⚡ Grade 9 Science · Physics

Samacheer Class 9 Science - Measurement

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Textbook Exercises
13 Sections
33 Questions

Complete Grade 9 Science questions and answers for Measurement. Click any question to expand the answer.

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📋 Sections in this chapter
I. Choose the Correct AnswerII. Fill in the BlanksIII. State Whether True or FalseIV. Match the FollowingV. Assertion and Reason Type QuestionsVI. Answer Very BrieflyVII. Answer BrieflyVIII. Answer in DetailIX. Numerical ProblemsIntext ActivitiesActivity – 1Activity – 2Additional Numerical Problems
Your Progress — Measurement0% complete
1I. Choose the Correct Answer4 questions
Q.1Choose the correct one.
✓ Answer
  • (a) mm < cm < m < km
  • (b) mm > cm > m > km
  • (c) km < m < cm < mm
  • (d) mm > m > cm > km

Answer:
(a) mm < cm < m < km


Q.2Rulers, measuring tapes and metre scales are used to measure
✓ Answer
  • (a) mass
  • (b) weight
  • (c) time
  • (d) length

Answer:
(d) length


Q.31 metric ton is equal to
✓ Answer
  • (a) 100 quintals
  • (b) 10 quintals
  • (c) 1/10 quintals
  • (d) 1/100 quintals

Answer:
(b) 10 quintals


Q.4Which among the following is not a device to measure mass?
✓ Answer
  • (a) Spring balance
  • (b) Beam balance
  • (c) Physical balance
  • (d) Digital balance

Answer:
(a) Spring balance



2II. Fill in the Blanks0 questions
  • Metre is the unit of length.
  • 1 kg of rice is weighed by beam balance.
  • Thickness of a cricket ball is measured by vernier caliper.
  • Radius of a thin wire is measured by screw gauge.
  • A physical balance measures small differences in mass up to 1 mg or less.


3III. State Whether True or False6 questions

If false, correct the statement.


Q.1The SI unit of electric current is kilogram.
✓ Answer

Answer: False

Correct Statement:
The SI unit of electric current is ampere.


Q.2Kilometre is one of the SI units of measurement.
✓ Answer

Answer: True


Q.3In everyday life, we use the term weight instead of mass.
✓ Answer

Answer: True


Q.4A physical balance is more sensitive than a beam balance.
✓ Answer

Answer: True


Q.5One Celsius degree is an interval of 1 K and zero degree Celsius is 273.15 K.
✓ Answer

Answer: True


Q.6With the help of vernier caliper we can have an accuracy of 0.1 mm and with screw gauge we can have an accuracy of 0.01 mm.
✓ Answer

Answer: True



4IV. Match the Following2 questions
Q.1Question 1
✓ Answer
QuantityUnit
Lengthmetre
Masskilogram
Timesecond
Temperaturekelvin

Q.2Question 2
✓ Answer
InstrumentUsed For
Screw gaugeCoins
Vernier caliperCricket ball
Beam balanceVegetables
Digital balanceGold ornaments


5V. Assertion and Reason Type Questions3 questions

Choose the correct answer:

  • (a) Both A and R are true but R is not the correct reason.
  • (b) Both A and R are true and R is the correct reason.
  • (c) A is true but R is false.
  • (d) A is false but R is true.

Q.1Question 1
✓ Answer

Assertion (A):
The scientifically correct expression is “The mass of the bag is 10 kg”.

Reason (R):
In everyday life, we use the term weight instead of mass.

Answer:
(a) Both A and R are true but R is not the correct reason.


Q.2Question 2
✓ Answer

Assertion (A):
0°C = 273.15 K. For convenience, it is rounded off to 273 K.

Reason (R):
To convert Celsius temperature into Kelvin, we add 273 to the given temperature.

Answer:
(b) Both A and R are true and R is the correct reason.


Q.3Question 3
✓ Answer

Assertion (A):
Distance between two celestial bodies is measured in terms of light year.

Reason (R):
The distance travelled by light in one year is one light year.

Answer:
(b) Both A and R are true and R is the correct reason.

Correction made:
The original answer marked as option (d) was incorrect.
A light year is indeed used to measure large astronomical distances.


6VI. Answer Very Briefly6 questions

Q.1Define measurement.
✓ Answer

Answer:
Measurement is the process of comparing a given physical quantity with a known standard quantity of the same nature.


Q.2Define standard unit.
✓ Answer

Answer:
A unit is a quantity of constant magnitude used to measure other quantities of the same nature.


Q.3What is the full form of SI system?
✓ Answer

Answer:
International System of Units.


Q.4Define least count of any device.
✓ Answer

Answer:
The least count of an instrument is the smallest measurement that can be measured accurately using that instrument.

Formulae:

For Vernier Caliper:

$$\text{Least Count} = \frac{\text{Value of one main scale division}}{\text{Total number of vernier scale divisions}}$$

For Screw Gauge:

$$\text{Least Count} = \frac{\text{Pitch}}{\text{Number of head scale divisions}}$$

Q.5What do you know about pitch of screw gauge?
✓ Answer

Answer:
Pitch of a screw gauge is the distance moved by the screw in one complete rotation.

$$\text{Pitch} = \frac{\text{Distance travelled on pitch scale}}{\text{Number of rotations}}$$

Q.6Can you find the diameter of a thin wire using a ruler?
✓ Answer

Answer:
No. A ruler is not accurate enough to measure the diameter of a thin wire. A screw gauge is used instead.



