Ch 1Number System Intext Questions | Brain Grain (Term 1)
5-Mark Questions
Write the following integers in ascending order: -5,0,2,4, -6,10, -10
Plotting the points on the number line, we getThe numbers are placed in an increasing order from left to right. ∴ Ascending order: -10 < -6 < -5 < 0 < 2 < 4 < 10
Write the given integers in descending order, -27, 19, 0, 12, -4, -22, 47, 3, -9, -35.
Separating positive and the negative integers, we get -27, -4, -22, -9, -35 Arranging the numbers in descending order -4 > -9 > -22 > -27 > -35 The positive numbers are 19,12,47, 3 Arranging in descending order, we get 47 > 19 > 12 > 3 0 stands in the middle. ∴ Descending order: 47 > 19 > 12 > 3 > 0 > -4 > -9 > -22 > -27 > -35 (Try This Text Book Page No. 3)
2-Mark Questions
When Kala woke up, her body temperature was 102°F. She took medicine for fever. After 2 hours it was 2°F lower. What was her temperature then?
Kala’s temperature initially = 102°F After two hours the temperature decreased = -2°F Now the final temperature = 102°F – 2°F = 100°F
(-5) – (-18) (i) 23 (ii) -13 (iii) 13 (iv) -23
(iii) 131
(-100) – 0 + 100 = (i) 200 (ii) 0 (iii) 100 (iv)-200
(ii) 0 About Us Privacy Policy Disclaimer Contact Us
1-Mark Questions (MCQ)
Which of the following expressions is equal to -30. (i) -20 – (-5 × 2) (ii) (6 × 10) – (6× 5) (iii) (2 × 5)+ (4 × 5) (iv) (-6) × (+5)
(iv) (-6) × (+5) Hint: (i) -20 + (10) = -10 (ii) 60 – 30 = 30 (iii) 10 + 20 = 30 (iv) (-6) × (+5) = – 30
Ch 2Measurements Intext Questions | Brain Grain (Term 1)
5-Mark Questions
Explain the area of the parallelogram as sum of the areas of the two triangles.
ABCD is a parallelogram. It can be divided into two triangles of equal area by drawing the diagonal BD.Area of the parallelogram ABCD = base × height = AB × DE
A rectangle is a parallelogram but a parallelogram is not a rectangle. Why?
(i) For both rectangle and parallelogram (i) opposite sides are equal and parallel. (ii) For rectangle all angles equal to 90°. But for parallelogram opposite angles are equal. ∴ All rectangles are parallelograms. But all parallelograms are not rectan¬gles as their angles need not be equal to 90°. (Try These Textbook Page No. 36)
2-Mark Questions
Draw as many parallelograms as possible in a grid sheet with the area 20 square units each.
Area of parallelogram (a), (b) or (c) = 20 sq. units Exercise 2.2 Rhombus (Try These Textbook Page No. 41)
Can you find the perimeter of the rhombus?
If we know the length of one side we can find the perimeter using 4 × side units.
Can diagonals of a rhombus be of the same length?
When the diagonals of a rhombus become equal it become a square.
1-Mark Questions (MCQ)
Count the squares and find the area of the following parallelograms by converting those into rectangles of the same area. (Without changing the base and height).
Converting the given parallelograms into rectangles we get.(a) 10 sq. units (b) 18 sq. units (c) 16 sq. units (d) 5 sq. units
Ch 3Algebra Intext Questions | Brain Grain (Term 1)
5-Mark Questions
Fing the numerical co-efficient of each of the following terms: -3yx, 12k, y, 121bc, -x, 9pq, 2ab.
