⚗️ Chemistry · Chapter 7 · Samacheer Kalvi Grade 10

Samacheer Class 10 Science - Atoms and Molecules

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Samacheer Kalvi Class 10 Science Chapter 7 Atoms and Molecules book back questions and answers — complete MCQ, fill in the blanks, short answer and long answer solutions. This chapter covers laws of chemical combination, Dalton's atomic theory, atomic mass, molecular mass, mole concept, Avogadro's number and empirical formula as per the Tamil Nadu Grade 10 Chemistry syllabus. Step-by-step solutions for all numerical problems.

Atoms and Molecules — key concepts & quick answers

What is the difference between an atom and a molecule?
An atom is the smallest particle of an element that takes part in a chemical reaction. A molecule is the smallest particle of an element or compound that can exist independently, made of two or more atoms.
What is the mole concept?
One mole is the amount of a substance that contains as many particles as there are atoms in exactly 12 g of carbon-12 — that is, 6.022 × 10²³ particles.
What is Avogadro's number?
Avogadro's number is 6.022 × 10²³ — the number of particles (atoms, molecules or ions) present in one mole of any substance.
What is the difference between atomic mass and molecular mass?
Atomic mass is the mass of one atom of an element (in atomic mass units). Molecular mass is the sum of the atomic masses of all the atoms in a molecule.
What is the law of conservation of mass?
In a chemical reaction, matter is neither created nor destroyed — the total mass of the reactants equals the total mass of the products.
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Multiple Choice Questions True or False Match the Following Assertion & Reasoning Short Answer Questions Numerical Problems Assertion & Reasoning Long Answer Questions Higher Order Thinking
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MCQI. Multiple Choice Questions1 mark each
Q.1 Which of the following has the smallest mass?
✓ Answer: (B) 1 atom of He
Q.2 Which of the following is a triatomic molecule?
✓ Answer: (C) Carbon dioxide
Q.3 The volume occupied by 4.4 g of CO2 at S.T.P
✓ Answer: (B) 2.24 litre
Q.4 Mass of 1 mole of Nitrogen atom is
✓ Answer: (D) 14 g
Q.5 Which of the following represents 1 amu?
✓ Answer: (C) 1/12th of the mass of a C-12 atom
Q.6 Which of the following statement is incorrect?
✓ Answer: A and C are incorrect statements
Q.7 The volume occupied by 1 mole of a diatomic gas at S.T.P is
✓ Answer: (C) 22.4 litre
Q.8 In the nucleus of 20Ca40, there are
✓ Answer: (B) 20 protons and 20 neutrons
Q.9 The gram molecular mass of oxygen molecule is
✓ Answer: (C) 32 g
Q.10 1 mole of any substance contains ____ molecules.
✓ Answer: (A) 6.023 x 10^23
Q.1 Atoms of different elements having same mass number, but different atomic numbers are called isobars.

Options not available — refer to textbook.

✓ Answer: (—)
Q.2 Atoms of different elements having same number of neutrons are called isotones.

Options not available — refer to textbook.

✓ Answer: (—)
Q.3 Atoms of one element can be transmuted into atoms of other element by artificial transmutation

Options not available — refer to textbook.

✓ Answer: (—)
Q.4 The sum of the numbers of protons and neutrons of an atom is called its mass number

Options not available — refer to textbook.

✓ Answer: (—)
Q.5 Relative atomic mass is otherwise known as standard atomic weight

Options not available — refer to textbook.

✓ Answer: (—)
Q.6 The average atomic mass of hydrogen is 1.0079 amu.

Options not available — refer to textbook.

✓ Answer: (—)
Q.7 If a molecule is made of similar kind of atoms, then it is called Homo atomic molecule.

Options not available — refer to textbook.

✓ Answer: (—)
Q.8 The number of atoms present in a molecule is called its atomicity

Options not available — refer to textbook.

✓ Answer: (—)
Q.9 One mole of any gas occupies 22400 ml at S.T.P 10 Atomicity of phosphorous is 4

Options not available — refer to textbook.

