Samacheer Class 7 Maths - Geometry Intext Questions

1. A. Describe the translation of the pool of fish.
2. B. Can the fishing boat make the same translation? Explain.
3. C. Describe a translation the fishing boat could make to get to point D.

(a) Translation of pool of fish is 7 →, 2↓
(b) No, the fishing boat will be landed on the island if translated.
(c) To get point D, the translation will be 5 →, 3↓

(i) Image of ∠L is ∠L’, Image of ∠M is ∠M’,
Image of ∠N is ∠N’, Image of ∠O is ∠O’
Image of vertex L is L’, Image of vertex M is ∠M’
Image of vertex N is ∠N’, Image of vertex O is O’
(ii) Corresponding sides are LM and L’M’, MN and M’N’, NO and N’O’ and OL and O’L’

(i) r = 4 cm

Step 1 : Market a point ‘O’ on the paper.
Step 2 : Extended the compass distance equal to radius 4 cm.
Step 3 : At center ‘O’, helded the compass firmly and placed the pointed end of the compass.
Step 4 : Slowly rotated the compass around to get the circle.

(ii) d = 12 cm
given d= 12 cm
∴ radius r = \(\frac { d }{ 2 } \) = \(\frac { 12 }{ 2 } \) = 6 cm

Step 1: Marked a point ‘O’ on the paper.
Step 2: Extended the compass distance equal to radius 6 cm.
Step 3: At center ‘O’, held the compass firmly and placed the pointed end of the compass.
Step 4: Slowly rotated the compass around to get the circle.
(iii) r = 3.5 cm

Step 1: Market a point ‘O’ on the paper.
Step 2: Extended the compass distance equal to radius 3.5 cm.
Step 3: At center ‘O’, held the compass firmly and placed the pointed end of the compass.
Step 4: Slowly rotated the compass around to get the circle.

(iv) r = 6.5 cm

Step 1: Market a point ‘O’ on the paper.
Step 2: Extended the compass distance equal to radius 6.5 cm.
Step 3: At center ‘O’, held the compass firmly and placed the pointed end of the compass.
Step 4: Slowly rotated the compass around to get the circle.
(v) d = 6 cm
∴ radius r = \(\frac { d }{ 2 } \) = \(\frac { 6 }{ 2 } \) = 3 cm

Step 1: Market a point ‘O’ on the paper.
Step 2: Extended the compass distance equal to radius 3 cm.
Step 3: At center ‘O’, held the compass firmly and placed the pointed end of the compass.
Step 4: Slowly rotated the compass around to get the circle.

(i) r = 3 cm and r = 5 cm.

Width of the circular ring = OB – OA = 5 – 3 = 2 cm
Step 1: Drawn a rough diagram and market the given measurements
Step2: Taken any point O and marked it as center.
Step 3: With O as center drawn a circle of radius OA = 3 cm.
Step 4: With O as center drawn a circle of radius OB = 5 cm. Thus concentric circles C 1 and C 2 are drawn.
Width of the circular ring = OB – OA = 5 – 3 = 2 cm

(ii) r = 3.5 cm and r = 6.5 cm

Step 1: Drawn a rough diagram and market the given measurements
Step 2: Taken any point O and marked it as the center.
Step 3: With O as center drawn a circle of radius OA = 3.5 cm.
Step 4: With O as center drawn a circle of radius OB = 6.5 cm. Thus the concentric circles C 1 and C 2 are drawn.
Width of the circular ring = OB – OA = 6.5 – 3.5 = 3 cm

(iii) d = 6.4 cm and d = 11.6 cm
r = \(\frac { d }{ 2 } \)
r = \(\frac { 6.4 }{ 2 } \) = 3.2 cm; r = \(\frac { 11.6 }{ 2 } \) = 5.8 cm

Step 1: Drawn a rough diagram and market the given measurements
Step 2: Taken any point O and marked it as the center.
Step 3: With O as center drawn a circle of radius OA =3.2 cm.
Step 4: With O as center and drawn a circle of radius OB = 5.8 cm. Thus the concentric circles C 1 and C 2 are drawn.
Width of the circular ring = OB – OA = 5.8 – 3.2 = 2.6 cm

