i) 300 + 5 + \(\frac { 7 }{ 10 } \) + \(\frac { 9 }{ 100 } \) + \(\frac { 2 }{ 100 } \) = 305.792
(ii) 1000 + 400 + 30 + 2 + \(\frac { 6 }{ 10 } \) + \(\frac { 7 }{ 100 } \) = 1432.67
Samacheer Kalvi 7th Maths Solutions Term 2 Chapter 1 Number System Ex 1.5

Answer:

(i) 300 + 5 + \(\frac { 7 }{ 10 } \) + \(\frac { 9 }{ 100 } \) + \(\frac { 2 }{ 100 } \) = 305.792
(ii) 1000 + 400 + 30 + 2 + \(\frac { 6 }{ 10 } \) + \(\frac { 7 }{ 100 } \) = 1432.67
Samacheer Kalvi 7th Maths Solutions Term 2 Chapter 1 Number System Ex 1.5

Q.3Which is greater? (i) 0.888 (or) 0.28 (ii) 23.914 (or) 23.915v
Solution

(i) 0.888 (or) 0.28
The whole number parts is equal for both the numbers.
Comparing the digits in the tenths place we get, 8 > 2.
0.888 > 0.28 ∴ 0.888 is greater.
(ii) 23.914 or 23.915
The whole number part is equal in both the numbers.
Also the tenth place and hundredths place are also equal.
∴ Comparing the thousandths place, we get 5 > 4.
23.915 > 23.914 ∴ 23.915 is greater.

Answer:

(i) 0.888 (or) 0.28
The whole number parts is equal for both the numbers.
Comparing the digits in the tenths place we get, 8 > 2.
0.888 > 0.28 ∴ 0.888 is greater.
(ii) 23.914 or 23.915
The whole number part is equal in both the numbers.
Also the tenth place and hundredths place are also equal.
∴ Comparing the thousandths place, we get 5 > 4.
23.915 > 23.914 ∴ 23.915 is greater.

Q.4In a 25 m swimming competition, the time taken by 5 swimmers A, B, C, D and E are 15.7 seconds, 15.68 seconds, 15.6 seconds, 15.74 seconds and 15.67 seconds respectively. Identify the winner.v
Solution

The winner is one who took less time for swimming 25 m.
Comparing the time taken by A, B, C, D, E the whole number part is equal for all participants.
Comparing digit in tenths place we get 6 < 7.
∴ Comparing 15.68, 15.6, 15.67, that is comparing the digits in hundredths place we get 15.60 < 15.67 < 15.68
One who took 15.6 seconds is the winner. ∴ C is the winner.
Samacheer Kalvi 7th Maths Solutions Term 2 Chapter 1 Number System Ex 1.5

Answer:

The winner is one who took less time for swimming 25 m.
Comparing the time taken by A, B, C, D, E the whole number part is equal for all participants.
Comparing digit in tenths place we get 6 < 7.
∴ Comparing 15.68, 15.6, 15.67, that is comparing the digits in hundredths place we get 15.60 < 15.67 < 15.68
One who took 15.6 seconds is the winner. ∴ C is the winner.
Samacheer Kalvi 7th Maths Solutions Term 2 Chapter 1 Number System Ex 1.5

Q.5Convert the following decimal numbers into fractions (i) 23.4 (ii) 46.301v
Solution

(i) 23.4 = \(\frac { 234 }{ 10 } \) = \(\frac{234 \div 2}{10 \div 2}\) = \(\frac { 117 }{ 5 } \)
(ii) 46.301 = \(\frac { 46301 }{ 1000 } \)

Answer:

(i) 23.4 = \(\frac { 234 }{ 10 } \) = \(\frac{234 \div 2}{10 \div 2}\) = \(\frac { 117 }{ 5 } \)
(ii) 46.301 = \(\frac { 46301 }{ 1000 } \)

Q.6Express the following in kilometres using decimals, (i) 256 m (ii) 4567 mv
Solution

1 m = \(\frac { 1 }{ 1000 } \) km = 0.001 Km
(i) 256 m = \(\frac { 256 }{ 1000 } \) km = 0.256 km
(ii) 4567 m = \(\frac { 4567 }{ 1000 } \) km = 4.567 km

Answer:

1 m = \(\frac { 1 }{ 1000 } \) km = 0.001 Km
(i) 256 m = \(\frac { 256 }{ 1000 } \) km = 0.256 km
(ii) 4567 m = \(\frac { 4567 }{ 1000 } \) km = 4.567 km