(i) Numerical co-efficient of-3yx is – 3 (ii) Numerical co-efficient of 12k is 12 (iii) Numerical coefficient of y is 1 (iv) Numerical co-efficient of 1216c is 121 (v) Numerical co-efficient of – x is – 1 (vi) Numerical co-efficient of 9pq is 9 (vii) Numerical co-efficient of 2ab is 2
If x = 2 andy = 3, then find the value of the following expressions, (i) 2x – 3y (ii) x + y (iii) 4y – x (iv) x + 1 – y
Given x = 2; y = 3. (i) 2x – 3y = 2 (2) – 3 (3) = 4 – 9 = 4 + (Additive inverse of 9) = 4 +(-9) = -5 (ii) x + y = 2 + 3 = 5 (iii) 4y – x = 4 (3) – 2 = 12 – 2 = 10 (iv) x + 1 – y = 2 + 1 – 3 = 3 – 3 = 0 Objective Type Questions
2-Mark Questions
Identify the variable and constants among the following terms. a, 11 – 3x, xy, -89, -m, -n, 5, 5ab, -5 3y, 8pqr, 18, -9t, -1, -8
Variable : a, -3x, xy, -m, -n, 5ab, 3y, -9t, 8pqr Constants : 11, -89, 5, -5, 18, -1, -8
Write the variables, constants and terms of the following expressions, (i) 18 + x – y (ii) 7p – 4q + 5 (iii) 29x + 13y (iv) b + 2
Identify the like terms among the following 7x, 5y, -8x, 12y, 6z, z, -12x, -9y, 11 z
Ch 4Direct and Inverse Proportion Intext Questions
5-Mark Questions
Find the ratio (i) 555 g to 5 kg (ii) 21 km to 175 m.
(i) 1 kg = 1000 g ∴ 5 kg = 5000 g ∴ 555 g : 5 kg = 555 g : 5000 g = 111 : 1000 (ii) 21 km to 175m 1 km = 1000 m 21 km = 21 × 1000 = 21,000m ∴ 21 km : 175 m = 21000 : 175 = 120 : 1
Find the value of x in the following proportions : (i) 110 8: 88 (ii) x : 26 :: 5: 65
(i) Given 110 : x :: 8 : 88 Product of the means = Product of the extremes x × 8 = 110 × 88(ii) x : 26 :: 5 : 65 Product of the means = Product of the extremesTry this (Text Book Page No. 74)
2-Mark Questions
Think of an example in real life where two variable are inversely proportional.
Example of inverse proportion are (i) Men working and the amount of work. (ii) Speed and time to travel Try These (Text book Page No. 78)
Read the following examples and group them in two categories.
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A dozen bananas costs ₹ 20. What is the price of 48 bananas ?
Let the required price be ₹ x. As the number of bananas increases price also increases ∴ Number of bananas and cost are in direct proportion.
Ch 5Geometry Intext Questions | Brain Grain (Term 1)
5-Mark Questions
Look at the figure and answer the following questions. (i) Which line is parallel to AB. (ii) Name a line which intersect CD. (iii) Name the lines which are perpendicular to GH (iv) How many lines are parallel to IJ (v) Will EF intersect AB? Explain.
\(\overleftrightarrow { GH } \) is parallel to \(\overleftrightarrow { AB } \) (ii) \(\overleftrightarrow { IJ } \) and \(\overleftrightarrow { KL } \) intersect \(\overleftrightarrow { CD } \) (iii) \(\overleftrightarrow { IJ } \) and \(\overleftrightarrow { KL } \) are perpendicular to \(\overleftrightarrow { GH } \) (iv) Only one line \(\overleftrightarrow { KL } \) is parallel to \(\overleftrightarrow { IJ } \) (v) Yes, \(\overleftrightarrow { EF } \) will intersect \(\overleftrightarrow { AB } \) at some point. Try These (Text Book Page No. 85) Choose the correct answer
Observe the six angles marked in the picture shown. Write any four pairs of adjacent angles and that are not.
Four pairs of adjacent angles are 1. ∠A and ∠B 2. ∠B and ∠C 3. ∠C and ∠D 4. ∠D and ∠EFour pairs of non adjacent angles are. 1. ∠A and ∠C 2. ∠C and ∠F 3. ∠E and ∠D 4. ∠A and ∠F
2-Mark Questions
Identify the common arm, common vertex of the adjacent angles and shade the interior with two colours in each of the following figures.
(ii)
Draw a line which is not the transversal to the above figures.
How many transversals can you draw for the following two lines
Infinite number of transversals can be drawn.a, b, c, d, e, f, g are transversal to m and n. Try these (Text book Page No. 96)
1-Mark Questions (MCQ)
A straight angle measures
(c) 180° No, they are not adjacent pairs.
