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Samacheer Class 9 Science - Motion

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13 Sections
24 Questions

Complete Grade 9 Science questions and answers for Motion. Click any question to expand the answer.

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📋 Sections in this chapter
I. Choose the Correct AnswerII. Fill in the BlanksIII. State Whether True or FalseIV. Assertion and Reason Type QuestionsV. Match the FollowingVI. Answer BrieflyVII. Answer in DetailVIII. Exercise ProblemsIntext ActivitiesActivity – 1Activity – 2Activity – 3Activity – 4
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1I. Choose the Correct Answer4 questions

Q.1The area under velocity-time graph represents the
✓ Answer
  • (a) velocity of the moving object
  • (b) displacement covered by the moving object
  • (c) speed of the moving object
  • (d) acceleration of the moving object

Answer:
(b) displacement covered by the moving object


Q.2Which one of the following is most likely not a case of uniform circular motion?
✓ Answer
  • (a) Motion of the Earth around the Sun
  • (b) Motion of a toy train on a circular track
  • (c) Motion of a racing car on a circular track
  • (d) Motion of the hour hand on a clock dial

Answer:
(c) Motion of a racing car on a circular track


Q.3Which of the following graph represents uniform motion of a moving particle?
✓ Answer

Answer:
(b)

Uniform motion is represented by a straight-line distance-time graph with constant slope.

Q.4The centrifugal force is
✓ Answer
  • (a) a real force
  • (b) the reaction force of centripetal force
  • (c) a virtual force
  • (d) directed towards the centre of the circular path

Answer:
(c) a virtual force



2II. Fill in the Blanks0 questions
  • Speed is a scalar quantity whereas velocity is a vector quantity.
  • The slope of the distance-time graph at any point gives speed.
  • Negative acceleration is called retardation or deceleration.
  • Area under the velocity-time graph shows displacement.


3III. State Whether True or False5 questions

If false, correct the statement.


Q.1The motion of a city bus in heavy traffic is an example of uniform motion.
✓ Answer

Answer: False

Correct Statement:
The motion of a city bus in heavy traffic is an example of non-uniform motion.


Q.2Acceleration can have a negative value.
✓ Answer

Answer: True


Q.3Distance covered by a particle never becomes zero but displacement can become zero.
✓ Answer

Answer: True


Q.4The velocity-time graph of a freely falling body is a straight line parallel to the x-axis.
✓ Answer

Answer: False

Correct Statement:
The velocity-time graph of a freely falling body is a straight line inclined to the x-axis because velocity increases uniformly with time.


Q.5If the velocity-time graph of a particle is a straight line inclined to the x-axis, then its displacement-time graph will also be a straight line.
✓ Answer

Answer: False

Correct Statement:
If the velocity-time graph is a straight inclined line, the displacement-time graph will be a curve because the body is uniformly accelerated.

Correction made:
Original answer marked as True was incorrect.


4IV. Assertion and Reason Type Questions3 questions

Choose the correct option:

  • (a) Both assertion and reason are true and reason is the correct explanation.
  • (b) Both assertion and reason are true but reason is not the correct explanation.
  • (c) Assertion is true but reason is false.
  • (d) Assertion is false but reason is true.

Q.1Question 1
✓ Answer

Assertion:
Accelerated motion may be due to a change in magnitude or direction of velocity or both.

Reason:
Acceleration can be produced only by change in magnitude of velocity.

Answer:
(c) Assertion is true but reason is false.


Q.2Question 2
✓ Answer

Assertion:
The speedometer of a car measures its average speed.

Reason:
Average velocity equals total displacement divided by total time taken.

Answer:
(d) Assertion is false but reason is true.

Correction Note:
A speedometer measures instantaneous speed, not average speed.

Q.3Question 3
✓ Answer

Assertion:
Displacement of a body may be zero when distance travelled is not zero.

Reason:
Displacement is the shortest distance between initial and final positions.

Answer:
(a) Both assertion and reason are true and reason is the correct explanation.



5V. Match the Following0 questions
List IList II
Motion covering equal distances in equal intervals of timeUniform motion
Motion with non-uniform accelerationNon-uniform motion
Constant retardationNegative acceleration
Uniform accelerationConstant acceleration
The original uploaded content was incomplete. The matching was logically completed based on standard textbook concepts.


6VI. Answer Briefly7 questions

Q.1Define velocity.
✓ Answer

Answer:

Velocity is the rate of change of displacement with respect to time.

$$\text{Velocity} = \frac{\text{Displacement}}{\text{Time}}$$
  • Velocity is a vector quantity.
  • SI unit of velocity is (m/s).

Q.2Distinguish between distance and displacement.
✓ Answer
DistanceDisplacement
Actual length of path travelledShortest distance between initial and final position
Scalar quantityVector quantity
Always positiveCan be positive, negative, or zero
Depends on pathIndependent of path

Q.3What is uniform motion?
✓ Answer

Answer:
An object is said to be in uniform motion if it covers equal distances in equal intervals of time.