✓ Answer: (—)
MatchIII. Match the Following1 mark each
Column AColumn B
8 g of O20.25 moles
4 g of H22 moles
52 g of He13 moles
112 g of N24 moles
35.5 g of Cl20.5 moles
T/FIV. True or False1 mark each
#StatementAnswerCorrection (if False)
1Two elements sometimes can form more than one compound.True-
2Noble gases are DiatomicFalseNoble gases are monoatomic.
3The gram atomic mass of an element has no unitFalseThe gram atomic mass of an element is expressed in grams.
41 mole of Gold and Silver contain same number of atomsTrue-
5Molar mass of CO2 is 42g.FalseMolar mass of CO2 is 44 g mol^-1.
A&RV. Assertion & Reasoning2 marks each
Q.1 Assertion: Atomic mass of aluminium is 27
✓ Answer
Reason: An atom of aluminium is 27 times heavier than 1/12th of the mass of the C-12 atom.
Answer: A and R are correct, and R explains A.
Q.2 Assertion: The relative atomic mass of chlorine is 35.5 a.m.u.
✓ Answer
Reason: The natural abundance of chlorine isotopes is not equal.
Answer: A and R are correct, and R explains A. Chlorine has isotopes Cl-35 and Cl-37 in unequal natural abundance, so its average relative atomic mass is 35.5.
ShortVI. Short Answer Questions2 marks each
Q.1 Define: Relative atomic mass.
✓ Answer

The relative atomic mass of an element is a dimensionless quantity that represents the average mass of atoms of that element compared to a standard reference. Specifically, it is defined as the ratio of the average mass of one atom of the element to one-twelfth (1/12) of the mass of an atom of the carbon-12 isotope. Carbon-12 is used as the standard because it is abundant and stable. This definition allows for a consistent and comparable scale for the masses of different elements, facilitating stoichiometric calculations and understanding chemical composition. It is important to note that relative atomic mass is a ratio and therefore has no units.

Q.2 Write the different types of isotopes of oxygen and its percentage abundance.
✓ Answer

Oxygen, a vital element for life, exists in nature as a mixture of three stable isotopes. These isotopes have the same number of protons but differ in their number of neutrons, leading to slightly different atomic masses. The most abundant isotope is Oxygen-16 (¹⁶O), which has a mass of approximately 15.9949 atomic mass units (amu) and constitutes about 99.757% of naturally occurring oxygen. The second isotope is Oxygen-17 (¹⁷O), with a mass of approximately 16.9991 amu, and it is present in a very small abundance of about 0.038%. The third stable isotope is Oxygen-18 (¹⁸O), having a mass of approximately 17.9992 amu, and it accounts for about 0.205% of natural oxygen. These isotopic abundances are crucial for various scientific applications, including dating and tracer studies.

Q.3 Define: Atomicity
✓ Answer

Atomicity refers to the number of atoms that are chemically bonded together to form a single molecule of a particular element or compound. For instance, in the case of elements, if a molecule consists of only one atom, it is monatomic (like Helium, He). If it consists of two atoms, it is diatomic (like Oxygen, O₂). Molecules made of three atoms are triatomic (like Ozone, O₃), and so on. For compounds, atomicity is the total count of all atoms of different elements present in one molecule. For example, a molecule of water (H₂O) has an atomicity of three (two hydrogen atoms and one oxygen atom).

Q.4 Give any two examples for heterodiatomic molecules.
✓ Answer

Heterodiatomic molecules are molecules composed of two atoms of different elements chemically bonded together. These molecules are diatomic because they contain exactly two atoms. Examples of such molecules include hydrogen chloride (HCl), where one hydrogen atom is bonded to one chlorine atom, and carbon monoxide (CO), where one carbon atom is bonded to one oxygen atom. In both cases, the molecule consists of two distinct types of atoms, making them heterodiatomic. Other examples include nitric oxide (NO) and hydrogen bromide (HBr).

Q.5 What is Molar volume of a gas?
✓ Answer

The molar volume of a gas is a fundamental concept in chemistry that defines the space occupied by a specific amount of gas under standard conditions. It is defined as the volume that one mole of any gas occupies at Standard Temperature and Pressure (STP). At STP, which is typically defined as a temperature of 0°C (273.15 K) and a pressure of 1 atmosphere (atm), one mole of any ideal gas occupies a volume of 22.4 liters (L) or 22,400 milliliters (mL). This principle, known as Avogadro's Law, is extremely useful for calculations involving gases, allowing chemists to relate the amount of a gas (in moles) to its volume without needing to know its specific identity.