Ch 6Information Processing Intext Questions | Brain Grain (Term 1)
5-Mark Questions
Observe the pictures and answer the following. (i) Find all the possible routes from house to school via fire station. (ii) Find all the possible routes between central park and school with distance. Mention the shortest route? (iii) Calculate the shortest distance between bank and school.
(i) (a) House ➝ Fire station ➝ Library ➝ Central Park ➝ Hotel ➝ Fruit shop ➝ School. (b) House ➝ Fire station ➝ Library ➝ Fruit shop ➝ School. (c) House ➝ Fire station ➝ Library ➝ School. (ii) Possible routes between Central park and school and their distances are (a) School ➝ Fruit shop ➝ Hotel ➝ Central park. Distance ➝ (150 + 300 + 100)m = 550 m (b) School ➝ Fruit shop ➝ Library ➝ Central park Distance ➝(150 + 100 + 200)m = 450 m (c) School ➝ Library ➝ Central park Distance = (20 + 200 m) = 220 m (d) School ➝ Library ➝ Fire station ➝ House ➝ central park Distance = (20 + 50 + 300 + 150) m = …
Find the shortest route to Vivekanandar Memorial Hall from the Mandapam using the given map.
Possible routes from Mandapam to Vivekandar Memorial are route 1: (a) Mandapam ➝ Pullivasal Island ➝ Krusadai Island ➝ Vivekanandar Memorial Hall. Distance = 6 Km + 2 Km + 1.5 Km = 9.5 Km route 2: (b) Mandapam ➝ Krusadai Island ➝ Vivekanandar Memorial Hall. Distance = 7 Km + 1.5 Km = 8.5 Km 8.5 km < 9.5 km ∴ Shortest route : Mandapam ➝ Krusadai Island ➝ Vivekanandar Memorial Hall. Challenge Problems
2-Mark Questions
A tetromino is a shape obtained by …… squares together.
4
Draw a tetromino which passes symmetry ……..
Shade the figure completely, by using five tetrominoes shapes only once.
Ch 7Number System Intext Questions | Brain Grain (Term 2)
5-Mark Questions
Represent the following decimal numbers pictorially. (i) 5 ones and 3 tenths (ii) 6 tenths (iii) 7 ones and 9 tenths (iv) 6 ones and 4 tenths (v) Seven tenths
(i) 5 ones and 3 tenths(ii) 6 tenths(iii) 7 ones and 9 tenths(iv) 6 ones and 4 tenths(v) Seven tenths(Try These Text book Page No. 5 & 6)
Express the following decimal numbers in an expanded form and place value grid form. (i) 56.78 (ii) 123.32 (iii) 354.56
(i) 56.78 (a) Expanded form 56.78 = 5 × 10 1 + 6 × 10 0 + 7 × 10 -1 + 8 × 10 -2 (b) Place value grid(ii) 123.32 (a) Expanded form 123.32 = 1 × 10 2 + 2 × 10 1 + 3 × 10 0 + 3 × 10 -1 +2 × 10 -2 (b) Place value grid(iii) 354.56 (a) Expande form 354.56 = 3 × 10 2 + 5 × 10 1 + 4 × 10 0 + 5 × 10 -1 + 6 × 10 -2 (b) Place value grid
2-Mark Questions
Represent the following fractions in decimal form by converting denominator into ten or powers of 10.
Give any two life situations where we use decimal numbers.
(i) Measuring weight of gold. (ii) Weighing our height (Try These Text book Page No. 3)
Identify any two decimal numbers between 2 and 3.
2.5 and 2.9
Ch 8Measurements Intext Questions | Brain Grain (Term 2)
5-Mark Questions
If the radius of a bangle is 2 inches then find the diameter.
Given radius of the bangle = 2 inches Diameter = 2 × radius = 2 × 2 = 4 inchesExercise 2.2 Try These (Text book Page No. 33)
Draw circles of different radii on a graph paper. Find the area by counting the number of squares covered by the circle. Also find the area by using the formula. (i) Find the area of the circle, if the radius is 4.2 cm. (ii) Find the area of the circle if the diameter is 28 cm.