Q.7There are 26 boys and 24 girls in a class. Express the fractions of boys and girls as decimal numbers.v
Solution

Boys = 26; Girls = 24; Total = 50
Fraction of boys = \(\frac { 26 }{ 50 } \) = \(\frac{26 \times 2}{50 \times 2}\) = \(\frac { 52 }{ 100 } \) = 0.52
Fraction of girls = \(\frac { 24 }{ 50 } \) = \(\frac{24 \times 2}{50 \times 2}\) = \(\frac { 48 }{ 100 } \) = 0.48
Challenge Problems

Answer:

Boys = 26; Girls = 24; Total = 50
Fraction of boys = \(\frac { 26 }{ 50 } \) = \(\frac{26 \times 2}{50 \times 2}\) = \(\frac { 52 }{ 100 } \) = 0.52
Fraction of girls = \(\frac { 24 }{ 50 } \) = \(\frac{24 \times 2}{50 \times 2}\) = \(\frac { 48 }{ 100 } \) = 0.48
Challenge Problems

Q.8Write the following amount using decimals. (i) 809 rupees 99 paise (ii) 147 rupees 70 paisev
Solution

100 paise = 1 rupee; 1 paise = \(\frac { 1 }{ 100 } \) rupee
(i) 809 rupees 99 paise = 809 rupees + \(\frac { 99 }{ 100 } \) rupees
= 809 + 0.99 rupees = ₹ 809.99
(ii) 147 rupees 70 paise = 147 rupees + \(\frac { 70 }{ 100 } \) rupees
= 147 rupees + 0.70 rupees = ₹ 147.70

Answer:

100 paise = 1 rupee; 1 paise = \(\frac { 1 }{ 100 } \) rupee
(i) 809 rupees 99 paise = 809 rupees + \(\frac { 99 }{ 100 } \) rupees
= 809 + 0.99 rupees = ₹ 809.99
(ii) 147 rupees 70 paise = 147 rupees + \(\frac { 70 }{ 100 } \) rupees
= 147 rupees + 0.70 rupees = ₹ 147.70

Q.9Express the following in metres using decimals. (i) 1328 cm (ii) 419 cmv
Solution

100 cm = 1 m; 1 cm = \(\frac { 1 }{ 100 } \) m
(i) 1328 cm = \(\frac { 1328 }{ 100 } \) m = 13.28 m
(ii) 419 cm = \(\frac { 419 }{ 100 } \) m = 4.19 m
Samacheer Kalvi 7th Maths Solutions Term 2 Chapter 1 Number System Ex 1.5

Answer:

100 cm = 1 m; 1 cm = \(\frac { 1 }{ 100 } \) m
(i) 1328 cm = \(\frac { 1328 }{ 100 } \) m = 13.28 m
(ii) 419 cm = \(\frac { 419 }{ 100 } \) m = 4.19 m
Samacheer Kalvi 7th Maths Solutions Term 2 Chapter 1 Number System Ex 1.5

Q.10Express the following using decimal notation. (i) 8 m 30 cm in metres (ii) 24 km 200 m in kilometresv
Solution

(i) 8 m 30 cm in metres
8 m + \(\frac { 30 }{ 100 } \) m = 8 m + 0.30 m = 8.30 m
(ii) 24 km 200 m in kilometres
24 km + \(\frac { 200 }{ 1000 } \) km = 24 km + 0.200 km = 24.200 km

Answer:

(i) 8 m 30 cm in metres
8 m + \(\frac { 30 }{ 100 } \) m = 8 m + 0.30 m = 8.30 m
(ii) 24 km 200 m in kilometres
24 km + \(\frac { 200 }{ 1000 } \) km = 24 km + 0.200 km = 24.200 km

Q.11Write the following fractions as decimal numbers. (i) \(\frac { 23 }{ 10000 } \) (ii) \(\frac { 421 }{ 100 } \) (iii) \(\frac { 37 }{ 10 } \)v
Solution

(i) \(\frac { 23 }{ 10000 } \) = 0.0023
(ii) \(\frac { 421 }{ 100 } \) = 4.21
(iii) \(\frac { 37 }{ 10 } \) = 3.7

Answer:

(i) \(\frac { 23 }{ 10000 } \) = 0.0023
(ii) \(\frac { 421 }{ 100 } \) = 4.21
(iii) \(\frac { 37 }{ 10 } \) = 3.7

