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Samacheer Class 9 Science - Measurement

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Textbook Exercises
13 Sections
33 Questions

Complete Grade 9 Science questions and answers for Measurement. Click any question to expand the answer.

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📋 Sections in this chapter
I. Choose the Correct AnswerII. Fill in the BlanksIII. State Whether True or FalseIV. Match the FollowingV. Assertion and Reason Type QuestionsVI. Answer Very BrieflyVII. Answer BrieflyVIII. Answer in DetailIX. Numerical ProblemsIntext ActivitiesActivity – 1Activity – 2Additional Numerical Problems
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1I. Choose the Correct Answer4 questions
Q.1Choose the correct one.
✓ Answer
  • (a) mm < cm < m < km
  • (b) mm > cm > m > km
  • (c) km < m < cm < mm
  • (d) mm > m > cm > km

Answer:
(a) mm < cm < m < km


Q.2Rulers, measuring tapes and metre scales are used to measure
✓ Answer
  • (a) mass
  • (b) weight
  • (c) time
  • (d) length

Answer:
(d) length


Q.31 metric ton is equal to
✓ Answer
  • (a) 100 quintals
  • (b) 10 quintals
  • (c) 1/10 quintals
  • (d) 1/100 quintals

Answer:
(b) 10 quintals


Q.4Which among the following is not a device to measure mass?
✓ Answer
  • (a) Spring balance
  • (b) Beam balance
  • (c) Physical balance
  • (d) Digital balance

Answer:
(a) Spring balance



2II. Fill in the Blanks0 questions
  • Metre is the unit of length.
  • 1 kg of rice is weighed by beam balance.
  • Thickness of a cricket ball is measured by vernier caliper.
  • Radius of a thin wire is measured by screw gauge.
  • A physical balance measures small differences in mass up to 1 mg or less.


3III. State Whether True or False6 questions

If false, correct the statement.


Q.1The SI unit of electric current is kilogram.
✓ Answer

Answer: False. The statement is incorrect. The SI unit of electric current is ampere (A), not kilogram. Kilogram is the SI unit of mass. Electric current measures the flow of electric charge through a conductor, and it is measured in amperes using an ammeter. This is one of the seven fundamental SI units in the International System of Units.

Q.2Kilometre is one of the SI units of measurement.
✓ Answer

Answer: True. Kilometre is indeed one of the SI units of measurement for length and distance. It is derived from the metre, which is the fundamental SI unit of length. One kilometre equals 1000 metres. The kilometre is widely used in everyday life and in scientific measurements, particularly for measuring large distances such as the distance between cities or geographical features.

Q.3In everyday life, we use the term weight instead of mass.
✓ Answer

Answer: True. In everyday life, we commonly use the term weight instead of mass, even though they are scientifically different. Weight is the force exerted by gravity on an object and varies with location, while mass is the amount of matter in an object and remains constant. However, in casual conversation, people often use weight and mass interchangeably when referring to how heavy something is, which is why this statement is true in the context of everyday usage.

Q.4A physical balance is more sensitive than a beam balance.
✓ Answer

Answer: True. A physical balance is more sensitive than a beam balance. A physical balance can detect smaller differences in mass and provides greater precision in measurements. This is because a physical balance has a more delicate construction and can measure mass to a higher degree of accuracy compared to a beam balance, which is a simpler instrument. The physical balance is therefore preferred in laboratories when precise measurements are required.

Q.5One Celsius degree is an interval of 1 K and zero degree Celsius is 273.15 K.
✓ Answer

Answer: True. One Celsius degree is an interval of 1 K (kelvin), meaning that a temperature change of one degree on the Celsius scale is equivalent to a change of one kelvin on the absolute temperature scale. Additionally, zero degree Celsius is equal to 273.15 K. This relationship shows that the Celsius and Kelvin scales have the same interval size, but differ in their reference points. The Kelvin scale is the absolute temperature scale used in the SI system.

Q.6With the help of vernier caliper we can have an accuracy of 0.1 mm and with screw gauge we can have an accuracy of 0.01 mm.
✓ Answer

Answer: True. With the help of a vernier caliper, we can achieve an accuracy of 0.1 mm, while with a screw gauge we can achieve an accuracy of 0.01 mm. This means that a screw gauge is ten times more precise than a vernier caliper. The screw gauge is used for measuring very small lengths and diameters with high precision, whereas the vernier caliper is used for measuring lengths, diameters, and depths with moderate precision. Both instruments are essential measuring tools in physics laboratories.


