Yes
Think (Text book Page No. 73)
A circle has infinite number of lines of symmetry.
Try These (Text book Page No. 73)
Yes, it is symmetric about both the diagonals.Try These (Text book Page No. 74)
Order of symmetry : 6
Order of symmetry : 3
For an equilateral triangle order of rotational symmetry is 3.Think (Text book Page No. 74)
Yes, order of rotational symmetry is 2.
Try These (Text book Page No. 75)
(i) 8 →(ii) 5 → 3 ↑Think (Text book Page No. 78)
There is no right, left, up or down movement took place.
Try These (Text book Page No. 80)
About Us
Privacy Policy
Disclaimer
Contact Us
(i) 3 →, 4↑
(ii) 3 ←, 3↑
(iii) 4 ←, 4↓
(iv) 2 ←, 2↓
- A. Describe the translation of the pool of fish.
- B. Can the fishing boat make the same translation? Explain.
- C. Describe a translation the fishing boat could make to get to point D.
(a) Translation of pool of fish is 7 →, 2↓
(b) No, the fishing boat will be landed on the island if translated.
(c) To get point D, the translation will be 5 →, 3↓
(i) It is translation
(ii) Reflection about horizontal line.
(iii) Reflection about vertical line.
(iv) Rotation about the heel.
(i) Image of ∠L is ∠L’, Image of ∠M is ∠M’,
Image of ∠N is ∠N’, Image of ∠O is ∠O’
Image of vertex L is L’, Image of vertex M is ∠M’
Image of vertex N is ∠N’, Image of vertex O is O’
(ii) Corresponding sides are LM and L’M’, MN and M’N’, NO and N’O’ and OL and O’L’
(ii) Rotation
(iii) Reflection
(i) Translation
(ii) Rotation
(i) Translation
About Us
Privacy Policy
Disclaimer
Contact Us
(i) r = 4 cmStep 1 : Market a point ‘O’ on the paper.
Step 2 : Extended the compass distance equal to radius 4 cm.
Step 3 : At center ‘O’, helded the compass firmly and placed the pointed end of the compass.
Step 4 : Slowly rotated the compass around to get the circle.(ii) d = 12 cm
given d= 12 cm
∴ radius r = \(\frac { d }{ 2 } \) = \(\frac { 12 }{ 2 } \) = 6 cmStep 1: Marked a point ‘O’ on the paper.
Step 2: Extended the compass distance equal to radius 6 cm.
Step 3: At center ‘O’, held the compass firmly and placed the pointed end of the compass.
Step 4: Slowly rotated the compass around to get the circle.
(iii) r = 3.5 cmStep 1: Market a point ‘O’ on the paper.
Step 2: Extended the compass distance equal to radius 3.5 cm.
Step 3: At center ‘O’, held the compass firmly and placed the pointed end of the compass.
Step 4: Slowly rotated the compass around to get the circle.(iv) r = 6.5 cmStep 1: Market a point ‘O’ on the paper.
Step 2: Extended the compass distance equal to radius 6.5 cm.
Step 3: At center ‘O’, held the compass firmly and placed the pointed end of the compass.
Step 4: Slowly rotated the compass around to get the circle.
(v) d = 6 cm
∴ radius r = \(\frac { d }{ 2 } \) = \(\frac { 6 }{ 2 } \) = 3 cmStep 1: Market a point ‘O’ on the paper.
Step 2: Extended the compass distance equal to radius 3 cm.
Step 3: At center ‘O’, held the compass firmly and placed the pointed end of the compass.
Step 4: Slowly rotated the compass around to get the circle.
(i) r = 3 cm and r = 5 cm.Width of the circular ring = OB – OA = 5 – 3 = 2 cm
Step 1: Drawn a rough diagram and market the given measurements
Step2: Taken any point O and marked it as center.
Step 3: With O as center drawn a circle of radius OA = 3 cm.
Step 4: With O as center drawn a circle of radius OB = 5 cm. Thus concentric circles C 1 and C 2 are drawn.
Width of the circular ring = OB – OA = 5 – 3 = 2 cm(ii) r = 3.5 cm and r = 6.5 cmStep 1: Drawn a rough diagram and market the given measurements
Step 2: Taken any point O and marked it as the center.
Step 3: With O as center drawn a circle of radius OA = 3.5 cm.
Step 4: With O as center drawn a circle of radius OB = 6.5 cm. Thus the concentric circles C 1 and C 2 are drawn.
Width of the circular ring = OB – OA = 6.5 – 3.5 = 3 cm(iii) d = 6.4 cm and d = 11.6 cm
r = \(\frac { d }{ 2 } \)
r = \(\frac { 6.4 }{ 2 } \) = 3.2 cm; r = \(\frac { 11.6 }{ 2 } \) = 5.8 cmStep 1: Drawn a rough diagram and market the given measurements
Step 2: Taken any point O and marked it as the center.
