Answer: (b) (40 Ar, 18) and (14 N, 7).
Explanation: Other pairs are isotones (same number of neutrons). The pair in (b) do not share the same neutron count, so they are the odd pair.
- (a) ion
- (b) isotope
- (c) isobar
- (d) another element
Answer:
(b) isotope
- (a) protons and electrons
- (b) only neutrons
- (c) electrons and neutrons
- (d) protons and neutrons
Answer:
(d) protons and neutrons
- (a) 80, 80, 35
- (b) 35, 55, 80
- (c) 35, 35, 80
- (d) 35, 45, 35
Answer:
(d) 35, 45, 35
- (a) 2, 8, 9
- (b) 2, 8, 1
- (c) 2, 8, 8, 1
- (d) 2, 8, 8, 3
Answer:
(c) 2, 8, 8, 1
If false, correct the statement.
This statement is true according to Bohr's model of the atom. Electrons revolve around the nucleus in fixed, discrete orbits or energy levels. Each orbit corresponds to a specific energy level, and electrons can only occupy these fixed orbits and not exist between them. The electrons in these orbits experience the attractive force of the positively charged nucleus, which provides the centripetal force needed to keep them in circular motion. The innermost orbit, closest to the nucleus, has the lowest energy, while orbits farther from the nucleus have progressively higher energy levels.
This statement is false. Isotopes are atoms of the same element that have the same atomic number but different mass numbers. Since atomic number is determined by the number of protons in the nucleus, isotopes must have the same number of protons and therefore the same atomic number. The difference between isotopes lies in the number of neutrons they possess, which causes them to have different mass numbers. For example, carbon-12 and carbon-14 are isotopes of carbon; both have atomic number 6, but they have different numbers of neutrons and thus different mass numbers.
This statement is false. While electrons do have negligible mass compared to protons and neutrons, they do possess a definite negative electric charge. The mass of an electron is approximately 1/1836 times the mass of a proton, which is why it is considered negligible in most calculations of atomic mass. However, the negative charge of the electron is a fundamental property and is not negligible; it is equal in magnitude but opposite in sign to the charge of a proton. This charge is essential for the chemical behavior of atoms and the formation of chemical bonds.
This statement is true. According to Bohr's model of the atom, electrons in smaller orbits closer to the nucleus have lower energy levels compared to electrons in larger orbits farther from the nucleus. The energy of an electron is inversely related to the size of its orbit. Electrons in the first orbit (n=1) have the lowest energy, those in the second orbit (n=2) have higher energy, and so on. This is why electrons naturally occupy the lowest available energy levels, filling inner orbits before moving to outer orbits.
Answer: False
Correct Statement:
Using formula:
For L-shell:
Maximum electrons = 8
Answer: isobars
Answer: 2n^2
Answer: Uranium-235
Answer: 4
Answer: zero
| Scientist | Contribution |
|---|---|
| Dalton | First atomic theory |
| Chadwick | Discovery of neutron |
| Rutherford | Discovery of nucleus |
| Niels Bohr | Hydrogen atom model |
| Particle | Symbol | Charge | Relative Mass |
|---|---|---|---|
| Electron | (e^-) | (-1) | Negligible |
| Proton | (p^+) | (+1) | 1 amu |
| Neutron | (n^0) | 0 | 1 amu |
Answer:
Beryllium
Atomic number = 4
Electronic configuration:
Potassium (K)
Atomic number = 19
Chlorine (Cl)
Atomic number = 17
(,^{1}_{1}H)
Hydrogen atom
- Atomic number = 1
- Mass number = 1
(,^{1}_{0}n)
Neutron
- Charge = 0
- Mass = 1 amu
(,^{0}_{-1}e)
Electron
- Charge = (-1)
- Negligible mass
Using:
- K = 2
- L = 8
- M = 18
Total:
Answer:
28 electrons
(a) Lithium, Sodium, Potassium
All have:
(b) Beryllium, Magnesium, Calcium
All have:
Answer:
Rutherford bombarded thin gold foil with alpha particles.
Observations:
- Most particles passed through foil.
- Few deflected.
- Very few bounced back.
Conclusion:
Most of atom is empty space.
Answer:
Both isotopes have:
- same atomic number
- same electronic configuration
Hence chemical properties are same.
They differ in number of neutrons.
Oxygen
Atomic number = 8
Electronic configuration:
Sulphur
Atomic number = 16
Electronic configuration:
(i) Atomic Number = 3, Mass Number = 7
Protons:
Electrons:
Neutrons:
(ii) Atomic Number = 92, Mass Number = 238
Protons:
Electrons:
Neutrons:
Answer:
Particles present inside nucleus are called nucleons.
They include:
- protons
- neutrons
Nucleons in Phosphorus
Mass number of phosphorus:
Hence phosphorus has:
Conclusions
- Atom contains very small nucleus.
- Most of atom is empty space.
- Entire positive charge concentrated in nucleus.
- Most mass concentrated in nucleus.
- Electrons revolve around nucleus.
Main Postulates
(i)
Electrons revolve around the nucleus only in certain allowed circular orbits called stationary orbits.
(ii)
Electrons do not emit radiation or lose energy while moving in a stationary orbit.
(iii)
The angular momentum of an electron in an allowed orbit is quantised.
(iv)
Electrons absorb or emit energy only when they jump between allowed orbits.
(v)
Shells are represented as:
or
Energy Levels
- K-shell has least energy
- Energy increases outward
Statement
Volumes of reacting gases bear simple whole-number ratio under same temperature and pressure.
Example: Formation of Water
Step 1:
Word equation:
Hydrogen + Oxygen → Water
Step 2:
Chemical equation:
Volume Ratio
Thus gases combine in simple whole-number ratio.
Symbolic Representation
| Element | Symbolic Form |
|---|---|
| Carbon | (,^{12}_{6}C) |
| Oxygen | (,^{16}_{8}O) |
| Silicon | (,^{28}_{14}Si) |
| Beryllium | (,^{9}_{4}Be) |
Valency
| Element | Valency |
|---|---|
| Phosphorus | 3 or 5 |
| Chlorine | 1 |
| Silicon | 4 |
| Argon | 0 |
Isotopes of Oxygen
Oxygen-16
- Protons = 8
- Neutrons = 8
Oxygen-18
- Protons = 8
- Neutrons = 10
Isotones
(i) Fluorine and Neon
(ii) Sodium and Magnesium
(iii) Aluminium and Silicon
All pairs contain equal neutrons.
Gay-Lussac Law Using Ammonia
Volume ratio:
# Test Yourself
# Number of Neutrons
(a) (,^{27}_{13}Al)
(b) (,^{31}_{15}P)
Correction made:
Original notation incorrectly showed 34 instead of 31.
(c) (,^{190}_{76}Os)
(d) (,^{54}_{24}Cr)
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