4IV. Match the Following2 questions
Q.1Question 1
✓ Answer
QuantityUnit
Lengthmetre
Masskilogram
Timesecond
Temperaturekelvin

Q.2Question 2
✓ Answer
InstrumentUsed For
Screw gaugeCoins
Vernier caliperCricket ball
Beam balanceVegetables
Digital balanceGold ornaments


5V. Assertion and Reason Type Questions3 questions

Choose the correct answer:

  • (a) Both A and R are true but R is not the correct reason.
  • (b) Both A and R are true and R is the correct reason.
  • (c) A is true but R is false.
  • (d) A is false but R is true.

Q.1Question 1
✓ Answer

Assertion (A):
The scientifically correct expression is “The mass of the bag is 10 kg”.

Reason (R):
In everyday life, we use the term weight instead of mass.

Answer:
(a) Both A and R are true but R is not the correct reason.


Q.2Question 2
✓ Answer

Assertion (A):
0°C = 273.15 K. For convenience, it is rounded off to 273 K.

Reason (R):
To convert Celsius temperature into Kelvin, we add 273 to the given temperature.

Answer:
(b) Both A and R are true and R is the correct reason.


Q.3Question 3
✓ Answer

Answer: (b) Both A and R are true and R is the correct reason. The assertion that distance between two celestial bodies is measured in terms of light year is true. The reason that the distance travelled by light in one year is one light year is also true and correctly explains why light years are used for astronomical measurements. A light year is a unit of distance, not time, and represents the vast distances between stars and galaxies. Since ordinary units like metres or kilometres are impractically large for cosmic distances, astronomers use light years to express these enormous distances in more manageable numbers.


6VI. Answer Very Briefly6 questions

Q.1Define measurement.
✓ Answer

Answer: Measurement is the process of comparing a given physical quantity with a known standard quantity of the same nature. In other words, measurement involves determining how many times a standard unit is contained in the physical quantity being measured. For example, when we measure the length of a table, we compare it with a standard unit of length such as a metre. Measurement is fundamental to science and allows us to quantify physical properties in a way that can be communicated and verified by others.

Q.2Define standard unit.
✓ Answer

Answer: A standard unit is a fixed quantity of constant magnitude that is used as a reference to measure other quantities of the same nature. Standard units are internationally agreed upon and remain unchanged, ensuring consistency and uniformity in measurements across different regions and countries. For example, the metre is the standard unit of length, the kilogram is the standard unit of mass, and the second is the standard unit of time. These standard units form the basis of the SI system and allow scientists and people worldwide to communicate measurements accurately.

Q.3What is the full form of SI system?
✓ Answer

Answer: The full form of SI system is International System of Units. This is the modern metric system of measurement that is used worldwide in science, technology, and commerce. The SI system was established to provide a uniform and standardized set of units for all physical quantities. It consists of seven fundamental units: metre for length, kilogram for mass, second for time, ampere for electric current, kelvin for temperature, mole for amount of substance, and candela for luminous intensity.

Q.4Define least count of any device.
✓ Answer

Answer:
The least count of an instrument is the smallest measurement that can be measured accurately using that instrument.

Formulae:

For Vernier Caliper:

$$\text{Least Count} = \frac{\text{Value of one main scale division}}{\text{Total number of vernier scale divisions}}$$

For Screw Gauge:

$$\text{Least Count} = \frac{\text{Pitch}}{\text{Number of head scale divisions}}$$

Q.5What do you know about pitch of screw gauge?
✓ Answer

Answer:
Pitch of a screw gauge is the distance moved by the screw in one complete rotation.

$$\text{Pitch} = \frac{\text{Distance travelled on pitch scale}}{\text{Number of rotations}}$$

Q.6Can you find the diameter of a thin wire using a ruler?
✓ Answer

Answer:
No. A ruler is not accurate enough to measure the diameter of a thin wire. A screw gauge is used instead.



7VII. Answer Briefly4 questions

Q.1Write the rules followed while writing SI unit symbols.
✓ Answer

Answer:

  • Units named after scientists are written in lowercase letters.

Example: joule, kelvin, newton

  • Symbols are generally written in lowercase.

Example: m, kg, s

  • Symbols derived from scientists’ names are written in capital letters.

Example: N, J, C

  • Symbols are not followed by a full stop.

Example: 75 cm

  • Symbols are never written in plural form.

Example: 100 kg (not 100 kgs)


Q.2Write the need for a standard unit.
✓ Answer

Answer: Standard units are needed to maintain uniformity and accuracy in measurements throughout the world. Without standard units, different regions and countries would use different units for the same physical quantity, making it impossible to compare measurements or communicate scientific findings accurately. Standard units ensure that a measurement made in one part of the world can be understood and verified in another part. They also allow scientists to conduct experiments and share results with confidence, knowing that everyone is using the same reference standards. This universal agreement on standard units is essential for scientific progress and international cooperation.