Step 3: With O as center drawn a circle of radius OA =3.2 cm.
Step 4: With O as center and drawn a circle of radius OB = 5.8 cm. Thus the concentric circles C 1 and C 2 are drawn.
Width of the circular ring = OB – OA = 5.8 – 3.2 = 2.6 cm(iv) r = 5 cm and r = 7.5 cmStep 1 : Drawn a rough diagram and market the given measurements
Step 2 : Taken any point O and marked it as the center.
Step 3 : With O as center drawn a circle of radius OA = 5 cm.
Step 4 : With O as center drawn a circle of radius OB = 7.5 cm. Thus the concentric circles C 1 and C 2 are drawn.
Width of the circular ring = OB – OA = 7.5 – 5 = 2.5 cm
(v) d = 6.2 cm and r = 6.2 cm.
r = \(\frac { d }{ 2 } \)
∴ r = \(\frac { 6.2 }{ 2 } \) = 3.1 cm and r = 6.2 cmStep 1: Drawn a rough diagram and market the given measurements
Step 2: Taken any point O and marked it as the center.
Step 3: With O as center, drawn a circle of radius OA = 3.1 cm.
Step 4: With O as center, drawn a circle of radius OB = 6.2 cm.
Thus the concentric circles C 1 and C 2 are drawn.
Width of the circular ring = OB – OA = 6.2 – 3.1 = 3.1 cm(vi) r = 7.1 cm and d = 12 cm.
r = \(\frac { d }{ 2 } \)
∴ r = \(\frac { 12 }{ 2 } \) = 6 cm and r = 7.1 cmStep 1: Drawn a rough diagram and marked the given measurements
Step 2 : Taken any point O and marked it as center.
Step 3 : With O as center, drawn a circle of radius OA = 6 cm.
Step 4 : with O as center, drawn a circle of radius OB = 7.1 cm. Thus concentric circles
C 1 and C 2 are drawn.
Width of the circular ring = OB – OA = 7.1 – 6 = 1.1 cm
About Us
Privacy Policy
Disclaimer
Contact Us
Pawn – 1 ↑ or 2↑
Rook – 1 to 8 ↑
Knight – 2 →,1 ↑or 2 ←,1 ↑ or 1 →,2 ↑or 1 ←,2↑
Bishop – 1 →,1 ↑ or 2 →,2↑or 3 →,3↑ or 4 →,4↑ or 5 → 5 ↑1 ←,1↑ or 2 ←,2↑or 3 ←,3↑or 4 ←,4↑ or 5 ← 5↑
Queen – 1 to 8 ,1 →, 1 ↑ or 2 →,2↑ or 3 → ,3↑or 4 → ,4↑or 5 →,5↑or 1 ←,↑1 or 2 ←,2 ↑or
3 ←,3 ↑ or 4 ←,4 ↑ or 5 ← 5↑
King – 1 → or ← or ↑
(i) Essay Writing category shows translation
(ii) Essay Writing and Mono Acting categories shows reflection
(i) rotation
(ii) reflection
(iii) translation
(iv) reflection
(v) rotation
(vi) reflection
(vii) rotation
(viii) translationChallenge problems
.
2 ←,1↓ and then 1 ←, 2↓ (or) 2 ←, 1↓and then 1 ← ,2↓
(i) Translation 3 ←, 5↑ and 90° counter clockwise rotation about the green point and translates 5 ←, 2↓,
(ii) Translation 2 ← 90° counter clockwise rotation about the green point and translates 2 ←, 2↓.
Give radius of inner circle = 4.5 cm
Width of circular ring is 2.5 cm
Radius of outer circle = 4.5 + 2.5 = 7 cmStep 1 : Drawn a rough diagram and marked the given measurements
Step 2 : Taken any point O and marked it as the center.
Step 3 : With O as center and drawn a circle of radius OA = 4.5 cm.
Step 4 : With O as center drawn a circle of radius OB = 4.5 + 2.5 = 7 cm. Thus the concentric circles C 1 and C 2 are drawn.
Width of the circular ring = OB – OA
= 7 – 4.5 = 2.5 cm
Give radius of outer circle = 5.3 cm
Width of circular ring = 1.8 cm
Radius of the inner circle = 5.3 – 1.8
= 3.5 cmStep 1: Drawn a rough diagram and marked the given measurements
Step 2 : Taken any point O and marked it as the center.
Step 3 : With O as center drawn a circle of radius OA =3.5 cm.
Step 4 : With O as center, drawn a circle of radius OB = 5.3 cm. Thus concentric circles
C 1 and C 2 are drawn.
Width of the circular ring = OB – OA
= 5.3 – 3.5 = 1.8 cm
About Us
Privacy Policy
Disclaimer
Contact Us