Q.6 Find the percentage of nitrogen in ammonia.
✓ Answer
Molar mass of NH3 = 14 + 3(1) = 17 g mol^-1.
Percentage of nitrogen = (14/17) x 100 = 82.35%.
NumericalVII. Numerical Problems3 marks each
Q.1 Calculate the number of water molecule present in one drop of water which weighs 0.18 g.
✓ Answer
Mass of water = 0.18 g. Molar mass of H2O = 18 g mol^-1.
Number of moles = 0.18/18 = 0.01 mol.
Number of molecules = 0.01 x 6.023 x 10^23 = 6.023 x 10^21 molecules.
Q.2 N2 + 3 H2 \rightarrow 2 NH3
✓ Answer
N2 + 3H2 -> 2NH3.
1 mole of nitrogen gas = 28 g; 3 moles of hydrogen gas = 3 x 2 = 6 g; 2 moles of ammonia = 2 x 17 = 34 g.
So, 28 g of N2 reacts with 6 g of H2 to form 34 g of NH3.
Q.3 Calculate the number of moles in $i) 27g of Al ii) 1.51 \times 1023 molecules of NH4Cl$
✓ Answer
(i) For 27 g of Al, number of moles = mass/atomic mass = 27/27 = 1 mole.
(ii) For 1.51 x 10^23 molecules of NH4Cl, number of moles = number of molecules/Avogadro number = (1.51 x 10^23)/(6.023 x 10^23) = 0.25 mole approximately.
Q.4 Give the salient features of “Modern atomic theory”.
✓ Answer
The salient features of modern atomic theory are:
(i) Atom is divisible into subatomic particles such as electrons, protons and neutrons.
(ii) Atoms of the same element may have different atomic masses; these are isotopes, such as Cl-35 and Cl-37.
(iii) Atoms of different elements may have the same mass number; these are isobars, such as Ar-40 and Ca-40.
(iv) Atoms of one element can be transmuted into atoms of another element by nuclear reactions.
(v) Atom is the smallest particle that takes part in a chemical reaction.
(vi) Mass can be converted into energy in nuclear reactions, E = mc^2.
Q.5 Derive the relationship between Relative molecular mass and Vapour density.
✓ Answer
Vapour density is the ratio of the mass of a certain volume of a gas or vapour to the mass of an equal volume of hydrogen under the same conditions.
By Avogadro's law, equal volumes contain equal number of molecules. Since hydrogen is diatomic, the mass of one molecule of hydrogen is twice the mass of one hydrogen atom.
Therefore, vapour density = molecular mass/2.
Hence, relative molecular mass = 2 x vapour density.
HOTIX. Higher Order Thinking3 marks each
Q.1 Calcium carbonate is decomposed on heat-ing in the following reaction
✓ Answer
CaCO3 -> CaO + CO2.
(i) Number of moles of CaCO3 involved = 1 mole.
(ii) Gram molecular mass of CaCO3 = 40 + 12 + (16 x 3) = 100 g mol^-1.
(iii) Number of moles of CO2 formed = 1 mole.
NumericalVII. Numerical Problems3 marks each
Q.1 How many grams are there in the following?
✓ Answer
(i) 2 moles of H2: molar mass = 2 g mol^-1, mass = 2 x 2 = 4 g.
(ii) 3 moles of Cl2: molar mass = 70.9 g mol^-1, mass = 3 x 70.9 = 212.7 g.
(iii) 5 moles of S8: molar mass = 32 x 8 = 256 g mol^-1, mass = 5 x 256 = 1280 g.
(iv) 4 moles of P4: molar mass = 31 x 4 = 124 g mol^-1, mass = 4 x 124 = 496 g.
Q.2 Calculate the % of each element in calci-um carbonate. (Atomic mass: C-12, O-16, Ca -40)
✓ Answer
Molar mass of CaCO3 = 40 + 12 + (3 x 16) = 100 g mol^-1.
Percentage of Ca = (40/100) x 100 = 40%.
Percentage of C = (12/100) x 100 = 12%.
Percentage of O = (48/100) x 100 = 48%.
Q.3 Calculate the % of oxygen in Al2(SO4)3. (Atomic mass: Al-12, O-16, S -32)
✓ Answer
Molar mass of Al2(SO4)3 = (27 x 2) + (32 x 3) + (16 x 12) = 342 g mol^-1.
Mass of oxygen = 16 x 12 = 192 g.
Percentage of oxygen = (192/342) x 100 = 56.14%.
Q.4 Calculate the % relative abundance of B -10 and B -11, if its average atomic mass is 10.804 amu.
✓ Answer
Let the percentage abundance of B-10 be x and B-11 be 100 - x.
Average atomic mass = [10.01294x + 11.009305(100 - x)]/100 = 10.804.
Solving, x = 20.636%. Therefore B-10 = 20.636% and B-11 = 79.364%.
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