7VII. Answer Briefly4 questions

Q.1Write the rules followed while writing SI unit symbols.
✓ Answer

Answer:

  • Units named after scientists are written in lowercase letters.

Example: joule, kelvin, newton

  • Symbols are generally written in lowercase.

Example: m, kg, s

  • Symbols derived from scientists’ names are written in capital letters.

Example: N, J, C

  • Symbols are not followed by a full stop.

Example: 75 cm

  • Symbols are never written in plural form.

Example: 100 kg (not 100 kgs)


Q.2Write the need for a standard unit.
✓ Answer

Answer:
Standard units are needed to maintain uniformity and accuracy in measurements throughout the world.


Q.3Differentiate mass and weight.
✓ Answer
MassWeight
Fundamental quantityDerived quantity
Scalar quantityVector quantity
Amount of matter in a bodyGravitational force acting on a body
Constant everywhereVaries from place to place
Measured using physical balanceMeasured using spring balance
SI unit: kilogram (kg)SI unit: newton (N)

Q.4How will you measure the least count of vernier caliper?
✓ Answer

Answer:

$$\text{Least Count} = \frac{\text{Value of one main scale division}}{\text{Number of vernier scale divisions}}$$

It is the minimum value measured accurately using a vernier caliper.



8VIII. Answer in Detail2 questions

Q.1Explain a method to find the thickness of a hollow tea cup.
✓ Answer

Answer:

Procedure:
  • Determine the pitch and least count of the screw gauge.
  • Place the tea cup between the studs.
  • Rotate the ratchet until the cup is held gently.
  • Note the pitch scale reading (PSR).
  • Note the head scale coincidence (HSC).
  • Calculate thickness using:
$$\text{Thickness} = \text{PSR} + (\text{HSC} \times \text{LC})$$
  • Repeat readings at different positions and calculate the average.

Q.2How will you find the thickness of a one rupee coin?
✓ Answer

Answer:

Procedure:
  • Determine the pitch and least count of the screw gauge.
  • Place the coin between the studs.
  • Rotate the ratchet gently.
  • Note PSR and HSC.
  • Calculate thickness using:
$$\text{Thickness} = \text{PSR} + (\text{HSC} \times \text{LC})$$
  • Repeat readings and calculate the average value.


9IX. Numerical Problems4 questions

Q.1Light Year Problem
✓ Answer

Question:
Inian says one light year is (9.46 \times 10^{15}) m.
Ezhilan says it is (9.46 \times 10^{12}) km.
Who is correct?

Solution:

Both are correct because:

$$1 \text{ km} = 10^3 \text{ m}$$
$$9.46 \times 10^{15} \text{ m} = 9.46 \times 10^{12} \text{ km}$$

Q.2Radius of a Rubber Ball
✓ Answer

Given:

  • MSR = 7 cm
  • VC = 6
  • LC = 0.01 cm
Diameter:
$$D = \text{MSR} + (\text{VC} \times \text{LC})$$
$$D = 7 + (6 \times 0.01)$$
$$D = 7.06 \text{ cm}$$
Radius:
$$R = \frac{D}{2}$$
$$R = \frac{7.06}{2}$$
$$R = 3.53 \text{ cm}$$
Correction made:
Original answer incorrectly converted units to metres.

Q.3Thickness of a Five Rupee Coin
✓ Answer

Given:

  • PSR = 1 mm
  • HSC = 68
  • LC = 0.01 mm
Calculation:
$$\text{Thickness} = \text{PSR} + (\text{HSC} \times \text{LC})$$
$$= 1 + (68 \times 0.01)$$
$$= 1 + 0.68$$
$$= 1.68 \text{ mm}$$

Q.4Find the Mass of an Object Weighing 98 N
✓ Answer

Given:

$$W = 98N$$
$$g = 9.8 , m/s^2$$

Using:

$$W = mg$$
$$m = \frac{W}{g}$$
$$m = \frac{98}{9.8}$$
$$m = 10 , kg$$


10Intext Activities0 questions


11Activity – 10 questions

Using Vernier Caliper to Find the Outer Diameter of a Pen Cap

Aim:

To find the outer diameter of a pen cap.

Materials Required:

  • Vernier caliper
  • Pen cap

Result:

The outer diameter of the pen cap = 9.35 cm

Possible textbook typo noted:
A pen cap diameter is usually around 0.935 cm or 9.35 mm.


12Activity – 20 questions

Determining Thickness of a Single Sheet Using Screw Gauge

Result:

The thickness of a single sheet = 0.30 mm



13Additional Numerical Problems2 questions

Q.1Mass of Iron
✓ Answer

Given:

$$D = 6.8 , g/cm^3$$
$$V = 40 , cm^3$$

Using:

$$\text{Mass} = \text{Density} \times \text{Volume}$$
$$M = 6.8 \times 40$$
$$M = 272 , g$$

Q.2Mass of Apples
✓ Answer
Given:

40 apples = 5 kg = 5000 g


(i) Mass of 12 apples

$$\text{Mass of 1 apple} = \frac{5000}{40}$$
$$= 125g$$
$$\text{Mass of 12 apples} = 125 \times 12$$
$$= 1500g$$

(ii) Mass of one apple

$$\frac{5000}{40} = 125g$$

Answer:
Mass of one apple = 125 g


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