(iv) r = 5 cm and r = 7.5 cm

Step 1 : Drawn a rough diagram and market the given measurements
Step 2 : Taken any point O and marked it as the center.
Step 3 : With O as center drawn a circle of radius OA = 5 cm.
Step 4 : With O as center drawn a circle of radius OB = 7.5 cm. Thus the concentric circles C 1 and C 2 are drawn.
Width of the circular ring = OB – OA = 7.5 – 5 = 2.5 cm
(v) d = 6.2 cm and r = 6.2 cm.
r = \(\frac { d }{ 2 } \)
∴ r = \(\frac { 6.2 }{ 2 } \) = 3.1 cm and r = 6.2 cm

Step 1: Drawn a rough diagram and market the given measurements
Step 2: Taken any point O and marked it as the center.
Step 3: With O as center, drawn a circle of radius OA = 3.1 cm.
Step 4: With O as center, drawn a circle of radius OB = 6.2 cm.
Thus the concentric circles C 1 and C 2 are drawn.
Width of the circular ring = OB – OA = 6.2 – 3.1 = 3.1 cm

(vi) r = 7.1 cm and d = 12 cm.
r = \(\frac { d }{ 2 } \)
∴ r = \(\frac { 12 }{ 2 } \) = 6 cm and r = 7.1 cm

Step 1: Drawn a rough diagram and marked the given measurements
Step 2 : Taken any point O and marked it as center.
Step 3 : With O as center, drawn a circle of radius OA = 6 cm.
Step 4 : with O as center, drawn a circle of radius OB = 7.1 cm. Thus concentric circles
C 1 and C 2 are drawn.
Width of the circular ring = OB – OA = 7.1 – 6 = 1.1 cm
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Pawn – 1 ↑ or 2↑
Rook – 1 to 8 ↑
Knight – 2 →,1 ↑or 2 ←,1 ↑ or 1 →,2 ↑or 1 ←,2↑
Bishop – 1 →,1 ↑ or 2 →,2↑or 3 →,3↑ or 4 →,4↑ or 5 → 5 ↑1 ←,1↑ or 2 ←,2↑or 3 ←,3↑or 4 ←,4↑ or 5 ← 5↑
Queen – 1 to 8 ,1 →, 1 ↑ or 2 →,2↑ or 3 → ,3↑or 4 → ,4↑or 5 →,5↑or 1 ←,↑1 or 2 ←,2 ↑or
3 ←,3 ↑ or 4 ←,4 ↑ or 5 ← 5↑
King – 1 → or ← or ↑

(i) Translation 3 ←, 5↑ and 90° counter clockwise rotation about the green point and translates 5 ←, 2↓,
(ii) Translation 2 ← 90° counter clockwise rotation about the green point and translates 2 ←, 2↓.

Give radius of inner circle = 4.5 cm
Width of circular ring is 2.5 cm
Radius of outer circle = 4.5 + 2.5 = 7 cm

Step 1 : Drawn a rough diagram and marked the given measurements
Step 2 : Taken any point O and marked it as the center.
Step 3 : With O as center and drawn a circle of radius OA = 4.5 cm.
Step 4 : With O as center drawn a circle of radius OB = 4.5 + 2.5 = 7 cm. Thus the concentric circles C 1 and C 2 are drawn.
Width of the circular ring = OB – OA
= 7 – 4.5 = 2.5 cm

Give radius of outer circle = 5.3 cm
Width of circular ring = 1.8 cm
Radius of the inner circle = 5.3 – 1.8
= 3.5 cm

Step 1: Drawn a rough diagram and marked the given measurements
Step 2 : Taken any point O and marked it as the center.
Step 3 : With O as center drawn a circle of radius OA =3.5 cm.
Step 4 : With O as center, drawn a circle of radius OB = 5.3 cm. Thus concentric circles
C 1 and C 2 are drawn.
Width of the circular ring = OB – OA
= 5.3 – 3.5 = 1.8 cm
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Disclaimer
Contact Us
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Copyright © 2026 Samacheer Kalvi Guru