(i) Radius of the circle r = 4.2 cm Area of the circle A = π r 2 sq.units = \(\frac { 22 }{ 7 } \) × 4.2 × 4.2 cm 2 = 5.44 cm 2 (ii) Diameter of the circle d = 28 cm radius r = \(\frac { d }{ 2 } \) = \(\frac { 28 }{ 2 } \) = 14 cm Area of the circle A = π r 2 sq.units = \(\frac { 22 }{ 7 } \) × 14 × 14 cm 2 = 616 cm 2Exercise 2.3 Try These (Text book Page No. 35)
2-Mark Questions
Find the diameter of your bicycle wheel?
Diameter of my bicycle wheel is 700 mm
If the diameter of the circle is 14cm, what will be it’s radius?
diameter d = 14 cm radius = \(\frac { d }{ 2 } \) = \(\frac { 14 }{ 2 } \) = 7cm
Formula used to find the circumference of a circle is (i) 2πr units (ii) πr 2 + 2r units (iii) πr 2 sq. units (iv) πr 3 cu. units
(i) 2πr units
1-Mark Questions (MCQ)
Find the missing values in the following table for the circles with radius (r), diameter (d) and Circumference (C).
(i) Given radius r = 15cm ∴ diameter d = 2 × 15 = 30 cm Circumference C = π d units = \(\frac { 22 }{ 7 } \) × 30 = \(\frac { 660 }{ 7 } \) = 94.28 cm (ii) Given circumference C = 1760 cm 2πr = 1760 2 × \(\frac { 22 }{ 7 } \) × r = 1760 r = \(\frac{1760 \times 7}{2 \times 22}\) = \(\frac{160 \times 7}{2 \times 2}\) = 40 × 7 = 280 cm diameter = 2 × r = 2 × 280 = 560 cm (iii) diameter d = 24m radius r = \(\frac { d }{ 2 } \) = \(\frac { 24 }{ 2 } \) = 12 m Circumference C = 2 π r units = 2 × \(\frac { 22 }{ 7 } \) × 12 = \(\frac { 528 }{ 7 } \) = 75.4 m Tabulating the results
Ch 9Algebra Intext Questions | Brain Grain (Term 2)
5-Mark Questions
Simplify and write the following in exponential form. 1. 2 3 × 2 5 2. p 2 × P 4 3. x 6 × x 4 4. 3 1 × 3 5 × 3 4 5. (-1) 2 × (-1) 3 × (-1) 5
1. 2 3 × 2 5 = 2 3+5 = 2 8 [since a m × a n = a m+n ] 2. p 2 × p 4 = p 2+4 = p 6 [since a m × a n = a m+n ] 3. x 6 × x 4 = x 6 + 4 = x 10 [since a m × a n = a m+n ] 4. 3 1 × 3 5 × 3 4 = 3 1+5 × 3 4 [since a m × a n = a m+n ] = 3 6 × 3 4 [since a m × a n = a m+n ] = 3 10 5. (-1) 2 × (-1) 3 × (-1) 5 = (-1) 2+3 × (-1) 5 [Since a m × a n = a m+n ] = (-1) 5 × (-1) 5 = (-1) 5+5 [Since a m × a n = a m+n ] = (-1) 10Try These (Text book Page No. 48)
Simplify and write the following in exponent form. 1. (3 2 ) 3 2. [(-5) 3 ] 2 3. (20 6 ) 2 4. (10 3 ) 5
1. (3 2 ) 3 = 3 2×3 = 3 6 [since (a m ) n = a m×n ] 2. [(-5)] 2 = (-5) 3×2 = (-5) 6 [since (a m ) n = a m×n ] 3. (20 6 ) 2 = 20 6×2 = 20 12 [since (a m ) n = a m×n ] 4. (10 3 ) 5 = 10 3×5 = 10 15 [since (a m ) n = a m×n ]
2-Mark Questions
Simply the following. 1. 23 5 ÷ 23 2 2. 11 6 ÷ 11 3 3. (-5) 3 ÷ (-5) 2 4. 7 3 ÷ 7 3 5. 15 4 ÷ 15
Try These (Text book Page No. 48)
Simplify and express each of the following in exponential form: (i) 4 5 × 4 2 × 4 4 (ii) (3 2 × 3 3 ) 7 (iii) (5 2 × 5 8 ) ÷ 5 s (iv) 2 0 × 3 0 × 4 0 (v) \(\frac{5^{5} \times a^{8} \times b^{3}}{4^{3} \times a^{5} \times b^{2}}\)
Objective Type Questions
a × a × a × a × a equal to (i) a 5 (ii) 5 a (iii) 5a (iv) a + 5
(i) a 5
Ch 10Geometry Intext Questions | Brain Grain (Term 2)
5-Mark Questions
Can we have more than one right angle in a triangle?
