Term 3 · Class 7 Maths · Chapter 4

Samacheer Class 7 Maths - Geometry Intext Questions

36 textbook Q&AFree Content

Chapter-wise textbook exercise answers for Geometry Intext Questions with step-by-step solutions.

📝 Don't just read — test yourselfFree flashcards + scored self-test · no sign-in
Your Progress - Chapter 40% complete
1Book Back Questions36 questions
Q.1Can you draw a shape which has no line of symmetry?v
Answer:

Yes

Q.2Draw all possible line of symmetry for the following shapes.v
Answer:

Think (Text book Page No. 73)

Q.3What can you say about the number of lines of symmetry of a circle?v
Answer:

A circle has infinite number of lines of symmetry.
Try These (Text book Page No. 73)

Q.4Reflect the words CHEEK, BIKE, BOX with horizontal line.v
Answer:

Q.5Will the figure be symmetric about both the diagonals?v
Answer:

Yes, it is symmetric about both the diagonals.Try These (Text book Page No. 74)

Q.6Find the order of rotational symmetry of the following figures. v
Answer:

Order of symmetry : 6
Order of symmetry : 3

Q.7Find the order of rotational symmetry for an equilateral triangle.v
Answer:

For an equilateral triangle order of rotational symmetry is 3.Think (Text book Page No. 74)

Q.8Can a parallelogram have a rotational symmetry?v
Answer:

Yes, order of rotational symmetry is 2.
Try These (Text book Page No. 75)

Q.9How is the pre-image A translated to image A’ in each of the following figures? (i) (ii) v
Answer:

(i) 8 →(ii) 5 → 3 ↑Think (Text book Page No. 78)

Q.10The pre-image and the image after a translation coincide. What can you say about the translationv
Answer:

There is no right, left, up or down movement took place.
Try These (Text book Page No. 80)

Q.11Reflect the shape with given line of reflection. v
Answer:

About Us
Privacy Policy
Disclaimer
Contact Us

Q.12How is the pre-image translated to the image? v
Answer:

(i) 3 →, 4↑
(ii) 3 ←, 3↑
(iii) 4 ←, 4↓
(iv) 2 ←, 2↓

Q.13Reflect the shape with given line of reflection v
Answer:

Q.14Reflect the shape in each of the following pictures with given line of reflection. v
Answer:

Q.15A pool of fish translates from point F to point D. v
  1. A. Describe the translation of the pool of fish.
  2. B. Can the fishing boat make the same translation? Explain.
  3. C. Describe a translation the fishing boat could make to get to point D.
Answer:

(a) Translation of pool of fish is 7 →, 2↓
(b) No, the fishing boat will be landed on the island if translated.
(c) To get point D, the translation will be 5 →, 3↓

Q.16Name the transformation that will map footprint A onto the indicated footprint. (i) Footprint B (ii) Footprint (iii) Footprint D (iv) Footprint Ev
Answer:

(i) It is translation
(ii) Reflection about horizontal line.
(iii) Reflection about vertical line.
(iv) Rotation about the heel.

Q.17In given diagram, the blue figure is an image of the pink figure. (i) Choose an angle or a vertex from the preimage and name its image. (ii) List all pairs of corresponding sides.v
Answer:

(i) Image of ∠L is ∠L’, Image of ∠M is ∠M’,
Image of ∠N is ∠N’, Image of ∠O is ∠O’
Image of vertex L is L’, Image of vertex M is ∠M’
Image of vertex N is ∠N’, Image of vertex O is O’
(ii) Corresponding sides are LM and L’M’, MN and M’N’, NO and N’O’ and OL and O’L’

Q.18A _______ is a turn about a point. (i) Translation (ii) Rotation (iii) Reflection (iv) Glide Reflectionv
Answer:

(ii) Rotation

Q.19A _______ is a flip over a line. (i) Translation (ii) Rotation (iii) Reflection (iv) Glide Reflectionv
Answer:

(iii) Reflection

Q.20A _______ is a slide; move without turning or flipping the shape. (i) Translation (ii) Rotation (iii) Reflection (iv) Glide Reflectionv
Answer:

(i) Translation

Q.21The transformation used in the picture is (i) Translation (ii) Rotation (iii) Reflection (iv) Glide Reflectionv
Answer:

(ii) Rotation

Q.22The transformation used in the picture is (i) Translation (ii) Rotation (iii) Reflection (iv) Glide Reflectionv
Answer:

(i) Translation

Q.23You must rotate the puzzle piece 270° clockwise about point P to fit it into a puzzle. Which piece fits in the puzzle as shown? v
Answer:

About Us
Privacy Policy
Disclaimer
Contact Us

Q.24Draw circles for the following measurements of radius (r)/ diameters(d). (i) r = 4 cm (ii) d = 12 cm (iii) r = 3.5 cm (iv) r = 6.5 cm. (v) d = 6 cmv
Answer:

(i) r = 4 cmStep 1 : Market a point ‘O’ on the paper.
Step 2 : Extended the compass distance equal to radius 4 cm.
Step 3 : At center ‘O’, helded the compass firmly and placed the pointed end of the compass.
Step 4 : Slowly rotated the compass around to get the circle.(ii) d = 12 cm
given d= 12 cm
∴ radius r = \(\frac { d }{ 2 } \) = \(\frac { 12 }{ 2 } \) = 6 cmStep 1: Marked a point ‘O’ on the paper.
Step 2: Extended the compass distance equal to radius 6 cm.
Step 3: At center ‘O’, held the compass firmly and placed the pointed end of the compass.
Step 4: Slowly rotated the compass around to get the circle.
(iii) r = 3.5 cmStep 1: Market a point ‘O’ on the paper.
Step 2: Extended the compass distance equal to radius 3.5 cm.
Step 3: At center ‘O’, held the compass firmly and placed the pointed end of the compass.
Step 4: Slowly rotated the compass around to get the circle.(iv) r = 6.5 cmStep 1: Market a point ‘O’ on the paper.
Step 2: Extended the compass distance equal to radius 6.5 cm.
Step 3: At center ‘O’, held the compass firmly and placed the pointed end of the compass.
Step 4: Slowly rotated the compass around to get the circle.
(v) d = 6 cm
∴ radius r = \(\frac { d }{ 2 } \) = \(\frac { 6 }{ 2 } \) = 3 cmStep 1: Market a point ‘O’ on the paper.
Step 2: Extended the compass distance equal to radius 3 cm.
Step 3: At center ‘O’, held the compass firmly and placed the pointed end of the compass.
Step 4: Slowly rotated the compass around to get the circle.

Q.25Draw concentric circles for the following measurements of radii / diameters. Find out the width of each circular ring. (i) r = 3 cm and r = 5 cm. (ii) r = 3.5 cm and r = 6.5 cm. (iii) d = 6.4 cm and d = 11.6 cm. (iv) r = 5 cm and r = 7.5 cm. (vi) r = 7.1 cm and d = 12 cm.v
Answer:

(i) r = 3 cm and r = 5 cm.Width of the circular ring = OB – OA = 5 – 3 = 2 cm
Step 1: Drawn a rough diagram and market the given measurements
Step2: Taken any point O and marked it as center.
Step 3: With O as center drawn a circle of radius OA = 3 cm.
Step 4: With O as center drawn a circle of radius OB = 5 cm. Thus concentric circles C 1 and C 2 are drawn.
Width of the circular ring = OB – OA = 5 – 3 = 2 cm(ii) r = 3.5 cm and r = 6.5 cmStep 1: Drawn a rough diagram and market the given measurements
Step 2: Taken any point O and marked it as the center.
Step 3: With O as center drawn a circle of radius OA = 3.5 cm.
Step 4: With O as center drawn a circle of radius OB = 6.5 cm. Thus the concentric circles C 1 and C 2 are drawn.
Width of the circular ring = OB – OA = 6.5 – 3.5 = 3 cm(iii) d = 6.4 cm and d = 11.6 cm
r = \(\frac { d }{ 2 } \)
r = \(\frac { 6.4 }{ 2 } \) = 3.2 cm; r = \(\frac { 11.6 }{ 2 } \) = 5.8 cmStep 1: Drawn a rough diagram and market the given measurements
Step 2: Taken any point O and marked it as the center.
Step 3: With O as center drawn a circle of radius OA =3.2 cm.
Step 4: With O as center and drawn a circle of radius OB = 5.8 cm. Thus the concentric circles C 1 and C 2 are drawn.
Width of the circular ring = OB – OA = 5.8 – 3.2 = 2.6 cm(iv) r = 5 cm and r = 7.5 cmStep 1 : Drawn a rough diagram and market the given measurements
Step 2 : Taken any point O and marked it as the center.
Step 3 : With O as center drawn a circle of radius OA = 5 cm.
Step 4 : With O as center drawn a circle of radius OB = 7.5 cm. Thus the concentric circles C 1 and C 2 are drawn.
Width of the circular ring = OB – OA = 7.5 – 5 = 2.5 cm
(v) d = 6.2 cm and r = 6.2 cm.
r = \(\frac { d }{ 2 } \)
∴ r = \(\frac { 6.2 }{ 2 } \) = 3.1 cm and r = 6.2 cmStep 1: Drawn a rough diagram and market the given measurements
Step 2: Taken any point O and marked it as the center.
Step 3: With O as center, drawn a circle of radius OA = 3.1 cm.
Step 4: With O as center, drawn a circle of radius OB = 6.2 cm.
Thus the concentric circles C 1 and C 2 are drawn.
Width of the circular ring = OB – OA = 6.2 – 3.1 = 3.1 cm(vi) r = 7.1 cm and d = 12 cm.
r = \(\frac { d }{ 2 } \)
∴ r = \(\frac { 12 }{ 2 } \) = 6 cm and r = 7.1 cmStep 1: Drawn a rough diagram and marked the given measurements
Step 2 : Taken any point O and marked it as center.
Step 3 : With O as center, drawn a circle of radius OA = 6 cm.
Step 4 : with O as center, drawn a circle of radius OB = 7.1 cm. Thus concentric circles
C 1 and C 2 are drawn.
Width of the circular ring = OB – OA = 7.1 – 6 = 1.1 cm
About Us
Privacy Policy
Disclaimer
Contact Us