Q.3Differentiate mass and weight.
✓ Answer
MassWeight
Fundamental quantityDerived quantity
Scalar quantityVector quantity
Amount of matter in a bodyGravitational force acting on a body
Constant everywhereVaries from place to place
Measured using physical balanceMeasured using spring balance
SI unit: kilogram (kg)SI unit: newton (N)

Q.4How will you measure the least count of vernier caliper?
✓ Answer

Answer:

$$\text{Least Count} = \frac{\text{Value of one main scale division}}{\text{Number of vernier scale divisions}}$$

It is the minimum value measured accurately using a vernier caliper.



8VIII. Answer in Detail2 questions

Q.1Explain a method to find the thickness of a hollow tea cup.
✓ Answer

Answer:

Procedure:
  • Determine the pitch and least count of the screw gauge.
  • Place the tea cup between the studs.
  • Rotate the ratchet until the cup is held gently.
  • Note the pitch scale reading (PSR).
  • Note the head scale coincidence (HSC).
  • Calculate thickness using:
$$\text{Thickness} = \text{PSR} + (\text{HSC} \times \text{LC})$$
  • Repeat readings at different positions and calculate the average.

Q.2How will you find the thickness of a one rupee coin?
✓ Answer

Answer:

Procedure:
  • Determine the pitch and least count of the screw gauge.
  • Place the coin between the studs.
  • Rotate the ratchet gently.
  • Note PSR and HSC.
  • Calculate thickness using:
$$\text{Thickness} = \text{PSR} + (\text{HSC} \times \text{LC})$$
  • Repeat readings and calculate the average value.


9IX. Numerical Problems4 questions

Q.1Light Year Problem
✓ Answer

Question:
Inian says one light year is (9.46 \times 10^{15}) m.
Ezhilan says it is (9.46 \times 10^{12}) km.
Who is correct?

Solution:

Both are correct because:

$$1 \text{ km} = 10^3 \text{ m}$$
$$9.46 \times 10^{15} \text{ m} = 9.46 \times 10^{12} \text{ km}$$

Q.2Radius of a Rubber Ball
✓ Answer

Given:

  • MSR = 7 cm
  • VC = 6
  • LC = 0.01 cm
Diameter:
$$D = \text{MSR} + (\text{VC} \times \text{LC})$$
$$D = 7 + (6 \times 0.01)$$
$$D = 7.06 \text{ cm}$$
Radius:
$$R = \frac{D}{2}$$
$$R = \frac{7.06}{2}$$
$$R = 3.53 \text{ cm}$$
Correction made:
Original answer incorrectly converted units to metres.

Q.3Thickness of a Five Rupee Coin
✓ Answer

Given:

  • PSR = 1 mm
  • HSC = 68
  • LC = 0.01 mm
Calculation:
$$\text{Thickness} = \text{PSR} + (\text{HSC} \times \text{LC})$$
$$= 1 + (68 \times 0.01)$$
$$= 1 + 0.68$$
$$= 1.68 \text{ mm}$$

Q.4Find the Mass of an Object Weighing 98 N
✓ Answer

Given:

$$W = 98N$$
$$g = 9.8 , m/s^2$$

Using:

$$W = mg$$
$$m = \frac{W}{g}$$
$$m = \frac{98}{9.8}$$
$$m = 10 , kg$$


10Intext Activities0 questions


11Activity – 10 questions

Using Vernier Caliper to Find the Outer Diameter of a Pen Cap

Aim:

To find the outer diameter of a pen cap.

Materials Required:

  • Vernier caliper
  • Pen cap

Result:

The outer diameter of the pen cap = 9.35 cm

Possible textbook typo noted:
A pen cap diameter is usually around 0.935 cm or 9.35 mm.


12Activity – 20 questions

Determining Thickness of a Single Sheet Using Screw Gauge

Result:

The thickness of a single sheet = 0.30 mm



13Additional Numerical Problems2 questions

Q.1Mass of Iron
✓ Answer

Given:

$$D = 6.8 , g/cm^3$$
$$V = 40 , cm^3$$

Using:

$$\text{Mass} = \text{Density} \times \text{Volume}$$
$$M = 6.8 \times 40$$
$$M = 272 , g$$

Q.2Mass of Apples
✓ Answer
Given:

40 apples = 5 kg = 5000 g


(i) Mass of 12 apples

$$\text{Mass of 1 apple} = \frac{5000}{40}$$
$$= 125g$$
$$\text{Mass of 12 apples} = 125 \times 12$$
$$= 1500g$$

(ii) Mass of one apple

$$\frac{5000}{40} = 125g$$

Answer:
Mass of one apple = 125 g


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