No, we cannot have more than one right angle in a triangle. Because the sum of three angles of a triangle is 180°. But if two angles are right angles then their sum itself become 180°.
In a right triangle, what will be the sum of other two angles?
Sum of three angles of a triangle = 180° If one angle is right angle (i.e. 90°) . Sum of other two sides = 180° – 90° = 90°
2-Mark Questions
Each angle of an equilateral triangle is of measure.
same
How many obtuse angles are possible in a triangle?
Only one.
Can 30°, 60° and 90° be the angles of a triangle?
Given angles 30°, 60° and 90° Sum of the angles = 30° + 60° + 90° = 180° ∴ The given angles form a triangle.
1-Mark Questions (MCQ)
Which of the following can be the sides of a triangle? (i) 5.9.14 (ii) 7,7,15 (iii) 1,2,4 (iv) 3, 6, 8
(iv) 3, 6, 8 (i) Here 5 + 9 = 14 = the measure of the third side. In a triangle the sum of the measures of any two sides must be greater than the third side. ∴ 5, 9, 14 cannot be the sides of a triangle. (ii) 7.7.15 Here sum of two sides 7 + 7 = 14 < the measures of the thrid side. So 1,1, 15 cannot be the sides of a triangles. (iii) 1,2,4 Here sum of two sides 1 + 2 = 3 < the measure of the third side. ∴ 1, 2, 4 cannot be the sides of a triangle. (iv) 3, 6, 8 Sum of two sides 3 + 6 = 9 > the third side. ∴ 3, 6, 8 can be the sides of a triangle.
Ch 11Information Processing Intext Questions | Brain Grain (Term 2)
5-Mark Questions
Complete the given Pascal’s Triangle. Find the common property of the numbers filled by you. Can you relate this pattern with the pattern discussed in situation 2. Discuss.
Common Properties: The numbers filled by me are even numbers. Also they make triangular shape. Yes, this pattern and the pattern given in situation 2 have the same properties. About Us Privacy Policy Disclaimer Contact Us
Write the first five numbers in the third slanting row of the Pascal’s Triangle and find their squares. What do you infer?
Numbers in the 3rd slanding row are 1, 3, 6, 10, 15, 21,…. The squares are 1 2 , 3 2 , 6 2 , 10 2 . 15 2 , 21 2 ,…. = 1, 9, 36, 100, 225, 441,…From the above table we can conclude that the squares of the triangular numbers are the sum of cubes of natural numbers.Challenge Problems
2-Mark Questions
Observe the pattern given below. Continue the pattern for three more steps. Let, ‘x’ be the number of steps and ‘y’ be the number of match sticks. Tabulate the values of ‘x’ and ‘y’ and verify the relationship y = 7x + 5.
Three more patterns areFrom the table y = 7x + 5 is verified.Try These (Text book Page No. 92)
Observe the sequence of numbers obtained in the 3rd and 4th slanting rows of Pascal’s Triangle and find the difference between the consecutive numbers and complete the table given below.
Try These (Text book Page No. 96)
Match the given patterns of shapes with the appropriate number pattern and its generalization.
(i) (d) (ii) (a) (iii) (c) (iv) (c) (v) (b) Objective Type Questions
Ch 12Number System Intext Questions | Brain Grain (Term 3)
5-Mark Questions
Write the decimal number for the fraction 5 \(\frac { 1 }{ 5 } \)
5 \(\frac { 1 }{ 5 } \) = \(\frac { 26 }{ 5 } \) = \(\frac{26 \times 2}{5 \times 2}\) = \(\frac { 52 }{ 10 } \) = 5.2
Identify the biggest number : 0.567 and 0.576.
Comparing the digits of 0.567 and 0.576 from left to right, we have the tenths place same comparing the hundredths place 7 > 6. ⇒ 0.576 > 0.567
2-Mark Questions
Represent the fraction \(\frac { 1 }{ 4 } \) in decimal form
\(\frac { 1 }{ 4 } \) = \(\frac{1 \times 25}{4 \times 25}\) = \(\frac { 25 }{ 100 } \) = 0.25
What is the place value of 5 in 63.257.