Q.4Compare speed and velocity.
✓ Answer
SpeedVelocity
Rate of change of distanceRate of change of displacement
Scalar quantityVector quantity
Magnitude onlyMagnitude and direction
Always positiveCan be positive, negative, or zero
SI unit: m/sSI unit: m/s

Q.5What do you understand by negative acceleration?
✓ Answer

Answer:
When velocity decreases with time, acceleration becomes negative.

Negative acceleration is called:

  • Retardation
  • Deceleration

Q.6Is uniform circular motion accelerated? Give reason.
✓ Answer

Answer:
Yes. In uniform circular motion, speed remains constant but direction continuously changes. Since velocity changes, the motion is accelerated.


Q.7What is uniform circular motion? Give examples.
✓ Answer

Answer:
When an object moves with constant speed along a circular path, the motion is called uniform circular motion.

Examples:

  • Earth revolving around the Sun
  • Moon revolving around the Earth


7VII. Answer in Detail2 questions

Q.1Derive the Equations of Motion by Graphical Method
✓ Answer

First Equation of Motion

From velocity-time graph:

$$a = \frac{v-u}{t}$$

Rearranging,

$$v = u + at$$

This is the first equation of motion.


Second Equation of Motion

Displacement is equal to area under velocity-time graph.

$$s = ut + \frac{1}{2}at^2$$

This is the second equation of motion.


Third Equation of Motion

Using:

$$t = \frac{v-u}{a}$$

Substituting into:

$$s = \frac{1}{2}(u+v)t$$

We get:

$$v^2 = u^2 + 2as$$

This is the third equation of motion.


Q.2Explain Different Types of Motion
✓ Answer

(i) Linear Motion

Motion along a straight line.

Example:

  • Car moving on a straight road

(ii) Circular Motion

Motion along a circular path.

Example:

  • Earth revolving around the Sun

(iii) Oscillatory Motion

To-and-fro motion repeated at regular intervals.

Example:

  • Pendulum of a clock

(iv) Random Motion

Irregular and unpredictable motion.

Example:

  • Movement of fish in water


8VIII. Exercise Problems3 questions

Q.1Ball Dropped from Height
✓ Answer

Given:

$$u = 0$$
$$s = 20m$$
$$a = 10m/s^2$$

(a) Final Velocity

Using:

$$v^2 = u^2 + 2as$$
$$v^2 = 0 + 2 \times 10 \times 20$$
$$v^2 = 400$$
$$v = 20m/s$$

(b) Time Taken

Using:

$$v = u + at$$
$$20 = 0 + 10t$$
$$t = 2s$$

Answer:

  • Final velocity = (20m/s)
  • Time taken = (2s)

Q.2Athlete on Circular Track
✓ Answer

Given:

  • Diameter = 200 m
  • Radius = 100 m
  • Time for one round = 40 s
  • Total time = 2 min 20 s = 140 s

Speed

$$v = \frac{2\pi r}{40}$$
$$= \frac{2 \times 3.14 \times 100}{40}$$
$$= 15.7m/s$$

Distance Covered

$$\text{Distance} = vt$$
$$= 15.7 \times 140$$
$$= 2198m$$

Displacement

Number of rotations:

$$\frac{140}{40} = 3.5$$

After 3.5 rotations, athlete reaches opposite side of circle.

Displacement = diameter = (200m)


Q.3Racing Car Problem
✓ Answer

Given:

$$a = 4m/s^2$$
$$u = 0$$
$$t = 10s$$

Using:

$$s = ut + \frac{1}{2}at^2$$
$$s = 0 + \frac{1}{2} \times 4 \times 10^2$$
$$s = 200m$$

Answer:

Distance covered = (200m)



9Intext Activities0 questions


10Activity – 10 questions

Fixed and Movable Objects

Immovable Objects:

  • Houses
  • Trees
  • Plants

Movable Objects:

  • Birds
  • Cars
  • Buses


11Activity – 20 questions

Observation:

  • Bus in heavy traffic covers unequal distances in equal intervals of time.
  • Train in uniform motion covers equal distances in equal intervals of time.

Conclusion:

  • Bus → Non-uniform motion
  • Train → Uniform motion


12Activity – 30 questions

Observation:

  • Distance through path ABC:
$$4m + 3m = 7m$$
  • Distance AC:
$$5m$$
  • Shortest path from A to D:
$$AD = 3m$$
  • Total distance in path ABCDA:
$$14m$$


13Activity – 40 questions

Observation:

  • Stone and eraser reach ground almost together.
  • Eraser falls faster than paper.
  • Crumpled paper falls faster than plain paper.

Reason:

Air resistance depends on surface area exposed to air. Larger surface area experiences greater air resistance.


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