Q.12Convert the following decimals into fractions and reduce them to the lowest form, (i) 2.125 (ii) 0.0005v
Solution

(i) 2.125 = \(\frac { 2125 }{ 1000 } \) = \(\frac{2125 \div 25}{1000 \div 25}\) = \(\frac { 85 }{ 40 } \) = \(\frac{85 \div 5}{40 \div 5}\) = \(\frac { 17 }{ 8 } \)
(ii) 0.0005 = \(\frac { 5 }{ 1000 } \) = \(\frac{5 \div 5}{10000 \div 5}\) = \(\frac { 1 }{ 2000 } \)

Answer:

(i) 2.125 = \(\frac { 2125 }{ 1000 } \) = \(\frac{2125 \div 25}{1000 \div 25}\) = \(\frac { 85 }{ 40 } \) = \(\frac{85 \div 5}{40 \div 5}\) = \(\frac { 17 }{ 8 } \)
(ii) 0.0005 = \(\frac { 5 }{ 1000 } \) = \(\frac{5 \div 5}{10000 \div 5}\) = \(\frac { 1 }{ 2000 } \)

Q.13Represent the decimal numbers 0.07 and 0.7 on a number line.v
Solution

Samacheer Kalvi 7th Maths Solutions Term 2 Chapter 1 Number System Ex 1.5 3
0.07 lies between 0.0 and 0.1
The unit space between 0 and 0.1 is divided into 10 equal parts and 7th part is taken. Also 0.7 lies between 0 and 1.
The unit space between 0 and 1 is divided into 10 equal parts, and the 7th part is taken.
Samacheer Kalvi 7th Maths Solutions Term 2 Chapter 1 Number System Ex 1.5

Answer:

Samacheer Kalvi 7th Maths Solutions Term 2 Chapter 1 Number System Ex 1.5 3
0.07 lies between 0.0 and 0.1
The unit space between 0 and 0.1 is divided into 10 equal parts and 7th part is taken. Also 0.7 lies between 0 and 1.
The unit space between 0 and 1 is divided into 10 equal parts, and the 7th part is taken.
Samacheer Kalvi 7th Maths Solutions Term 2 Chapter 1 Number System Ex 1.5

Q.14Write the following decimal numbers in words. (i) 4.9 (ii) 220.0 (iii) 0.7 (iv) 86.3v
Solution

(i) 4.9 = Four and nine tenths
(ii) 220.0 = Two hundred and twenty
(iii) 0.7 = Seven tenths
(iv) 86.3 = Eighty six and three tenths.

Answer:

(i) 4.9 = Four and nine tenths
(ii) 220.0 = Two hundred and twenty
(iii) 0.7 = Seven tenths
(iv) 86.3 = Eighty six and three tenths.

Q.15Between which two whole numbers the given numbers lie? (i) 0.2 (ii) 3.4 (iii) 3.9 (iv) 2.7 (v) 1.7 (vi) 1.3v
Solution

(i) 0.2 lies between 0 and 1.
(ii) 3.4 lies between 3 and 4.
(iii) 3.9 lies between 3 and 4.
(iv) 2.7 lies between 2 and 3.
(v) 1.7 lies between 1 and 2.
(vi) 1.3 lies between 1 and 2.
Samacheer Kalvi 7th Maths Solutions Term 2 Chapter 1 Number System Ex 1.5

Answer:

(i) 0.2 lies between 0 and 1.
(ii) 3.4 lies between 3 and 4.
(iii) 3.9 lies between 3 and 4.
(iv) 2.7 lies between 2 and 3.
(v) 1.7 lies between 1 and 2.
(vi) 1.3 lies between 1 and 2.
Samacheer Kalvi 7th Maths Solutions Term 2 Chapter 1 Number System Ex 1.5

Q.16By how much is \(\frac { 9 }{ 10 } \) km less than 1 km. Express the same in decimal form.v
Solution

Given measures are 1 km and \(\frac { 9 }{ 10 } \) km. i.e., 1 km and 0.9 km.
Difference = 1.0 – 0.9 = 0.1 km.
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Answer:

Given measures are 1 km and \(\frac { 9 }{ 10 } \) km. i.e., 1 km and 0.9 km.
Difference = 1.0 – 0.9 = 0.1 km.
About Us
Privacy Policy
Disclaimer
Contact Us
Facebook
Twitter
Pinterest
LinkedIn
Copyright © 2026 Samacheer Kalvi Guru