Place value of 5 in 63.257 is 5 hundredths (Hundreth place)
Identify the digit in the tenth place of 75.036.
0
1-Mark Questions (MCQ)
Round the following decimal numbers upto 3 place of decimal
(a) 24.4003 Rounding 24.4003 upto 3 places of decimal means rounding to the nearest thousandths place. Underlining the digit in the thousandths place of 24.4003 gives 24.40 0 3. In 24.40 0 3 the digit next to the thousandths value is 3 which is less than 5. ∴ The underlined digit remains the same. So the rounded value of24.4003 upto 3 places of decimal is 24.400. (b) 1251.2345 Rounding 1251.2345 upto 3 places of decimal means rounding to the nearest thousandths place. …
Ch 13Percentage and Simple Interest Intext Questions
5-Mark Questions
Convert the fractions as percentage. (i) \(\frac { 1 }{ 20 } \) (ii) \(\frac { 13 }{ 25 } \) (iii) (i) \(\frac { 45 }{ 50 } \) (iv) \(\frac { 18 }{ 5 } \) (v) \(\frac { 27 }{ 10 } \) (vi) \(\frac { 72 }{ 90 } \)
(i) \(\frac { 1 }{ 20 } \) = \(\frac { 1 }{ 20 } \) × \(\frac { 100 }{ 100 } \) = \(\frac { 1 }{ 20 } \) × 100 % = 5 % (ii) \(\frac { 13 }{ 25 } \) = \(\frac { 13 }{ 25 } \) × \(\frac { 100 }{ 100 } \) = \(\frac { 13 }{ 25 } \) × 100 % = 52 % (iii) \(\frac { 45 }{ 50 } \) = \(\frac { 45 }{ 50 } \) × \(\frac { 100 }{ 100 } \) = \(\frac { 45 }{ 50 } \) × 100 % = 90 % (iv) \(\frac { 18 }{ 5 } \) = \(\frac { 18 }{ 5 } \) × \(\frac { 100 }{ 100 } \) = \(\frac { 18 }{ 50 } \) × 100 % = 360 % (iv) \(\frac { 27 }{ 10 } \) = \(\frac { 27 }{ 10 } \) × \(\frac { 100 }{ 100 } \) = \(\frac { 27 }{ 10 } \) …
Convert the following percentage as fractions. (i) 50% (ii) 75% (iii) 250% (iv) 30 \(\frac { 1 }{ 5 } \) % (v) \(\frac { 7 }{ 20 } \) % (vi) 90 %
(i) 50 % = \(\frac { 50 }{ 100 } \) = \(\frac { 5 }{ 10 } \) = \(\frac { 1 }{ 2 } \) (ii) 75 % = \(\frac { 75 }{ 100 } \) = \(\frac { 3 }{ 4 } \) (iii) 250 % = \(\frac { 250 }{ 100 } \) = \(\frac { 25 }{ 10 } \) = \(\frac { 5 }{ 2 } \) (iv) 30 \(\frac { 1 }{ 5 } \) % = \(\frac{30 \frac{1}{5}}{100}=\frac{\left(\frac{151}{5}\right)}{100}\) = \(\frac { 151 }{ 500 } \) (v) \(\frac { 7 }{ 20 } \) % = \(\frac{\frac{7}{20}}{100}=\frac{7}{20 \times 100}\) = \(\frac { 7 }{ 2000 } \) (vi) 90 % = \(\frac { 90 }{ 100 } \) = \(\frac { 9 }{ 10 } \)Think (Text book Page No. 32)
2-Mark Questions
Find the percentage of children whose scores fall in different categories given in table below.
Try These (Text book Page No. 29)
There are 50 students in class VII of a school. The number of students involved in these activities are : Scout: 7 Red Ribbon Club : 6 Junior Red Cross : 9 Green Force : 3 Sports : 14 Cultural activity : 11 Find the percentage of students who involved in various activities.
Try These (Text book Page No. 30)
What is the difference between 0.01 and 1%.
0.01 = \(\frac { 1 }{ 100 } \) = 1% 0.01 and 1% are the same.