Q.26Write a possible translation for each of chess piece for a single move. v
Answer:

Pawn – 1 ↑ or 2↑
Rook – 1 to 8 ↑
Knight – 2 →,1 ↑or 2 ←,1 ↑ or 1 →,2 ↑or 1 ←,2↑
Bishop – 1 →,1 ↑ or 2 →,2↑or 3 →,3↑ or 4 →,4↑ or 5 → 5 ↑1 ←,1↑ or 2 ←,2↑or 3 ←,3↑or 4 ←,4↑ or 5 ← 5↑
Queen – 1 to 8 ,1 →, 1 ↑ or 2 →,2↑ or 3 → ,3↑or 4 → ,4↑or 5 →,5↑or 1 ←,↑1 or 2 ←,2 ↑or
3 ←,3 ↑ or 4 ←,4 ↑ or 5 ← 5↑
King – 1 → or ← or ↑

Q.27Referring the graphic given, answer the following questions. Each bar of the category is made up of boy-girl-boy unit, (i) Which categories show a boy- girl-boy unit that is translation within the bar? (ii) Which categories show a boy-girl-boy unit that is reflected within the bar? v
Answer:

(i) Essay Writing category shows translation
(ii) Essay Writing and Mono Acting categories shows reflection

Q.28Describe the transformation involved in the following pair of figures (letters). Write translation, reflection or rotation. v
Answer:

(i) rotation
(ii) reflection
(iii) translation
(iv) reflection
(v) rotation
(vi) reflection
(vii) rotation
(viii) translationChallenge problems

Q.29In chess, a knight can move only in an L-shaped pattern: two vertical squares, then one horizontal square; two horizontal squares, then one vertical square; one vertical square, then two horizontal squares; or one horizontal square, then two vertical squares. Write a series of translations to move the knight from g8 to g5 (at most two moves)v
Answer:

.
2 ←,1↓ and then 1 ←, 2↓ (or) 2 ←, 1↓and then 1 ← ,2↓

Q.30The pink shape is congruent to blue shape. Describe a sequence of transformations in which the blue shape is the image of pink shape. v
Answer:

(i) Translation 3 ←, 5↑ and 90° counter clockwise rotation about the green point and translates 5 ←, 2↓,
(ii) Translation 2 ← 90° counter clockwise rotation about the green point and translates 2 ←, 2↓.

Q.31Draw concentric circles given that radius of inner circle is 4.5 cm and width of circular ring is 2.5 cm.v
Answer:

Give radius of inner circle = 4.5 cm
Width of circular ring is 2.5 cm
Radius of outer circle = 4.5 + 2.5 = 7 cmStep 1 : Drawn a rough diagram and marked the given measurements
Step 2 : Taken any point O and marked it as the center.
Step 3 : With O as center and drawn a circle of radius OA = 4.5 cm.
Step 4 : With O as center drawn a circle of radius OB = 4.5 + 2.5 = 7 cm. Thus the concentric circles C 1 and C 2 are drawn.
Width of the circular ring = OB – OA
= 7 – 4.5 = 2.5 cm

Q.32Draw concentric circles given that radius of outer circle is 5.3 cm and width of circular ring is 1.8 cm.v
Answer:

Give radius of outer circle = 5.3 cm
Width of circular ring = 1.8 cm
Radius of the inner circle = 5.3 – 1.8
= 3.5 cmStep 1: Drawn a rough diagram and marked the given measurements
Step 2 : Taken any point O and marked it as the center.
Step 3 : With O as center drawn a circle of radius OA =3.5 cm.
Step 4 : With O as center, drawn a circle of radius OB = 5.3 cm. Thus concentric circles
C 1 and C 2 are drawn.
Width of the circular ring = OB – OA
= 5.3 – 3.5 = 1.8 cm
About Us
Privacy Policy
Disclaimer
Contact Us