Ch 14Algebra Intext Questions | Brain Grain (Term 3)
5-Mark Questions
Observe the following figures and try to find its area, geometrically. Also verify the same by multiplication of monomial.
Area of each box = xy Totally 12 boxes ∴ Total area = 12 × xy = 12xy Also multiplying the length 4x and breadth 3y We have area of the rectangle = 4x × 3y = 12xy (ii) Area of each small box = x 2 Total number of boxes = 3 ∴ Total area = 3x 2 Also length of the rectangle = 3x breadth of the rectangle = x Area of the rectangle = length × breadth = 3x × x = 3x 2 (iii) Area of each small box is ay, by, cy ∴ Total area = ay + by + cy = y (a + b + c) Area of the rectangle = length × breadth = (a + b + c) y (iv) Area of each small square = x 2 There are 4 small squares ∴ Total area of the given squar …
Consider a square shaped paddy field with side of 48 m. A pathway with uniform breadth is surrounded the square field and the length of the outer side is 52 m. Can you find the area of the pathway by using identities?
Let a = 52 b = 4(a – b) 2 = a 2 – 2ab + b 2 = 52 2 – 2 (52) (4) + 4 2 = 2704 – 416 + 16 = 2304 Think (Text book Page No. 60)
2-Mark Questions
Is it the only way to decompose the numbers representing length and breadth? Discuss.
No, for example 15 can be decompose into 1 × 15, 3 × 5, 5 × 3, 15 × 1Try These (Text book Page No. 52)
Let the length and breadth of a tile be x and y respectively. Using such tiles construct as many rectangles as you can and find out the length and breadth of the rectangles so formed such that its area is (i) 12 xy (ii) 8xy (iii) 9xy
Try These (Text book Page No. 58)
If a + b = 5 and a 2 + b 2 = 13, then ab = ? (i) 12 (ii) 6 (iii) 5 (iv) 13
(ii) 6 Hint: (a + b) 2 = 25 13 + 2ab = 25 2ab = 12 ab = 6
Ch 15Geometry Intext Questions | Brain Grain (Term 3)
5-Mark Questions
In given diagram, the blue figure is an image of the pink figure. (i) Choose an angle or a vertex from the preimage and name its image. (ii) List all pairs of corresponding sides.
(i) Image of ∠L is ∠L’, Image of ∠M is ∠M’, Image of ∠N is ∠N’, Image of ∠O is ∠O’ Image of vertex L is L’, Image of vertex M is ∠M’ Image of vertex N is ∠N’, Image of vertex O is O’ (ii) Corresponding sides are LM and L’M’, MN and M’N’, NO and N’O’ and OL and O’L’
Draw circles for the following measurements of radius (r)/ diameters(d). (i) r = 4 cm (ii) d = 12 cm (iii) r = 3.5 cm (iv) r = 6.5 cm. (v) d = 6 cm
(i) r = 4 cmStep 1 : Market a point ‘O’ on the paper. Step 2 : Extended the compass distance equal to radius 4 cm. Step 3 : At center ‘O’, helded the compass firmly and placed the pointed end of the compass. Step 4 : Slowly rotated the compass around to get the circle.(ii) d = 12 cm given d= 12 cm ∴ radius r = \(\frac { d }{ 2 } \) = \(\frac { 12 }{ 2 } \) = 6 cmStep 1: Marked a point ‘O’ on the paper. Step 2: Extended the compass distance equal to radius 6 cm. Step 3: At center ‘O’, held the compass firmly and placed the pointed end of the compass. …
2-Mark Questions
Can you draw a shape which has no line of symmetry?
Yes
Draw all possible line of symmetry for the following shapes.
Think (Text book Page No. 73)
What can you say about the number of lines of symmetry of a circle?
A circle has infinite number of lines of symmetry. Try These (Text book Page No. 73)
1-Mark Questions (MCQ)
A pool of fish translates from point F to point D.
(a) Translation of pool of fish is 7 →, 2↓ (b) No, the fishing boat will be landed on the island if translated. (c) To get point D, the translation will be 5 →, 3↓
Ch 16Statistics Intext Questions
5-Mark Questions
Collect the height of students of your class. Organise the data in ascending order.
Height of 15 students in our class. 130cm, 150 cm, 155 cm, 142 cm, 138 cm, 145 cm, 148 cm, 147 cm, 148cm, 143 cm, 141cm, 152 cm, 147 cm, 139 cm, 155 cm. Ascending order: 130cm, 138cm, 139cm, 141cm, 142cm, 143cm, 145cm, 147cm, 147cm, 148cm, 148 cm, 150cm, 152 cm, 155cm, 155cm.Try These (Text book Page No. 97) Find the Arithmetic Mean or average of the following data.
If the mean is increased by 2, then what happens to the individual observations.
Given number are 3, 6, 9, 12, 15If mean is increased by 2 then,Sum of observations = 5 × 11 = 55 Difference in sum = 55 – 45 = 10 ∴ Each number is increased by 2 if the mean is increased by 2.
2-Mark Questions
The study time spent by Kathir in a week is 3 hrs, 4 hrs, 5 hrs, 3 hrs, 4 hrs, 3:45 hrs; 4:15 hrs.
mean = 3 : 52 hrs
The marks scored by Muhil in five subjects are 75, 91, 48, 63, 51.
Arithmetic Mean = 65.6
Money spent on vegetables for five days is ₹ 120, ₹ 80, ₹ 75, ₹ 95 and ₹ 86.
Arithmetic Mean = 91.2 Think (Text book Page No. 99) Check the properties of arithmetic mean for the example given below:
Ch 17Information Processing Ex 6.1
5-Mark Questions
The steps of withdrawing cash from your saving bank account using ATM card are explained in the figures given below. Construct an appropriated flow chart.
Algorithm: (i) Swipe your bank Debit card / credit card.(ii) Select banking (iii) Select language (iv) Select transaction (v) Enter your PIN (vi) Enter the required amount (vii) Collect your money
A merchant calculates the cost price (CP) and the selling price (SP) of the product bought by him. Construct the flow chart to print ‘PROFIT’ if the selling price (SP) is more than the cost price (CP) or else ‘LOSS’.
First we have to input the cost price and selling price. Then we check whether cost price less than selling price. If S.P > CP, then print “PROFIT” otherwise print ‘Loss’. Algorithm: Enter cost price Enter selling price Checking whether CP < SP If Yes print ‘PROFIT’ If No print ‘Loss’About Us Privacy Policy Disclaimer Contact Us
2-Mark Questions
Using given step by step process to recharge mobile phone, draw a sequence flowchart. Step by Step process: Login the mobile recharge web browser Select prepaid or postpaid Enter mobile number Select operator and browse plans to choose your recharge plan Enter amount to recharge Proceed to recharge
Complete the direction of the flowchart using arrows for the flow chart explaining the traffic rule given below.
Complete the given flowchart, input names of things and check whether it is living or non – living.
Input name Horse Horse = a Yes Print Living thing
Frequently asked questions
- Write the following integers in ascending order: -5,0,2,4, -6,10, -10
- Plotting the points on the number line, we getThe numbers are placed in an increasing order from left to right. ∴ Ascending order: -10 < -6 < -5 < 0 < 2 < 4 < 10
- Write the given integers in descending order, -27, 19, 0, 12, -4, -22, 47, 3, -9, -35.
- Separating positive and the negative integers, we get -27, -4, -22, -9, -35 Arranging the numbers in descending order -4 > -9 > -22 > -27 > -35 The positive numbers are 19,12,47, 3 Arranging in descending order, we get 47 > 19 > 12 > 3 0 stands in the middle. ∴ Descending order: 47 > 19 > 12 > 3 > 0 > -4 > -9 > -22 > -27 > -35 (Try This Text Book Page No. 3)
- When Kala woke up, her body temperature was 102°F. She took medicine for fever. After 2 hours it was 2°F lower. What was her temperature then?
- Kala’s temperature initially = 102°F After two hours the temperature decreased = -2°F Now the final temperature = 102°F – 2°F = 100°F
- (-5) – (-18) (i) 23 (ii) -13 (iii) 13 (iv) -23
- (iii) 131
These important questions are selected from the Samacheer Kalvi Class 7 Maths textbook book-back exercises to help you revise the most useful questions. Mark weightage (5/2/1) follows the usual exam pattern and may vary by exam — always check your latest syllabus and question pattern. Open each chapter for the complete set of questions and answers.